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Question-178508

Question Number 178508 by yaslm last updated on 17/Oct/22 Commented by MJS_new last updated on 17/Oct/22 $$\mathrm{obviously}\:{x}={y}=\mathrm{0} \\ $$$$\mathrm{we}\:\mathrm{can}\:\mathrm{choose}\:{x}\in\mathbb{R}\backslash\left\{\mathrm{log}_{\mathrm{6}} \:\mathrm{48}\right\}\:\mathrm{to}\:\mathrm{get} \\ $$$${y}=\frac{{x}\mathrm{ln}\:\mathrm{72}}{{x}\mathrm{ln}\:\mathrm{6}\:−\mathrm{ln}\:\mathrm{48}} \\ $$$$ \\…

400-2-100-2-

Question Number 47421 by 143jesus last updated on 09/Nov/18 $$\sqrt{\mathrm{400}^{\mathrm{2}} +\mathrm{100}^{\mathrm{2}} =} \\ $$ Answered by MJS last updated on 09/Nov/18 $$=\sqrt{\mathrm{100}^{\mathrm{2}} ×\mathrm{4}^{\mathrm{2}} +\mathrm{100}^{\mathrm{2}} ×\mathrm{1}^{\mathrm{2}}…

For-the-sequence-u-n-if-u-1-1-u-2-2-and-u-n-2-2-u-n-2-u-n-1-2-u-n-u-n-1-for-all-natural-number-n-Find-lim-u-n-

Question Number 178468 by Huy last updated on 16/Oct/22 $${For}\:{the}\:{sequence}\:\left\{{u}_{{n}} \right\}\:{if}\:{u}_{\mathrm{1}} =\mathrm{1},\:{u}_{\mathrm{2}} =\mathrm{2}\:{and}\:{u}_{{n}+\mathrm{2}} ^{\mathrm{2}} ={u}_{{n}} ^{\mathrm{2}} +{u}_{{n}+\mathrm{1}} ^{\mathrm{2}} −{u}_{{n}} {u}_{{n}+\mathrm{1}} ,\:{for}\:{all}\:{natural}\:{number}\:{n}. \\ $$$${Find}\:{lim}\:{u}_{{n}} ? \\…

find-n-th-terms-of-2-3-5-7-11-13-15-17-

Question Number 178467 by mokys last updated on 16/Oct/22 $${find}\:{n}^{{th}\:} {terms}\:{of}\:\mathrm{2},\mathrm{3},\mathrm{5},\mathrm{7},\mathrm{11},\mathrm{13},\mathrm{15},\mathrm{17},. \\ $$ Answered by Frix last updated on 16/Oct/22 $${a}_{{n}} =−\frac{\mathrm{41}{n}^{\mathrm{7}} }{\mathrm{5040}}+\frac{\mathrm{37}{n}^{\mathrm{6}} }{\mathrm{144}}−\frac{\mathrm{2381}{n}^{\mathrm{5}} }{\mathrm{720}}+\frac{\mathrm{3211}{n}^{\mathrm{4}}…

solve-the-equation-y-x-3-2y-x-5-by-ussing-matrixis-method-help-me-sir-please-

Question Number 112904 by mohammad17 last updated on 10/Sep/20 $${solve}\:{the}\:{equation}\:{y}+{x}=\mathrm{3},\:\mathrm{2}{y}+{x}=\mathrm{5}\:{by}\:{ussing}\:{matrixis}\:{method} \\ $$$${help}\:{me}\:{sir}\:{please}\:? \\ $$ Answered by bemath last updated on 10/Sep/20 $$\begin{pmatrix}{\mathrm{1}\:\:\:\mathrm{1}}\\{\mathrm{1}\:\:\:\mathrm{2}}\end{pmatrix}\begin{pmatrix}{\mathrm{x}}\\{\mathrm{y}}\end{pmatrix}=\begin{pmatrix}{\mathrm{3}}\\{\mathrm{5}}\end{pmatrix} \\ $$$$\begin{pmatrix}{\mathrm{x}}\\{\mathrm{y}}\end{pmatrix}=\begin{pmatrix}{\mathrm{1}\:\:\:\mathrm{1}}\\{\mathrm{1}\:\:\:\mathrm{2}}\end{pmatrix}^{−\mathrm{1}} \begin{pmatrix}{\mathrm{3}}\\{\mathrm{5}}\end{pmatrix}…

prove-that-B-1-A-1-AB-1-if-A-34-12-B-12-13-please-sir-help-me-

Question Number 112906 by mohammad17 last updated on 10/Sep/20 $${prove}\:{that}\:\left({B}^{−\mathrm{1}} \right)\left({A}^{−\mathrm{1}} \right)=\left({AB}\right)^{−\mathrm{1}} \:{if}\:{A}=\left(\mathrm{34},\mathrm{12}\right),{B}=\left(\mathrm{12},−\mathrm{13}\right) \\ $$$${please}\:{sir}\:{help}\:{me} \\ $$ Commented by mohammad17 last updated on 10/Sep/20 $${help}\:{me}\:{sir}…