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Solve-log-3-y-2-log-y-y-5-2-

Question Number 108674 by ZiYangLee last updated on 18/Aug/20 $$\mathrm{Solve}\:\:\mathrm{log}_{\mathrm{3}} \left(\mathrm{y}−\mathrm{2}\right)+\mathrm{log}_{\mathrm{y}} \left(\mathrm{y}+\mathrm{5}\right)=\mathrm{2} \\ $$ Answered by bshahid010 last updated on 18/Aug/20 $${i}\:{think}\:{no}\:{solution} \\ $$ Commented…

Question-174214

Question Number 174214 by Best1 last updated on 27/Jul/22 Answered by mr W last updated on 27/Jul/22 $${x}^{\mathrm{2}} +{y}^{\mathrm{2}} ={l}^{\mathrm{2}} \\ $$$$\mathrm{2}{x}\frac{{dx}}{{dt}}+\mathrm{2}{y}\frac{{dy}}{{dt}}=\mathrm{0} \\ $$$$\Rightarrow\frac{{dx}}{{dt}}=−\frac{{y}}{{x}}×\frac{{dy}}{{dt}} \\…

what-is-the-range-of-the-inverse-the-relation-x-y-y-4-x-1-

Question Number 174193 by Best1 last updated on 26/Jul/22 $${what}\:{is}\:{the}\:{range}\:{of}\:{the}\:{inverse}\: \\ $$$${the}\:{relation}\:\left\{\left({x},{y}\right):{y}=\sqrt{\mathrm{4}−\mid{x}−\mathrm{1}\mid}\right\}??? \\ $$ Commented by cortano1 last updated on 27/Jul/22 $$\:\:{y}=\sqrt{\mathrm{4}−\mid{x}−\mathrm{1}\mid}\:;\:\mathrm{4}−\mid{x}−\mathrm{1}\mid\:\geqslant\mathrm{0} \\ $$$$\:\:\mid{x}−\mathrm{1}\mid\leqslant\mathrm{4}\Rightarrow−\mathrm{3}\leqslant{x}\leqslant\mathrm{5} \\…

Question-174194

Question Number 174194 by mokys last updated on 26/Jul/22 Answered by Mathspace last updated on 27/Jul/22 $$\left.\mathrm{1}\right)\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} {sin}^{\mathrm{10}} {x}\:{cos}^{\mathrm{10}} {x}\:{dx} \\ $$$${we}\:{kmow}\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} {sin}^{\mathrm{2}{p}−\mathrm{1}}…

intgrate-x-2-cos-x-2-4x-dx-

Question Number 174191 by Best1 last updated on 26/Jul/22 $$\:\:\:\:\:{intgrate}\:\int\left({x}+\mathrm{2}\right){cos}\left({x}^{\mathrm{2}} +\mathrm{4}{x}\right){dx}? \\ $$ Commented by mokys last updated on 26/Jul/22 $$=\:\frac{\mathrm{1}}{\mathrm{2}}\:{sin}\left({x}^{\mathrm{2}} +\mathrm{4}{x}\right)+{c} \\ $$ Commented…

Question-174190

Question Number 174190 by Best1 last updated on 26/Jul/22 Answered by MikeH last updated on 26/Jul/22 $$\left(\mathrm{19}\right)\:−{x}+\mathrm{2}{y}−\mathrm{1}=\mathrm{0} \\ $$$$\Rightarrow{d}\:=\:\mid\frac{−\left(\mathrm{2}\right)+\mathrm{2}\left(\mathrm{1}\right)−\mathrm{1}}{\:\sqrt{\left(−\mathrm{1}\right)^{\mathrm{2}} +\left(\mathrm{2}\right)^{\mathrm{2}} }}\mid\:=\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{5}}}\:=\:\frac{\sqrt{\mathrm{5}}}{\mathrm{5}} \\ $$ Terms of…

Question-108637

Question Number 108637 by mathdave last updated on 18/Aug/20 Answered by bemath last updated on 18/Aug/20 $$\:\:\:\frac{\angle{bemath}\angle}{\multimap} \\ $$$$\int\:{dx}\:+\:\int\:\frac{\mathrm{2}{dx}}{\left({x}−\mathrm{3}\right)}+\int\:\frac{\mathrm{3}{dx}}{{x}−\mathrm{2}}= \\ $$$${x}\:+\mathrm{2ln}\:\mid{x}−\mathrm{3}\mid+\mathrm{3ln}\:\mid{x}−\mathrm{2}\mid+\:{C} \\ $$ Answered by…