Question Number 113330 by mathdave last updated on 12/Sep/20 Answered by MJS_new last updated on 12/Sep/20 $$\mathrm{use}\:\mathrm{formula}\:\mathrm{for}\:\mathrm{half}\:\mathrm{derivate} \\ $$$$\frac{{d}^{{q}} }{{dx}^{{q}} }{x}^{{p}} =\frac{\Gamma\:\left({p}+\mathrm{1}\right)}{\Gamma\:\left({p}−{q}+\mathrm{1}\right)}{x}^{{p}−{q}} \\ $$$$\Rightarrow \\…
Question Number 113333 by mohammad17 last updated on 12/Sep/20 Answered by mr W last updated on 13/Sep/20 $${let}\:{u}={xy} \\ $$$${y}=\frac{{u}}{{x}} \\ $$$${y}'=−\frac{{u}}{{x}^{\mathrm{2}} }+\frac{{u}'}{{x}} \\ $$$$−\frac{{u}}{{x}^{\mathrm{2}}…
Question Number 113309 by Hassen_Timol last updated on 12/Sep/20 Commented by Hassen_Timol last updated on 12/Sep/20 $$\mathrm{Can}\:\mathrm{you}\:\mathrm{please}\:\mathrm{help}\:\mathrm{me}…\:? \\ $$ Commented by mathmax by abdo last…
Question Number 47768 by Cesar Larez last updated on 14/Nov/18 $$\mathrm{Somebody}\:\mathrm{know}\:\mathrm{spanish}? \\ $$ Commented by Cesar Larez last updated on 14/Nov/18 $$\mathrm{have}\:\mathrm{u}\:\mathrm{whatsapp}? \\ $$ Commented…
Question Number 113278 by mathdave last updated on 12/Sep/20 $${solve} \\ $$$$\int\frac{\sqrt{{x}^{\mathrm{2}} +{x}+\mathrm{2}−\sqrt{\mathrm{4}{x}^{\mathrm{2}} +\mathrm{4}{x}+\mathrm{4}}}}{{x}\sqrt{{x}^{\mathrm{4}} +{x}^{\mathrm{3}} +{x}^{\mathrm{2}} }}{dx} \\ $$ Answered by 1549442205PVT last updated on…
Question Number 113271 by mathdave last updated on 12/Sep/20 $${solve}\:{the}\:{initial}\:{boundary}\:{value} \\ $$$${problem}\:{of}\:{wave}\:{equation} \\ $$$$\frac{\partial^{\mathrm{2}} {u}\left({x},{t}\right)}{\partial{t}^{\mathrm{2}} }=\mathrm{9}\frac{\partial^{\mathrm{2}} {u}\left({x},{t}\right)}{\partial{x}^{\mathrm{2}} },\mathrm{0}<{x}<\mathrm{2},{t}>\mathrm{0} \\ $$$${u}\left(\mathrm{0},{t}\right)=\mathrm{1},{u}\left(\mathrm{2},{t}\right)=\mathrm{3},{t}>\mathrm{0} \\ $$$${u}\left({x},\mathrm{0}\right)=\mathrm{2},\mathrm{0}<{x}<\mathrm{2} \\ $$$$\frac{\partial{u}}{\partial{t}}\left({x},\mathrm{0}\right)=\mathrm{sin2}{x},\mathrm{0}<{x}<\mathrm{2} \\…
Question Number 113246 by mohammad17 last updated on 11/Sep/20 Commented by mohammad17 last updated on 11/Sep/20 $${please}\:{sir}\:{help}\:{me} \\ $$ Answered by Aziztisffola last updated on…
Question Number 113237 by A8;15: last updated on 11/Sep/20 Answered by MJS_new last updated on 11/Sep/20 $$\mathrm{I}\:\mathrm{solved}\:\mathrm{it}.\:\mathrm{question}\:\mathrm{113109} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 113219 by naka3546 last updated on 11/Sep/20 Answered by 1549442205PVT last updated on 11/Sep/20 Commented by Aina Samuel Temidayo last updated on 11/Sep/20…
Question Number 178725 by ComplexPrime last updated on 20/Oct/22 $$\mathrm{Let}\:{a}\:\mathrm{be}\:\mathrm{a}\:\mathrm{positive}\:\mathrm{number}.\:\mathrm{Then} \\ $$$$\sqrt{{a}}=\sqrt{\left(−{a}\right)\left(−\mathrm{1}\right)}=\sqrt{−{a}}\centerdot{i}=\sqrt{{a}\left(−\mathrm{1}\right)}\centerdot{i}=\sqrt{{a}}\centerdot{i}^{\mathrm{2}} =−\sqrt{{a}} \\ $$$$\mathrm{Where}\:\mathrm{is}\:\mathrm{the}\:\mathrm{mistake}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com