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RESULT-Integration-Date-04-09-2020-FULL-MARKS-40-1-SREETOMA-40-2

Question Number 111548 by tkb last updated on 04/Sep/20 $$ \\ $$$$ \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{RESULT}\left(\mathrm{I}\boldsymbol{\mathrm{ntegration}}\right)\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{D}\boldsymbol{\mathrm{ate}}:\mathrm{04}.\mathrm{09}.\mathrm{2020} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{FULL}\:\mathrm{MARKS}\::\:\mathrm{40} \\ $$$$\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\mathrm{1}\:\:.\:\:\:\:.\boldsymbol{\mathrm{SR}}\mathrm{EET}\boldsymbol{\mathrm{OMA}}\::\mathrm{40} \\…

Question-111458

Question Number 111458 by mohammad17 last updated on 03/Sep/20 Commented by kaivan.ahmadi last updated on 03/Sep/20 $${Q}_{\mathrm{1}} \\ $$$$\left({ab}\right)^{{n}} =\left({ab}\right)\left({ab}\right)…\left({ab}\right)\:;\:{n}\:{times} \\ $$$${a}\left({ba}\right)\left({ba}\right)….\left({ba}\right){b}={a}\left({ab}\right)\left({ab}\right)…\left({ab}\right){b}= \\ $$$${a}^{\mathrm{2}} \left({ba}\right)….\left({ba}\right){b}^{\mathrm{2}}…

7-6-x-10-60-plz-help-me-

Question Number 45907 by gunay last updated on 18/Oct/18 $$\mathrm{7}×\left(\mathrm{6}+\mathrm{x}\right)−\mathrm{10}=\mathrm{60}\:\:\:\:\:\mathrm{plz}\:\mathrm{help}\:\mathrm{me} \\ $$ Commented by peter frank last updated on 18/Oct/18 $$\mathrm{42}+\mathrm{7x}−\mathrm{10}=\mathrm{60} \\ $$$$\mathrm{7x}=\mathrm{30} \\ $$$$\mathrm{x}=\frac{\mathrm{30}}{\mathrm{7}\:\:}…

solve-for-x-x-4-4x-1-0-

Question Number 45896 by Sanjarbek last updated on 18/Oct/18 $$\boldsymbol{{solve}}\:\boldsymbol{{for}}\:\boldsymbol{{x}} \\ $$$$\boldsymbol{{x}}^{\mathrm{4}} −\mathrm{4}\boldsymbol{{x}}+\mathrm{1}=\mathrm{0} \\ $$ Commented by tanmay.chaudhury50@gmail.com last updated on 18/Oct/18 Commented by tanmay.chaudhury50@gmail.com…

Question-176963

Question Number 176963 by Ml last updated on 28/Sep/22 Commented by Frix last updated on 29/Sep/22 $$\Omega=\underset{\mathrm{0}} {\overset{\mathrm{2}\pi} {\int}}\frac{\epsilon^{\mathrm{2}} \mathrm{sin}^{\mathrm{2}} \:\theta}{\left(\mathrm{1}−\epsilon\mathrm{cos}\:\theta\right)^{\mathrm{2}} }{d}\theta=\mathrm{2}\underset{\mathrm{0}} {\overset{\pi} {\int}}\frac{\epsilon^{\mathrm{2}} \mathrm{sin}^{\mathrm{2}}…