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Question-109606

Question Number 109606 by mathdave last updated on 24/Aug/20 Commented by malwan last updated on 24/Aug/20 $${What}\:{do}\:{you}\:{do}\:{sir}\:? \\ $$$${You}\:{post}\:{the}\:{solution}\:{as}\:{question} \\ $$$${and}\:??\:{where}\:{is}\:{the}\:{final}\:{result}?? \\ $$ Commented by…

Question-44068

Question Number 44068 by peter frank last updated on 21/Sep/18 Answered by kunal1234523 last updated on 21/Sep/18 $${join}\:{OB}\:{and}\:{OD}\:={R} \\ $$$${l}^{\mathrm{2}} +{x}^{\mathrm{2}} ={R}^{\mathrm{2}} \:\:\:\:…..\left(\mathrm{1}\right) \\ $$$${h}^{\mathrm{2}}…

Question-109605

Question Number 109605 by mathdave last updated on 24/Aug/20 Commented by Rasheed.Sindhi last updated on 24/Aug/20 $${mathdave}\:{sir}, \\ $$$$\mathcal{T}{he}\:{space}\:{in}\:{which}\:{you}\:{have} \\ $$$${written}\:{solution}\:\left({of}\:{an}\:{unknown}\right. \\ $$$$\left.{question}\right)\:{is}\:{specified}\:{for} \\ $$$$\boldsymbol{{asking}}\:\boldsymbol{{question}}.{Please}\:{don}'{t}…

o-hans-1-x-x-1-4-1-4-2-a-1-b-2-c-3-a-b-90-b-c-60-a-c-120-then-a-b-c-3-x-log-

Question Number 109584 by bobhans last updated on 24/Aug/20 $$\:\:\:\frac{−\flat{o}\flat−}{{hans}} \\ $$$$\left(\mathrm{1}\right)\sqrt{{x}−\sqrt{{x}−\frac{\mathrm{1}}{\mathrm{4}}}}\:\geqslant\:\frac{\mathrm{1}}{\mathrm{4}} \\ $$$$\left(\mathrm{2}\right)\mid\overset{\rightarrow} {{a}}\mid\:=\:\mathrm{1},\:\mid\overset{\rightarrow} {{b}}\mid\:=\:\mathrm{2}\:,\:\mid\overset{\rightarrow} {{c}}\mid=\mathrm{3}\:,\:\angle\left(\overset{\rightarrow} {{a}},\overset{\rightarrow} {{b}}\right)=\mathrm{90}° \\ $$$$\:\:\:\:\:\:\:\:\angle\left(\overset{\rightarrow} {{b}},\overset{\rightarrow} {{c}}\right)=\mathrm{60}°\:,\:\angle\left(\overset{\rightarrow} {{a}},\overset{\rightarrow} {{c}}\right)=\mathrm{120}°\:,\:{then}\:…

x-3-x-2-x-c-0-find-x-

Question Number 175095 by Gbenga last updated on 18/Aug/22 $$\boldsymbol{\mathrm{x}}^{\mathrm{3}} +\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{c}}=\mathrm{0} \\ $$$$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{x}} \\ $$ Answered by MJS_new last updated on 18/Aug/22 $${x}={z}−\frac{\mathrm{1}}{\mathrm{3}} \\…