Question Number 47561 by ggny last updated on 11/Nov/18 $$\mathrm{thanks}\:\mathrm{sir} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 47552 by ggny last updated on 11/Nov/18 $$\frac{\mathrm{5}\left(\mathrm{x}−\mathrm{2}\right)}{\mathrm{4}}=\frac{\mathrm{6x}−\mathrm{9}}{\mathrm{5}}\:\:\:\mathrm{plz}\:\mathrm{help}\:\mathrm{me} \\ $$ Commented by maxmathsup by imad last updated on 11/Nov/18 $${we}\:{use}\:{the}\:{equivalence}\:\:\frac{{a}}{{b}}=\frac{{c}}{{d}}\:\Leftrightarrow\frac{{a}}{{b}}−\frac{{c}}{{d}}=\mathrm{0}\:{so} \\ $$$$\frac{\mathrm{5}\left({x}−\mathrm{2}\right)}{\mathrm{4}}=\frac{\mathrm{6}{x}−\mathrm{9}}{\mathrm{5}}\:\Leftrightarrow\frac{\mathrm{5}\left({x}−\mathrm{2}\right)}{\mathrm{4}}−\frac{\mathrm{6}{x}−\mathrm{9}}{\mathrm{5}}\:=\mathrm{0}\Leftrightarrow\:\frac{\mathrm{25}\left({x}−\mathrm{2}\right)−\mathrm{4}\left(\mathrm{6}{x}−\mathrm{9}\right)}{\mathrm{20}}\:=\mathrm{0}\:\Rightarrow \\…
Question Number 113070 by ZiYangLee last updated on 11/Sep/20 $$\mathrm{If}\:{n}\in\mathbb{Z}^{+} ,\:\mathrm{prove}\:\mathrm{that} \\ $$$$\frac{\mathrm{1}}{\mathrm{2}\sqrt{\mathrm{1}}}+\frac{\mathrm{1}}{\mathrm{3}\sqrt{\mathrm{2}}}+\frac{\mathrm{1}}{\mathrm{4}\sqrt{\mathrm{3}}}+…\frac{\mathrm{1}}{\left({n}+\mathrm{1}\right)\sqrt{{n}}}<\mathrm{2} \\ $$$$ \\ $$ Answered by 1549442205PVT last updated on 11/Sep/20 $$\mathrm{We}\:\mathrm{have}\:\frac{\mathrm{1}}{\left(\mathrm{n}+\mathrm{1}\right)\sqrt{\mathrm{n}}}=\sqrt{\mathrm{n}}.\frac{\mathrm{1}}{\left(\mathrm{n}+\mathrm{1}\right)\mathrm{n}}…
Question Number 113063 by Aina Samuel Temidayo last updated on 11/Sep/20 Answered by nimnim last updated on 11/Sep/20 Commented by nimnim last updated on 11/Sep/20…
Question Number 47523 by hassentimol last updated on 11/Nov/18 $$\mathrm{I}\:\mathrm{have}\:\mathrm{a}\:\mathrm{question}, \\ $$$$\mathrm{Can}\:\mathrm{we}\:\mathrm{consider}\:\mathrm{as}\:\mathrm{a}\:\mathrm{complex}\:\mathrm{number}\:\mathrm{a} \\ $$$$\mathrm{number}\:\mathrm{if}\:\mathrm{its}\:\mathrm{real}\:\mathrm{part}\:\mathrm{or}\:\mathrm{his}\:\mathrm{imaginary} \\ $$$$\mathrm{part}\:\mathrm{is}\:\mathrm{null}\:? \\ $$$$\mathrm{For}\:\mathrm{example}\:: \\ $$$${a}\:+\:{b}\:{i} \\ $$$$\mathrm{where}\:\mathrm{a}=\mathrm{0}\:\mathrm{xor}\:\mathrm{b}=\mathrm{0}. \\ $$$$\mathrm{for}\:\mathrm{example}, \\…
Question Number 47508 by naka3546 last updated on 11/Nov/18 Commented by gunawan last updated on 11/Nov/18 $${xyz}=\mathrm{1} \\ $$$${xy}=\frac{\mathrm{1}}{{z}} \\ $$$${x}+{xy}=\mathrm{5} \\ $$$${x}\left(\mathrm{1}+{y}\right)=\mathrm{5} \\ $$$${x}=\frac{\mathrm{5}}{\mathrm{1}+{y}}…
Question Number 178582 by Best1 last updated on 19/Oct/22 $${show}\:{that}\:{Range}\:{of}\:{the}\:{ff}\:{projection}\: \\ $$$${obtained}\:{by}\:{algebric}\:{expression} \\ $$$${R}=\frac{\left({ucos}\theta\right)\left({usin}\theta\right)+\sqrt{\left({usin}\theta\right)^{\mathrm{2}} +\mathrm{2}{gh}}}{{g}}\:\:\:{help}\:{me}\:{please} \\ $$ Commented by Best1 last updated on 18/Oct/22 $${please}\:{help}\:{me}…
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Question Number 178561 by Huy last updated on 18/Oct/22 $${A}\:{sequence}\:{is}\:{given}\:{by}\: \\ $$$$\:\:\:\:\:\begin{cases}{{u}_{\mathrm{1}} =\mathrm{1}}\\{{u}_{{n}+\mathrm{1}} =\sqrt{{u}_{{n}} ^{\mathrm{2}} +\mathrm{1}}−{u}_{{n}} }\end{cases}\:\:\left({n}\in\mathbb{N},\:{n}\geqslant\mathrm{1}\right) \\ $$$${Find}\:{lim}\:{u}_{{n}} ? \\ $$ Answered by mr…
Question Number 113015 by mohssinee last updated on 10/Sep/20 Answered by Olaf last updated on 10/Sep/20 $$\underset{{k}=\mathrm{0}} {\overset{{n}} {\sum}}\left(\mathrm{2}{k}^{\mathrm{2}} +\mathrm{3}{k}+\mathrm{5}\right)\:= \\ $$$$\mathrm{2}\underset{{k}=\mathrm{0}} {\overset{{n}} {\sum}}{k}^{\mathrm{2}} +\mathrm{3}\underset{{k}=\mathrm{0}}…