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Question-109453

Question Number 109453 by mathdave last updated on 23/Aug/20 Answered by mathmax by abdo last updated on 23/Aug/20 $$\mathrm{I}\:=\int_{\mathrm{0}} ^{\mathrm{4}\pi} \mid\mathrm{cosx}\mid\:\mathrm{dx}\:\Rightarrow\:\mathrm{I}\:=_{\mathrm{x}\:=\mathrm{t}+\mathrm{2}\pi} \:\:\:\:\int_{−\mathrm{2}\pi} ^{\mathrm{2}\pi} \mid\mathrm{cost}\mid\:\mathrm{dt}\: \\…

Question-174982

Question Number 174982 by MikeH last updated on 15/Aug/22 Answered by Rasheed.Sindhi last updated on 15/Aug/22 $${a}+{b}\leqslant\mathrm{9}\:\wedge\:\underset{\left({i}\right)} {\underbrace{{a}\geqslant\mathrm{2}}}\:\wedge\:\underset{\left({ii}\right)} {\underbrace{{b}\geqslant−\mathrm{2}}} \\ $$$$\left({ii}\right)−\left({i}\right)\Rightarrow\:\:{b}−{a}\geqslant−\mathrm{2}−\mathrm{2}=−\mathrm{4} \\ $$$${Minimum}\:{value}\:{of}\:{b}−{a}\:{is}\:−\mathrm{4} \\ $$…

Question-174975

Question Number 174975 by sciencestudent last updated on 15/Aug/22 Answered by MikeH last updated on 15/Aug/22 $${R}_{\mathrm{1}} +{R}_{\mathrm{2}} \:=\:\mathrm{690}\:\mathrm{or}\:{x}+{y}\:=\:\mathrm{690}…..\left(\mathrm{1}\right) \\ $$$$\frac{{xy}}{{x}+{y}}\:=\:\mathrm{150} \\ $$$$\Rightarrow\:\frac{{xy}}{\mathrm{690}}\:=\:\mathrm{150}\:\Rightarrow\:{xy}\:=\:\mathrm{103500}\: \\ $$$$\mathrm{from}\:\left(\mathrm{1}\right)\:{x}\:=\:\mathrm{690}−{y}…

Question-174974

Question Number 174974 by sciencestudent last updated on 15/Aug/22 Answered by MikeH last updated on 15/Aug/22 $$\mathrm{total}\:\mathrm{resistance}\:=\:\mathrm{2}.\mathrm{0}\:+\:\mathrm{14}.\mathrm{0}\:+\:\mathrm{9}.\mathrm{5}\:=\:\mathrm{25}.\mathrm{5}\:\Omega \\ $$$$\mathrm{but}\:{V}\:=\:{IR}\:\Rightarrow\:{I}\:=\:\frac{{V}}{{R}}\:=\:\frac{\mathrm{9}.\mathrm{0}}{\mathrm{25}.\mathrm{5}}\:=\:\mathrm{0}.\mathrm{35}\:\mathrm{A} \\ $$$$\mathrm{now}\:\mathrm{transversing}\:\mathrm{the}\:\mathrm{circuit}, \\ $$$$\mathrm{9}.\mathrm{5}\left(\mathrm{0}.\mathrm{35}\right)\:+\:\mathrm{14}\left(\mathrm{0}.\mathrm{35}\right)+\mathrm{2}.\mathrm{0}\left(\mathrm{0}.\mathrm{35}\right)−\mathrm{9}.\mathrm{0}\:\approx\:\mathrm{0}.\mathrm{0}{V} \\ $$…

Question-174963

Question Number 174963 by MikeH last updated on 14/Aug/22 Commented by thfchristopher last updated on 15/Aug/22 $$\mathrm{But}\:\mathrm{there}\:\mathrm{is}\:\mathrm{no}\:\mathrm{such}\:\mathrm{option}\:\mathrm{for}\:\mathrm{7}.\mathrm{31}… \\ $$ Answered by a.lgnaoui last updated on…