Question Number 48541 by behi83417@gmail.com last updated on 25/Nov/18 Commented by math1967 last updated on 25/Nov/18 $${Is}\:{it}\:\left({x}−{y}\right)\left({y}−{z}\right)\left({z}−{x}\right)\left\{\left({x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} \right)\left({x}+{y}+{z}\right)+{xyz}\right\} \\ $$ Commented by math1967…
Question Number 48540 by behi83417@gmail.com last updated on 25/Nov/18 Answered by ajfour last updated on 25/Nov/18 $$\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} \:+\mathrm{2}\left({xy}+{yz}+{zx}\right)=\mathrm{0} \\ $$$$\Rightarrow\:{xy}+{yz}+{zx}\:=\:−\frac{{ab}}{\mathrm{2}} \\ $$$$\left({x}+{y}+{z}\right)^{\mathrm{3}} \:=\:{x}^{\mathrm{3}}…
Question Number 114037 by mohammad17 last updated on 16/Sep/20 $$\underset{\mathrm{0}} {\int}^{\:\frac{\pi}{\mathrm{4}}} \frac{{tan}\mathrm{2}{x}}{{sin}\mathrm{2}{x}+{cos}\mathrm{2}{x}}{dx} \\ $$ Answered by Dwaipayan Shikari last updated on 16/Sep/20 $$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \frac{{sin}\mathrm{2}{x}}{{cos}\mathrm{2}{x}\left({sin}\mathrm{2}{x}+{cos}\mathrm{2}{x}\right)}{dx}…
Question Number 179565 by Huy last updated on 30/Oct/22 $${Find}\:{x}: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:{tanx}=\frac{{x}^{\mathrm{2}} +\mathrm{1}}{\mathrm{2}{x}} \\ $$ Commented by mr W last updated on 31/Oct/22 $${you}\:{can}'{t}\:{solve}\:{exactly}.\:{there}\:{are}\: \\…
Question Number 48474 by mondodotto@gmail.com last updated on 24/Nov/18 $$\boldsymbol{\mathrm{evaluate}}\:\int_{\mathrm{0}} ^{\pi} \boldsymbol{\mathrm{sin}}^{\mathrm{2}} \boldsymbol{{x}\mathrm{d}{x}} \\ $$ Answered by hassentimol last updated on 24/Nov/18 Commented by hassentimol…
Question Number 113989 by OnyikeHenry last updated on 16/Sep/20 Answered by mr W last updated on 16/Sep/20 Commented by mr W last updated on 16/Sep/20…
Question Number 113983 by mohammad17 last updated on 16/Sep/20 $${if}\:{Z}_{\mathrm{1}} =\mathrm{1}−{i}\:{and}\:{Z}_{\mathrm{2}} ={i}^{\mathrm{4}} \:{by}\:{using}\:{demover}\:{find}\:\frac{{Z}_{\mathrm{1}} }{{Z}_{\mathrm{2}} }\:? \\ $$ Answered by Dwaipayan Shikari last updated on 16/Sep/20…
Question Number 48435 by ggny last updated on 23/Nov/18 $$\frac{\mathrm{2}}{\mathrm{11}}×−\frac{\mathrm{5}}{\mathrm{18}}{y}−\mathrm{1}\frac{\mathrm{13}}{\mathrm{22}}×+\frac{\mathrm{5}}{\mathrm{6}}{y}\:\:\:\: \\ $$$${sir}\:{could}\:{you}\:{help}\:{me}? \\ $$ Answered by $@ty@m last updated on 24/Nov/18 Terms of Service Privacy…
Question Number 48433 by ggny last updated on 23/Nov/18 $$\frac{\mathrm{7}}{\mathrm{9}}/\mathrm{3}.\mathrm{1}=×/\mathrm{9}.\mathrm{3}\:\:\:\:{sir}\:{plz}\:{help}\:{me} \\ $$$$ \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 23/Nov/18 $$\frac{\mathrm{7}}{\mathrm{9}×\mathrm{3}.\mathrm{1}}=\frac{{x}}{\mathrm{9}.\mathrm{3}} \\ $$$${x}×\mathrm{9}×\mathrm{3}.\mathrm{1}=\mathrm{9}.\mathrm{3}×\mathrm{7} \\…
Question Number 48434 by behi83417@gmail.com last updated on 23/Nov/18 Answered by tanmay.chaudhury50@gmail.com last updated on 23/Nov/18 $${tanx}={t} \\ $$$${t}\left(\mathrm{2}+\sqrt{\mathrm{3}}\:×\frac{\mathrm{3}{t}−{t}^{\mathrm{3}} }{\mathrm{1}−\mathrm{3}{t}^{\mathrm{2}} }\right)=\frac{\mathrm{3}{t}−{t}^{\mathrm{3}} }{\mathrm{1}−\mathrm{3}{t}^{\mathrm{2}} } \\ $$$$\mathrm{2}+\sqrt{\mathrm{3}}\:×\frac{\mathrm{3}{t}−{t}^{\mathrm{3}}…