Question Number 175302 by dianapretty last updated on 26/Aug/22 Answered by Joe905 last updated on 26/Aug/22 $$\left(\mathrm{3}{x}+\mathrm{10}\right)+\left(\mathrm{7}{x}−\mathrm{50}\right)=\mathrm{180} \\ $$$$\mathrm{10}{x}−\mathrm{40}=\mathrm{180} \\ $$$$\mathrm{10}{x}=\mathrm{220} \\ $$$${x}=\mathrm{22} \\ $$…
Question Number 175297 by zzzrot last updated on 26/Aug/22 Answered by Rasheed.Sindhi last updated on 26/Aug/22 $$\left(\mathrm{3}{x}−\mathrm{3}\right)+\left(\mathrm{6}{x}+\mathrm{10}\right)+\left(\mathrm{2}{x}−\mathrm{4}\right)+\left(\mathrm{4}{x}−\mathrm{18}\right)=\mathrm{360} \\ $$$$\mathrm{15}{x}−\mathrm{15}=\mathrm{360} \\ $$$${x}=\frac{\mathrm{360}+\mathrm{15}}{\mathrm{15}}=\frac{\mathrm{375}}{\mathrm{15}}=\mathrm{25}° \\ $$ Terms of…
Question Number 175294 by zzzrot last updated on 26/Aug/22 Answered by Rasheed.Sindhi last updated on 26/Aug/22 $${In}\:{triangle}: \\ $$$${a}:{the}\:{opposite}\:{side}\:{to}\:{the}\:{angle}\:{of} \\ $$$${measure}\:\mathrm{30}. \\ $$$${c}\::\:{hypotenuse}=\mathrm{2}{a} \\ $$$${a}^{\mathrm{2}}…
Question Number 109750 by mathdave last updated on 25/Aug/20 Answered by 1549442205PVT last updated on 28/Aug/20 $$\mathrm{x}^{\mathrm{6}} +\mathrm{27}=\left(\mathrm{x}^{\mathrm{2}} \right)^{\mathrm{3}} +\mathrm{3}^{\mathrm{3}} =\left(\mathrm{x}^{\mathrm{2}} +\mathrm{3}\right)\left(\mathrm{x}^{\mathrm{4}} −\mathrm{3x}^{\mathrm{2}} +\mathrm{9}\right) \\…
Question Number 175285 by MathsFan last updated on 26/Aug/22 $$\mathrm{simplfy} \\ $$$$\:\boldsymbol{\mathrm{sinh}}\left(\boldsymbol{\mathrm{log}}\mathrm{2}\right) \\ $$ Answered by MJS_new last updated on 26/Aug/22 $$\mathrm{sinh}\:{x}\:=\frac{\mathrm{e}^{{x}} −\mathrm{e}^{−{x}} }{\mathrm{2}} \\…
Question Number 44214 by 12344 last updated on 23/Sep/18 $$\mathrm{find}\:\mathrm{x}\:\mathrm{inthe}\:\mathrm{eqn}. \\ $$$$\mathrm{3}^{\mathrm{x}} −\mathrm{1}=\mathrm{x}^{\mathrm{3}} \\ $$ Answered by MJS last updated on 23/Sep/18 $$\mathrm{two}\:\mathrm{solutions}\:\mathrm{are}\:\mathrm{obvious} \\ $$$${x}=\mathrm{0}…
Question Number 109749 by mathdave last updated on 25/Aug/20 Answered by 1549442205PVT last updated on 26/Aug/20 $$\mathrm{By}\:\mathrm{obtained}\:\mathrm{result}\:\mathrm{above}\:\mathrm{we}\:\mathrm{have} \\ $$$$\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{\mathrm{324}}{\mathrm{x}^{\mathrm{6}} +\mathrm{27}}\mathrm{dx}=\int_{\mathrm{0}} ^{\:\mathrm{1}} \:\left(\frac{\mathrm{12}}{\left(\mathrm{x}^{\mathrm{2}} +\mathrm{3}\right)}+\frac{\mathrm{6}\left(\mathrm{x}+\mathrm{2}\right)}{\mathrm{x}^{\mathrm{2}}…
Question Number 175280 by naka3546 last updated on 26/Aug/22 $$\mathrm{A}\:\mathrm{biology}\:\:\mathrm{class}\:\mathrm{at}\:\mathrm{central}\:\:\mathrm{high}\:\:\mathrm{school} \\ $$$$\mathrm{predicted}\:\:\mathrm{that}\:\:\mathrm{a}\:\:\mathrm{local}\:\:\mathrm{population}\:\:\mathrm{of}\:\:\:\mathrm{animals} \\ $$$$\mathrm{will}\:\:\mathrm{double}\:\:\mathrm{in}\:\:\mathrm{size}\:\:\mathrm{every}\:\:\mathrm{12}\:\:\mathrm{years}. \\ $$$$\mathrm{The}\:\:\mathrm{population}\:\:\mathrm{at}\:\:\mathrm{the}\:\:\mathrm{beginning}\:\:\mathrm{of}\:\:\mathrm{2014} \\ $$$$\mathrm{was}\:\:\mathrm{estimated}\:\:\mathrm{to}\:\mathrm{be}\:\:\mathrm{50}\:\:\mathrm{animals}. \\ $$$$\mathrm{If}\:\:{P}\:\:\mathrm{represents}\:\:\mathrm{the}\:\:\mathrm{population}\:\:{n}\:\:\mathrm{years}\:\:\mathrm{after}\:\:\mathrm{2014}. \\ $$$$\mathrm{Find}\:\:\mathrm{the}\:\:\mathrm{equations}\:\:\mathrm{represents}\:\:\mathrm{the}\:\:\mathrm{class}\:\:\mathrm{model} \\ $$$$\mathrm{of}\:\:\mathrm{the}\:\:\mathrm{population}\:\:\mathrm{over}\:\:\mathrm{time}? \\…
Question Number 175279 by naka3546 last updated on 26/Aug/22 $$\mathrm{Find}\:\:\mathrm{the}\:\:\mathrm{angle}\:\:\mathrm{between}\:\:\mathrm{the}\:\:\mathrm{lines} \\ $$$${r}\:=\:\begin{pmatrix}{\mathrm{1}}\\{\mathrm{0}}\\{\mathrm{4}}\end{pmatrix}\:\:+\:\lambda\begin{pmatrix}{\mathrm{2}}\\{−\mathrm{1}}\\{−\mathrm{1}}\end{pmatrix} \\ $$$${r}\:=\:\begin{pmatrix}{\mathrm{1}}\\{\mathrm{0}}\\{\mathrm{4}}\end{pmatrix}\:\:+\:\lambda\begin{pmatrix}{\mathrm{3}}\\{\mathrm{0}}\\{\mathrm{1}}\end{pmatrix} \\ $$$$ \\ $$ Answered by mahdipoor last updated on 26/Aug/22…
Question Number 109738 by Khalmohmmad last updated on 25/Aug/20 $$\frac{\frac{\mathrm{x}}{\mathrm{y}}−\frac{\mathrm{y}}{\mathrm{x}}}{\frac{\mathrm{x}^{\mathrm{2}} +\mathrm{2xy}+\mathrm{y}^{\mathrm{2}} }{\mathrm{x}^{\mathrm{2}} −\mathrm{y}^{\mathrm{2}} }}=\frac{\mathrm{9}}{\mathrm{4}} \\ $$$$\frac{\mathrm{x}}{\mathrm{y}}=? \\ $$ Commented by nimnim last updated on 25/Aug/20…