Question Number 44810 by jasno91 last updated on 05/Oct/18 Answered by Kunal12588 last updated on 05/Oct/18 $$\left(\mathrm{6}{x}\right)^{\mathrm{2}} −\mathrm{2}\left(\mathrm{6}{x}\right)\left(\mathrm{5}{y}\right)+\left(\mathrm{5}{y}\right)^{\mathrm{2}} =\left(\mathrm{6}{x}−\mathrm{5}{y}\right)^{\mathrm{2}} \\ $$$$\left(\mathrm{4}−\mathrm{1}\right)^{\mathrm{2}} =\mathrm{9} \\ $$ Terms…
Question Number 44807 by jasno91 last updated on 05/Oct/18 Answered by Kunal12588 last updated on 05/Oct/18 $$\left({a}+{b}\right)^{\mathrm{2}} ={a}^{\mathrm{2}} +\mathrm{2}{ab}+{b}^{\mathrm{2}} \\ $$$$\mathrm{1}.\:\left(\mathrm{50}+\mathrm{4}\right)^{\mathrm{2}} =\mathrm{2500}+\mathrm{16}+\mathrm{400}=\mathrm{2916} \\ $$$$\mathrm{2}.\:\left(\mathrm{80}+\mathrm{2}\right)^{\mathrm{2}} =\mathrm{6400}+\mathrm{4}+\mathrm{320}=\mathrm{6734}…
Question Number 44808 by jasno91 last updated on 05/Oct/18 Commented by Kunal12588 last updated on 05/Oct/18 $${read}\:{some}\:{books} \\ $$ Answered by Kunal12588 last updated on…
Question Number 44806 by jasno91 last updated on 05/Oct/18 Answered by Kunal12588 last updated on 05/Oct/18 $${let}\:{the}\:{numbers}\:{be}\:{x}\:{and}\:{y} \\ $$$${x}:{y}=\mathrm{3}:\mathrm{5} \\ $$$$\Rightarrow\frac{{x}}{{y}}=\frac{\mathrm{3}}{\mathrm{5}}\Rightarrow{x}=\frac{\mathrm{3}{y}}{\mathrm{5}}\:\:\:….\left(\mathrm{1}\right) \\ $$$$\left({x}+\mathrm{10}\right):\left({y}+\mathrm{10}\right)=\mathrm{5}:\mathrm{7} \\ $$$$\Rightarrow{x}=\frac{\mathrm{5}}{\mathrm{7}}\left({y}+\mathrm{10}\right)−\mathrm{10}\:\left(\mathrm{2}\right)…
Question Number 44805 by jasno91 last updated on 05/Oct/18 Answered by Kunal12588 last updated on 05/Oct/18 $${let}\:{the}\:{numbers}\:{be}\:{a},{b},{c} \\ $$$${a}:{b}:{c}=\mathrm{4}:\mathrm{5}:\mathrm{6} \\ $$$${let}\:{a}=\mathrm{4}{x},\:{b}=\mathrm{5}{x},\:{c}=\mathrm{6}{x} \\ $$$${here}\:\mathrm{6}{x}>\mathrm{5}{x}>\mathrm{4}{x} \\ $$$$\therefore\:\mathrm{6}{x}+\mathrm{4}{x}=\mathrm{5}{x}+\mathrm{55}…
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Question Number 175821 by daus last updated on 07/Sep/22 Commented by daus last updated on 07/Sep/22 $${help}\:{me}\:{for}\:{a} \\ $$ Answered by Rasheed.Sindhi last updated on…
Question Number 110288 by mathdave last updated on 28/Aug/20 Answered by bemath last updated on 28/Aug/20 $$\:\:\:\:\:\Delta\frac{{be}}{{math}}\bigtriangledown \\ $$$${let}\:{y}\:=\:{vx}\:\Rightarrow{dy}={v}\:{dx}+\:{x}\:{dv} \\ $$$$\Leftrightarrow\left(\mathrm{4}{vx}−\mathrm{2}{x}\right){dx}=\left({x}+{vx}\right)\left({v}\:{dx}+{x}\:{dv}\right) \\ $$$$\left(\mathrm{4}{v}−\mathrm{2}\right){dx}=\left(\mathrm{1}+{v}\right)\left({v}\:{dx}\:+\:{x}\:{dv}\:\right) \\ $$$$\left(\mathrm{4}{v}−\mathrm{2}\right){dx}=\left({v}+{v}^{\mathrm{2}}…
Question Number 110287 by mathdave last updated on 28/Aug/20 Commented by bemath last updated on 28/Aug/20 $$\mathrm{sin}^{−\mathrm{1}} \left(\mathrm{5}\right)=\frac{\pi}{\mathrm{2}}−\mathrm{cos}^{−\mathrm{1}} \left(\mathrm{5}\right) \\ $$$$\mathrm{sin}\:\left(\mathrm{sin}^{−\mathrm{1}} \left(\mathrm{5}\right)\right)=\mathrm{sin}\:\left(\frac{\pi}{\mathrm{2}}−\mathrm{cos}^{−\mathrm{1}} \left(\mathrm{5}\right)\right) \\ $$$$\Rightarrow\:\mathrm{5}\:=\:\mathrm{cos}\:\left(\mathrm{cos}^{−\mathrm{1}}…
Question Number 110286 by mathdave last updated on 28/Aug/20 Answered by mathmax by abdo last updated on 28/Aug/20 $$\mathrm{f}\left(\mathrm{a}\right)\:=\mathrm{ln}\left(\mathrm{a}\right)\int\:\frac{\mathrm{a}^{\mathrm{3x}} −\mathrm{1}}{\mathrm{a}^{\mathrm{2x}} +\mathrm{1}}\mathrm{dx}\:\:\mathrm{changement}\:\mathrm{a}^{\mathrm{x}} \:=\mathrm{t}\:\mathrm{give}\:\mathrm{e}^{\mathrm{xln}\left(\mathrm{a}\right)} \:=\mathrm{t}\:\Rightarrow \\ $$$$\mathrm{xln}\left(\mathrm{a}\right)\:=\mathrm{ln}\left(\mathrm{t}\right)\:\Rightarrow\mathrm{x}\:=\frac{\mathrm{ln}\left(\mathrm{t}\right)}{\mathrm{lna}}\:\Rightarrow\mathrm{f}\left(\mathrm{a}\right)\:=\mathrm{ln}\left(\mathrm{a}\right)\int\:\frac{\mathrm{t}^{\mathrm{3}}…