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if-y-1-x-2-x-3-x-n-x-y-

Question Number 203910 by Davidtim last updated on 01/Feb/24 $${if}\:\:\:{y}=\left(\mathrm{1}−{x}\right)\left(\mathrm{2}−{x}\right)\left(\mathrm{3}−{x}\right)\centerdot\centerdot\centerdot\left({n}−{x}\right) \\ $$$${y}^{'} =? \\ $$ Answered by mr W last updated on 01/Feb/24 $${y}=\underset{{k}=\mathrm{1}} {\overset{{n}}…

Hmmm-I-have-one-Question-f-t-C-C-mean-can-derivate-times-where-t-R-Can-f-t-integrable-when-S-R-Q-Ex-integral-1-e-ln-z-dz-S-1-e-But-Except-Q-in-set-S-like-

Question Number 203875 by MathedUp last updated on 31/Jan/24 $$\mathrm{Hmmm}…..\:\mathrm{I}\:\mathrm{have}\:\mathrm{one}\:\mathrm{Question}. \\ $$$${f}\left({t}\right)\in{C}^{\infty} \:,\:\left\{{C}_{\:} ^{\boldsymbol{\alpha}} \:\mathrm{mean}\:\mathrm{can}\:\mathrm{derivate}\:\boldsymbol{\alpha}\:\mathrm{times}.\right\} \\ $$$$\mathrm{where}\:{t}\in\mathbb{R}\:,\:\mathrm{Can}\:{f}\left({t}\right)\:\:\mathrm{integrable}\:\mathrm{when}\:{S}\in\mathbb{R}\backslash\left\{\mathbb{Q}\right\}?? \\ $$$$\mathrm{Ex}.\:\mathrm{integral}\:\int_{\mathrm{1}} ^{\:{e}} \:\mathrm{ln}\left({z}\right)\mathrm{d}{z}\:{S}\in\left[\mathrm{1},{e}\right]\: \\ $$$$\mathrm{But}\:\mathrm{Except}\:\mathbb{Q}\:\mathrm{in}\:\mathrm{set}\:{S}\:\mathrm{like}..\:{S}^{'} ={S}\backslash\left\{\mathbb{Q}\right\}\: \\…

Question-203822

Question Number 203822 by 073 last updated on 29/Jan/24 Answered by esmaeil last updated on 29/Jan/24 $$\mathrm{1}:\frac{\mathrm{1}}{{x}}={p}\overset{{x}\rightarrow\infty\rightarrow{p}\rightarrow\mathrm{0}} {\rightarrow}\left[\frac{{x}+\mathrm{1}}{{x}}\right]=\left[{p}+\mathrm{1}\right)=\mathrm{1}\rightarrow \\ $$$$\Omega=\underset{{p}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{sinp}}{{p}}=\mathrm{1} \\ $$ Answered by…

Question-203690

Question Number 203690 by yaslm last updated on 26/Jan/24 Answered by Frix last updated on 26/Jan/24 $$=\frac{\mathrm{1}}{\mathrm{3}}\int\frac{{x}+\mathrm{1}}{{x}^{\mathrm{2}} −{x}+\mathrm{1}}−\frac{\mathrm{1}}{{x}+\mathrm{1}}{dx} \\ $$$$\mathrm{Should}\:\mathrm{be}\:\mathrm{easy}\:\mathrm{now} \\ $$ Terms of Service…

Question-203716

Question Number 203716 by professorleiciano last updated on 26/Jan/24 Answered by AST last updated on 26/Jan/24 $${Let}\:{AP}\:{and}\:{DC}\:{meet}\:{at}\:{F},{then}\:\bigtriangleup{BPA}\approx\bigtriangleup{CPF} \\ $$$$\Rightarrow\frac{{BA}}{{CF}}=\frac{{BP}}{{CP}}\Rightarrow\frac{{s}}{{CF}}=\frac{\mathrm{8}}{{s}−\mathrm{8}}\Rightarrow{CF}=\frac{{s}\left({s}−\mathrm{8}\right)}{\mathrm{8}}…\left({i}\right) \\ $$$${in}\:\bigtriangleup{AFD};{AQ}\:{bisects}\:\angle{FAD}\Rightarrow\frac{{AD}}{{DQ}}=\frac{{AF}}{{FQ}} \\ $$$$\Rightarrow\frac{{s}}{\mathrm{9}}=\frac{\sqrt{{s}^{\mathrm{2}} +\left({s}+{CF}\right)^{\mathrm{2}} }}{{CF}+{s}−\mathrm{9}}\Rightarrow\frac{{s}}{\mathrm{9}}=\frac{\sqrt{{s}^{\mathrm{2}}…

50-divide-into-to-part-that-the-mini-figure-2-3-and-large-one-is-5-7-and-the-sum-of-them-is-21-find-the-tow-figures-

Question Number 203712 by Davidtim last updated on 26/Jan/24 $$\mathrm{50}\:{divide}\:{into}\:{to}\:{part}\:{that}\:{the}\:{mini}\: \\ $$$${figure}\:\frac{\mathrm{2}}{\mathrm{3}}\:{and}\:{large}\:{one}\:{is}\:\frac{\mathrm{5}}{\mathrm{7}},\:{and}\:{the}\: \\ $$$${sum}\:{of}\:{them}\:{is}\:\mathrm{21},\:{find}\:{the}\:{tow}\: \\ $$$${figures}? \\ $$ Commented by Davidtim last updated on 30/Jan/24…