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Question-174767

Question Number 174767 by Best1 last updated on 10/Aug/22 Answered by Ar Brandon last updated on 10/Aug/22 $$\mathrm{60}+\frac{\mathrm{1}}{\mathrm{3}}\left(\mathrm{60}+\mathrm{60}\right)+\frac{\mathrm{1}}{\mathrm{9}}\left(\mathrm{60}+\mathrm{60}\right)+\frac{\mathrm{1}}{\mathrm{27}}\left(\mathrm{60}+\mathrm{60}\right)+\frac{\mathrm{1}}{\mathrm{81}}\left(\mathrm{60}+\mathrm{60}\right) \\ $$$$=\mathrm{60}+\frac{\mathrm{120}}{\mathrm{3}}+\frac{\mathrm{120}}{\mathrm{9}}+\frac{\mathrm{120}}{\mathrm{27}}+\frac{\mathrm{120}}{\mathrm{81}} \\ $$$$=\mathrm{119}.\mathrm{2592593}\:\mathrm{m} \\ $$ Terms…

A-graduating-student-keeps-applying-for-a-job-until-she-gets-an-offer-The-probability-of-getting-an-offer-at-any-trial-is-0-35-What-is-the-expected-number-of-applications-

Question Number 174737 by MathsFan last updated on 09/Aug/22 $$\mathrm{A}\:\mathrm{graduating}\:\mathrm{student}\:\mathrm{keeps}\:\mathrm{applying} \\ $$$$\mathrm{for}\:\mathrm{a}\:\mathrm{job}\:\mathrm{until}\:\mathrm{she}\:\mathrm{gets}\:\mathrm{an}\:\mathrm{offer}.\:\mathrm{The} \\ $$$$\mathrm{probability}\:\mathrm{of}\:\mathrm{getting}\:\mathrm{an}\:\mathrm{offer}\:\mathrm{at}\:\mathrm{any} \\ $$$$\mathrm{trial}\:\mathrm{is}\:\mathrm{0}.\mathrm{35}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{expected}\: \\ $$$$\mathrm{number}\:\mathrm{of}\:\mathrm{applications}? \\ $$ Answered by aleks041103 last updated…