Question Number 112328 by mohammad17 last updated on 07/Sep/20 $${find}\:{the}\:{all}\:{root}\:\left({m}^{\mathrm{3}} −\mathrm{6}{m}+\mathrm{9}\right)=\mathrm{0} \\ $$ Answered by MJS_new last updated on 07/Sep/20 $$\mathrm{first}\:\mathrm{try}\:\mathrm{factors}\:\mathrm{of}\:\mathrm{9}:\:\pm\mathrm{1},\:\pm\mathrm{3},\:\pm\mathrm{9} \\ $$$$\Rightarrow\:{m}_{\mathrm{1}} =−\mathrm{3} \\…
Question Number 112320 by mohammad17 last updated on 07/Sep/20 Commented by mohammad17 last updated on 07/Sep/20 $${help}\:{me}\:{sir}\:{in}\:{Q}\mathrm{1} \\ $$ Answered by john santu last updated…
Question Number 177848 by mathdave last updated on 09/Oct/22 Commented by mathdave last updated on 09/Oct/22 $${mr}\:{w}\:{help}\:{me}\:{out}\:{oo}\:{or}\:{others} \\ $$ Commented by mr W last updated…
Question Number 112310 by mohammad17 last updated on 07/Sep/20 Answered by bemath last updated on 07/Sep/20 $$\left.\mathrm{Q2}/\mathrm{A}\right)\:\mathrm{5x}+\mathrm{6y}\:=\:\mathrm{5}×\mathrm{5}+\mathrm{6}×\mathrm{2} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{5x}+\mathrm{6y}\:=\:\mathrm{37} \\ $$ Answered by mathmax by…
Question Number 112313 by mathdave last updated on 07/Sep/20 $${solve} \\ $$$$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\mathrm{ln}{x}}{\:\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }}{dx} \\ $$ Commented by mohammad17 last updated on 07/Sep/20 $${set}:{x}={tan}\left({r}\right)\Rightarrow{dx}={sec}^{\mathrm{2}}…
Question Number 112301 by mohammad17 last updated on 07/Sep/20 Commented by mohammad17 last updated on 07/Sep/20 $${help}\:{me}\:{sir} \\ $$ Terms of Service Privacy Policy Contact:…
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Question Number 112287 by weltr last updated on 07/Sep/20 $$\begin{cases}{{x}^{\mathrm{2}} \:+\:\mathrm{3}{xy}\:+\:{y}^{\mathrm{2}} \:=\:−\mathrm{1}}\\{{x}^{\mathrm{3}} \:+\:{y}^{\mathrm{3}} \:=\:\mathrm{7}}\end{cases} \\ $$ Answered by ajfour last updated on 07/Sep/20 $${x}^{\mathrm{2}} +{y}^{\mathrm{2}}…
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Question Number 112231 by mohammad17 last updated on 06/Sep/20 $$\int{z}^{\mathrm{3}} {e}^{−\frac{\mathrm{4}}{\mathrm{3}}{z}^{\mathrm{3}} } {dz} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com