Menu Close

Category: None

Question-48283

Question Number 48283 by naka3546 last updated on 21/Nov/18 Commented by maxmathsup by imad last updated on 22/Nov/18 $${let}\:{S}_{{n}} =\sum_{{k}=\mathrm{1}} ^{{n}} \:\frac{\left(−\mathrm{1}\right)^{{k}+\mathrm{1}} }{\mathrm{2}{k}−\mathrm{1}}\:\:{changement}\:{of}\:{indice}\:{k}−\mathrm{1}={j}\:{give} \\ $$$${S}_{{n}}…

lim-x-0-xlnx-

Question Number 113812 by Khalmohmmad last updated on 15/Sep/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}xlnx}=? \\ $$ Answered by bemath last updated on 15/Sep/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{ln}\:{x}}{\frac{\mathrm{1}}{{x}}}\:=\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\frac{\mathrm{1}}{{x}}}{−\frac{\mathrm{1}}{{x}^{\mathrm{2}} }}\:=\:\mathrm{0} \\…

find-the-greatest-coeeficient-in-the-expansion-6-4x-3-

Question Number 113796 by aurpeyz last updated on 15/Sep/20 $$\mathrm{find}\:\mathrm{the}\:\mathrm{greatest}\:\mathrm{coeeficient}\:\mathrm{in}\:\mathrm{the}\:\mathrm{expansion}\: \\ $$$$\left(\mathrm{6}−\mathrm{4x}\right)^{−\mathrm{3}} \\ $$ Answered by mr W last updated on 15/Sep/20 $$\left(\mathrm{6}−\mathrm{4}{x}\right)^{−\mathrm{3}} =\mathrm{6}^{−\mathrm{3}} \left(\mathrm{1}−\frac{\mathrm{2}}{\mathrm{3}}{x}\right)^{−\mathrm{3}}…

find-the-largest-coeeficient-in-3x-2-3-

Question Number 113794 by aurpeyz last updated on 15/Sep/20 $$\mathrm{find}\:\mathrm{the}\:\mathrm{largest}\:\mathrm{coeeficient}\:\mathrm{in}\:\left(\mathrm{3x}−\mathrm{2}\right)^{\mathrm{3}} \\ $$ Answered by mr W last updated on 15/Sep/20 $$\left(\mathrm{3}{x}−\mathrm{2}\right)^{\mathrm{3}} =\left(\mathrm{3}{x}\right)^{\mathrm{3}} +\mathrm{3}\left(\mathrm{3}{x}\right)^{\mathrm{2}} \left(−\mathrm{2}\right)+\mathrm{3}\left(\mathrm{3}{x}\right)\left(−\mathrm{2}\right)^{\mathrm{2}} +\left(−\mathrm{2}\right)^{\mathrm{3}}…

n-1-3-n-n-3-

Question Number 113789 by Khalmohmmad last updated on 15/Sep/20 $$\underset{\mathrm{n}=\mathrm{1}} {\overset{\propto} {\sum}}\frac{\mathrm{3}}{\mathrm{n}\left(\mathrm{n}+\mathrm{3}\right)}=? \\ $$ Answered by aleks041103 last updated on 15/Sep/20 $$\frac{\mathrm{3}}{{n}\left({n}+\mathrm{3}\right)}=\frac{\left({n}+\mathrm{3}\right)−{n}}{{n}\left({n}+\mathrm{3}\right)}=\frac{\mathrm{1}}{{n}}−\frac{\mathrm{1}}{{n}+\mathrm{3}} \\ $$$$\underset{{n}=\mathrm{1}} {\overset{\infty}…

Question-113771

Question Number 113771 by mohammad17 last updated on 15/Sep/20 Answered by Dwaipayan Shikari last updated on 15/Sep/20 $$\left({x}^{\mathrm{2}} +{y}^{\mathrm{2}} \right)−\mathrm{2}{xy}\frac{{dy}}{{dx}}=\mathrm{0} \\ $$$$\mathrm{2}{vx}^{\mathrm{2}} \frac{{dy}}{{dx}}=\left({x}^{\mathrm{2}} +{v}^{\mathrm{2}} {x}^{\mathrm{2}}…