Question Number 202187 by sonukgindia last updated on 22/Dec/23 Commented by mr W last updated on 22/Dec/23 $${is}\:{AB}={AC}\:? \\ $$ Commented by AST last updated…
Question Number 202143 by otchereabdullai@gmail.com last updated on 21/Dec/23 $$\:{find}\:{x}\:{in}\:{the}\:{interval}\:\:\mathrm{0}°<{x}<\mathrm{360}°\:{if} \\ $$$$\:\:{f}\left({x}\right)=\:\mathrm{6}{sinx}\:{is}\:−\mathrm{12} \\ $$ Commented by otchereabdullai@gmail.com last updated on 22/Dec/23 $${answer}\:{in}\:{the}\:{book}\:{is}\:\mathrm{210}°\:{and}\:\mathrm{330}°\: \\ $$$${but}\:{i}\:{dont}\:{know}\:{how}\:\:{he}\:{come}\:{about}\: \\…
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Question Number 202100 by sonukgindia last updated on 20/Dec/23 Answered by mr W last updated on 21/Dec/23 $${f}'={g} \\ $$$${f}''={g}'={f} \\ $$$${f}''−{f}=\mathrm{0} \\ $$$${r}^{\mathrm{2}} −\mathrm{1}=\mathrm{0}\:\Rightarrow{r}=\pm\mathrm{1}…
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Question Number 202093 by sonukgindia last updated on 20/Dec/23 Commented by a.lgnaoui last updated on 22/Dec/23 Commented by a.lgnaoui last updated on 22/Dec/23 $$\Delta\mathrm{AMN}\:\:\measuredangle\:\mathrm{MNA}=\frac{\mathrm{3}\pi}{\mathrm{4}}−\alpha \\…
Question Number 202094 by otchereabdullai@gmail.com last updated on 20/Dec/23 $$\:{A}\:{computer}\:{systerm}\:{has}\:{a}\:{memory}\: \\ $$$$\:\:{leak}\:{issue}\:{causing}\:{its}\:{usage}\:{to} \\ $$$$\:\:{increase}\:{over}\:{time}.\:{the}\:{rate}\:{of}\: \\ $$$$\:\:{memory}\:{usage}\:{growth}\:{is}\:{directly}\: \\ $$$$\:\:{proportional}\:{to}\:{the}\:{difference}\: \\ $$$$\:\:{between}\:{the}\:{current}\:{memory}\:{usage}\: \\ $$$$\:{and}\:{the}\:{systerms}\:{maximum}\:{memory} \\ $$$$\:\:{capacity}.\:{Write}\:{one}\:{ODE}\:{and}\:{one}\: \\…
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Question Number 202039 by sonukgindia last updated on 19/Dec/23 Answered by mr W last updated on 19/Dec/23 Commented by mr W last updated on 19/Dec/23…
Question Number 202034 by cortano12 last updated on 19/Dec/23 Answered by MM42 last updated on 19/Dec/23 $${if}\:\frac{\mathrm{7}}{\mathrm{3}}<{a}<\frac{\mathrm{7}}{\mathrm{2}}\Rightarrow\lfloor\frac{\mathrm{7}}{{a}}\rfloor+\lfloor\frac{{a}}{\mathrm{7}}\rfloor=\mathrm{2} \\ $$$${if}\:\:\:\mathrm{14}<{a}<\mathrm{21}\Rightarrow\lfloor\frac{\mathrm{7}}{{a}}\rfloor+\lfloor\frac{{a}}{\mathrm{7}}\rfloor=\mathrm{2} \\ $$$$ \\ $$ Terms of…