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1-Let-z-3-4i-3-4i-where-square-root-is-taken-with-positive-real-part-Then-Re-z-is-a-3-b-4-c-2-d-1-2-Suppose-a-b-c-are-in-AP-and-a-2-b-2-c-2-are-in-GP-If

Question Number 112364 by john santu last updated on 07/Sep/20 $$\left(\mathrm{1}\right)\:{Let}\:{z}\:=\:\sqrt{\mathrm{3}+\mathrm{4}{i}}\:+\:\sqrt{−\mathrm{3}−\mathrm{4}{i}}\:,\:{where} \\ $$$${square}\:{root}\:{is}\:{taken}\:{with}\:{positive}\: \\ $$$${real}\:{part}.\:{Then}\:{Re}\left({z}\right)\:{is}\:\_ \\ $$$$\left({a}\right)\mathrm{3}\:\:\:\:\:\left({b}\right)\:\mathrm{4}\:\:\:\:\:\left({c}\right)\:\mathrm{2}\:\:\:\:\:\left({d}\right)\:\mathrm{1} \\ $$$$\left(\mathrm{2}\right){Suppose}\:{a},{b},{c}\:{are}\:{in}\:{AP}\:{and}\:{a}^{\mathrm{2}} ,{b}^{\mathrm{2}} ,{c}^{\mathrm{2}} \\ $$$${are}\:{in}\:{GP}.\:{If}\:{a}<{b}<{c}\:{and}\:{a}+{b}+{c}=\frac{\mathrm{3}}{\mathrm{2}}, \\ $$$${then}\:{a}\:=\:\_…

Question-177884

Question Number 177884 by DAVONG last updated on 10/Oct/22 Answered by mr W last updated on 10/Oct/22 $$\mathrm{6}\:{black}\:{and}\:{n}\:{red}\:{balls}\:{in}\:{bag}. \\ $$$${to}\:{take}\:\mathrm{3}\:{balls}\:{there}\:{are}\:{totally} \\ $$$${C}_{\mathrm{3}} ^{{n}+\mathrm{6}} \:{ways}. \\…

Question-177880

Question Number 177880 by DAVONG last updated on 10/Oct/22 Answered by mr W last updated on 10/Oct/22 $$\left(\mathrm{1}+{x}\right)^{{n}} =\underset{{k}=\mathrm{0}} {\overset{{n}} {\sum}}{C}_{{k}} ^{{n}} {x}^{{k}} \\ $$$${n}\left(\mathrm{1}+{x}\right)^{{n}−\mathrm{1}}…

Can-someone-please-help-me-for-the-following-Solve-fot-x-exact-value-with-formulas-17x-4-7x-3-11-x-2-18x-3-0-Thank-you-

Question Number 46802 by hassentimol last updated on 31/Oct/18 $$\mathrm{Can}\:\mathrm{someone}\:\mathrm{please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{for}\:\mathrm{the}\:\mathrm{following}: \\ $$$$ \\ $$$$\mathrm{Solve}\:\mathrm{fot}\:{x}\:\left(\mathrm{exact}\:\mathrm{value}\:\mathrm{with}\:\mathrm{formulas}\right)\:: \\ $$$$ \\ $$$$\mathrm{17}{x}^{\mathrm{4}} \:+\:\mathrm{7}{x}^{\mathrm{3}} \:−\:\sqrt{\mathrm{11}}\mathrm{x}^{\mathrm{2}} \:−\:\mathrm{18}{x}\:+\:\mathrm{3}\:=\:\mathrm{0} \\ $$$$ \\ $$$$\mathrm{Thank}\:\mathrm{you}…