Question Number 179137 by yaslm last updated on 25/Oct/22 Answered by MJS_new last updated on 26/Oct/22 $$\int\frac{\mathrm{sin}\:\mathrm{3}{x}}{\:\sqrt{\mathrm{1}−\mathrm{sin}\:{x}\:\mathrm{cos}\:{x}}}{dx}= \\ $$$$\:\:\:\:\:\left[{t}=\mathrm{tan}\:{x}\:\rightarrow\:{dx}=\frac{{dt}}{{t}^{\mathrm{2}} +\mathrm{1}}\right] \\ $$$$=−\int\frac{{t}\left({t}^{\mathrm{2}} −\mathrm{3}\right)}{\left({t}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{2}} \sqrt{{t}^{\mathrm{2}}…
Question Number 113589 by mathdave last updated on 14/Sep/20 $${prove}\:{the}\:{following}\:{integral} \\ $$$$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \frac{{x}^{\mathrm{2}} }{\mathrm{sin}{x}}{dx}=\mathrm{2}\pi{G}−\frac{\mathrm{7}}{\mathrm{2}}\zeta\left(\mathrm{3}\right) \\ $$$$\int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{ln}\left[\frac{{x}+\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}{{x}−\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}\right]^{\mathrm{2}} \frac{{x}}{\mathrm{1}−{x}^{\mathrm{2}} }{dx}=\frac{.\pi^{\mathrm{2}} }{\mathrm{2}} \\…
Question Number 113587 by mohammad17 last updated on 14/Sep/20 Commented by mohammad17 last updated on 14/Sep/20 $${help}\:{me}\:{sir} \\ $$ Answered by 1549442205PVT last updated on…
Question Number 113578 by Algoritm last updated on 14/Sep/20 Commented by Algoritm last updated on 14/Sep/20 $$\mathrm{x}=\mathrm{1553}\:\:\:\mathrm{prove}\:\mathrm{that} \\ $$ Commented by Algoritm last updated on…
Question Number 113542 by Tinku Tara last updated on 13/Sep/20 $$\mathrm{App}\:\mathrm{Update}\:\mathrm{v2}.\mathrm{203} \\ $$$$\mathrm{A}\:\mathrm{function}\:\mathrm{plotter}\:\mathrm{for}\:\mathrm{one}\:\mathrm{variable} \\ $$$$\mathrm{is}\:\mathrm{available}.\:\mathrm{Steps}\:\mathrm{to}\:\mathrm{use} \\ $$$$\mathrm{Insert}\:\mathrm{Drawing} \\ $$$$\mathrm{Insert}\:\mathrm{Equation} \\ $$$$\mathrm{select}\:\mathrm{equation}\:\mathrm{from}\:\mathrm{the}\:\mathrm{list}\:\mathrm{of}\:\mathrm{shape} \\ $$$$\mathrm{tap}\:\mathrm{on}\:\mathrm{BUILD}\:\:\mathrm{and}\:\mathrm{select}\:\mathrm{plot} \\ $$$$\mathrm{A}\:\mathrm{sample}\:\mathrm{plot}\:\mathrm{is}\:\mathrm{show}\:\mathrm{as}\:\mathrm{image}\:\mathrm{below}.…
Question Number 113532 by Khalmohmmad last updated on 13/Sep/20 Commented by kaivan.ahmadi last updated on 13/Sep/20 $${dose}\:{note}\:{exist} \\ $$$$ \\ $$ Answered by Dwaipayan Shikari…
Question Number 179073 by yaslm last updated on 24/Oct/22 Answered by MJS_new last updated on 24/Oct/22 $$\mathrm{the}\:\mathrm{absolute}\:\mathrm{value}\:\mathrm{of}\:\mathrm{any}\:\mathrm{number}\:\mathrm{is}\:\mathrm{greater} \\ $$$$\mathrm{than}\:\mathrm{zero}\:\Rightarrow\:\mathrm{it}'\mathrm{s}\:\mathrm{greater}\:\mathrm{than}\:−\mathrm{2}\:\Rightarrow\:\mathrm{answer} \\ $$$$\mathrm{is} \\ $$$${x}\in\mathbb{C} \\ $$…
Question Number 113530 by Khalmohmmad last updated on 13/Sep/20 Answered by Aziztisffola last updated on 13/Sep/20 $$−\infty×\left(+\infty\right)=−\infty \\ $$ Answered by mathmax by abdo last…
Question Number 113524 by Khalmohmmad last updated on 13/Sep/20 Answered by Dwaipayan Shikari last updated on 13/Sep/20 $${tan}^{−\mathrm{1}} \left({x}^{\mathrm{2}} −{x}^{\mathrm{4}} \right)={y} \\ $$$${tany}={x}^{\mathrm{2}} \left(\mathrm{1}−{x}^{\mathrm{2}} \right)\:\:\:\:{x}\rightarrow\infty…
Question Number 179054 by Giantyusuf last updated on 24/Oct/22 $${find}\:{the}\:{sum}\:{of}\:{the}\:{following}\:{vectors} \\ $$$$\left({a}\right){AB},\:−{CD},\:{BC}\:{and}\:{CE} \\ $$$$\left({b}\right)\:{PR},\:−{SR},\:{ST}\:{and}\:−{QT}\:\: \\ $$$$\left({c}\right)\:{AC},\mathrm{3}{BC},{CD},\mathrm{3}{CD}\:{and}\:{DA} \\ $$$$\left({d}\right)\:{PQRS}\:{is}\:{a}\:{quadilateral}\:{with}\:{M}\:\&{N}\:{as}\:{the} \\ $$$${mid}−{points}\:{of}\:{SP}\:{and}\:{RQ}\:{respectively}. \\ $$$${Show}\:{that}\:\overset{\rightarrow} {{PS}}+\overset{\rightarrow} {{SR}}=\mathrm{2}\overset{\rightarrow} {{MN}}…