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To-this-formula-find-the-value-of-S-when-t-1-u-2-a-3-b-4-c-5-S-tu-a-b-c-Answer-S-0-1666666666666-0-17-Solution-S-tu-

Question Number 46464 by Zahir Ussene Mamede last updated on 26/Oct/18 $${To}\:{this}\:{formula}\:{find}\:{the}\:{value}\:{of}\:{S}\:{when}\:{t}=\mathrm{1}\:{u}=\mathrm{2}\:{a}=\mathrm{3}\:{b}=\mathrm{4}\:{c}=\mathrm{5} \\ $$$${S}=\frac{{tu}}{\left({a}+{b}+{c}\right)} \\ $$$$\left[{Answer}\right]========================= \\ $$$$ \\ $$$$\:\:\:\:{S}=\mathrm{0}.\mathrm{1666666666666}… \\ $$$$\:\:\:\:\:\:\:\approx\mathrm{0}.\mathrm{17} \\ $$$$ \\…

Question-111974

Question Number 111974 by mohammad17 last updated on 05/Sep/20 Answered by mathmax by abdo last updated on 05/Sep/20 $$\left.\mathrm{1}\right)\mathrm{f}\left(\mathrm{x},\mathrm{y}\right)=\mathrm{x}^{\mathrm{2}} \:\mathrm{arctan}\left(\frac{\mathrm{y}}{\mathrm{x}}\right)\:\Rightarrow\frac{\partial\mathrm{f}}{\partial\mathrm{x}}\left(\mathrm{x},\mathrm{y}\right)=\mathrm{2x}\:\mathrm{arctan}\left(\frac{\mathrm{y}}{\mathrm{x}}\right)+\mathrm{x}^{\mathrm{2}} ×\left(\frac{−\mathrm{y}}{\mathrm{x}^{\mathrm{2}} \left(\mathrm{1}+\frac{\mathrm{y}^{\mathrm{2}} }{\mathrm{x}^{\mathrm{2}} }\right)}\right) \\…

Question-46430

Question Number 46430 by MrW3 last updated on 26/Oct/18 Commented by MrW3 last updated on 27/Oct/18 $${maybe}\:{we}\:{should}\:{at}\:{first}\:{forget}\:{the} \\ $$$${length}\:{of}\:{the}\:{rope}\:{ring}.\:{the}\:{question} \\ $$$${is}\:{just}\:{if}\:{the}\:{rope}\:{can}\:{rest}\:{in}\:{a}\:{inclined} \\ $$$${position}\:{on}\:{the}\:{surface}\:{of}\:{cone}. \\ $$…

Give-a-proof-for-the-following-a-R-b-c-R-x-C-ax-2-bx-c-a-x-b-b-2-4ac-2a-x-b-b-2-4ac-2a-To-answer-I-should-not-expand-from-the-second-

Question Number 46427 by hassentimol last updated on 26/Oct/18 $$\mathrm{Give}\:\mathrm{a}\:\mathrm{proof}\:\mathrm{for}\:\mathrm{the}\:\mathrm{following}. \\ $$$$ \\ $$$$ \\ $$$$\forall\:{a}\:\in\:\mathbb{R}^{\ast} \:,\:\left({b},{c}\right)\:\in\:\mathbb{R}\:,\:{x}\:\in\:\mathbb{C}\:: \\ $$$$ \\ $$$$ \\ $$$${ax}^{\mathrm{2}} \:+\:{bx}\:+\:{c} \\…

Question-111934

Question Number 111934 by mohammad17 last updated on 05/Sep/20 Answered by Aina Samuel Temidayo last updated on 05/Sep/20 $$\sqrt{\mathrm{x}+\mathrm{5}}+\sqrt{\mathrm{2x}+\mathrm{1}}=\mathrm{4x}−\mathrm{10} \\ $$$$\mathrm{Squaring}\:\mathrm{both}\:\mathrm{sides},\mathrm{we}\:\mathrm{have} \\ $$$$\mathrm{x}+\mathrm{5}+\mathrm{2x}+\mathrm{1}+\mathrm{2}\sqrt{\left(\mathrm{x}+\mathrm{5}\right)\left(\mathrm{2x}+\mathrm{1}\right)}=\mathrm{16x}^{\mathrm{2}} +\mathrm{100}−\mathrm{80x} \\…