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Question-202224

Question Number 202224 by sonukgindia last updated on 23/Dec/23 Answered by witcher3 last updated on 23/Dec/23 $$\mathrm{x}\rightarrow\frac{\mathrm{1}}{\mathrm{a}+\mathrm{bcos}^{\mathrm{2}} \left(\mathrm{x}\right)}=\mathrm{f}\left(\mathrm{x}\right),\mathrm{is}\:\mathrm{p}\:\mathrm{peridic} \\ $$$$\Rightarrow\int_{\mathrm{k}\pi} ^{\left(\mathrm{k}+\mathrm{1}\right)\pi} \mathrm{f}\left(\mathrm{x}\right)\mathrm{dx}=\int_{\mathrm{0}} ^{\pi} \mathrm{f}\left(\mathrm{x}\right)\mathrm{dx};\mathrm{by}\:\mathrm{k}\pi+\mathrm{y}=\mathrm{x} \\…

Question-202276

Question Number 202276 by professorleiciano last updated on 23/Dec/23 Answered by professorleiciano last updated on 23/Dec/23 $${Area}\left({retangulo}\right)=\mathrm{4}×\mathrm{6}=\mathrm{24}{m}^{\mathrm{2}} \\ $$$${Area}\left({triangulo}\:{I}\right)=\mathrm{3}×\mathrm{6}=\mathrm{18}/\mathrm{2}=\mathrm{9}{m}^{\mathrm{2}} \\ $$$${Area}\left({triangulo}\:{II}\right)=\mathrm{3}×\mathrm{4}=\mathrm{12}/\mathrm{2}=\mathrm{6}{m}^{\mathrm{2}} \\ $$$${Area}\left({triangulo}\:{III}\right)=\mathrm{3}×\mathrm{4}=\mathrm{12}/\mathrm{2}=\mathrm{6}{m}^{\mathrm{2}} \\ $$$${Area}\left({total}\right)=\mathrm{24}{m}^{\mathrm{2}}…

Question-202170

Question Number 202170 by sonukgindia last updated on 22/Dec/23 Answered by AST last updated on 22/Dec/23 $$\mathrm{112}={a}\mathrm{2}^{{m}} \Rightarrow{a}\mathrm{2}^{{m}−\mathrm{4}} =\mathrm{7}\Rightarrow\mathrm{2}^{{m}−\mathrm{4}} =\mathrm{1}\Rightarrow{m}=\mathrm{4};{a}=\mathrm{7} \\ $$$$\mathrm{11392}={b}\mathrm{2}^{{n}} =\mathrm{2}^{\mathrm{7}} ×\mathrm{89}\Rightarrow{n}=\mathrm{7};{b}=\mathrm{89} \\…

2-2023-abc-a-b-c-

Question Number 202203 by SEKRET last updated on 22/Dec/23 $$\:\: \\ $$$$ \\ $$$$\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\mathrm{2}^{\mathrm{2023}} =\:\overset{\_\_\_\_\_\_\_\_\_\_\_\_\_\_} {\boldsymbol{\mathrm{abc}}………….} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\boldsymbol{\mathrm{a}}+\boldsymbol{\mathrm{b}}+\boldsymbol{\mathrm{c}}\:=\:? \\ $$$$ \\ $$$$ \\…

Question-202153

Question Number 202153 by sonukgindia last updated on 22/Dec/23 Answered by witcher3 last updated on 22/Dec/23 $$\mathrm{ln}\left(\mathrm{x}\right)\mathrm{y}'+\frac{\mathrm{y}}{\mathrm{x}}=\left(\mathrm{ln}\left(\mathrm{x}\right)\right)\mathrm{y}'+\left(\mathrm{ln}\left(\mathrm{x}\right)\right)'\mathrm{y} \\ $$$$=\frac{\mathrm{d}}{\mathrm{dx}}\left(\mathrm{ln}\left(\mathrm{x}\right)\mathrm{y}\right) \\ $$$$\Leftrightarrow\begin{cases}{\frac{\mathrm{d}}{\mathrm{dx}}\left(\mathrm{y}.\left(\mathrm{ln}\left(\mathrm{x}\right)\right)=\mathrm{x}^{\mathrm{2}} \mathrm{sin}\left(\mathrm{x}\right)\right.}\\{\mathrm{y}\left(\pi\right)=\frac{\pi^{\mathrm{2}} }{\mathrm{ln}\left(\pi\right)}}\end{cases} \\ $$$$\Rightarrow\int_{\pi}…