Question Number 107941 by mohammad17 last updated on 13/Aug/20 Commented by kaivan.ahmadi last updated on 13/Aug/20 $$\frac{\partial\theta}{\partial{t}}={nt}^{{n}−\mathrm{1}} {e}^{\frac{−{r}^{\mathrm{2}} }{\mathrm{2}{t}}} +{t}^{{n}} \frac{{r}^{\mathrm{2}} }{\mathrm{2}{t}^{\mathrm{2}} }{e}^{\frac{−{r}^{\mathrm{2}} }{\mathrm{2}{t}}} =\left({nt}^{{n}−\mathrm{1}}…
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Question Number 107926 by mohammad17 last updated on 13/Aug/20 Answered by Aziztisffola last updated on 13/Aug/20 $$\mathrm{True} \\ $$ Answered by Aziztisffola last updated on…
Question Number 107924 by mohammad17 last updated on 13/Aug/20 Answered by Aziztisffola last updated on 13/Aug/20 $$\mathrm{True} \\ $$ Commented by mohammad17 last updated on…
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Question Number 107922 by mohammad17 last updated on 13/Aug/20 $${if}:\:{y}=\frac{{x}}{{x}^{\mathrm{2}} +\mathrm{1}}\:{then}\:{find}\:\frac{{d}\sqrt{{y}}}{{d}\sqrt{{x}}}\:? \\ $$ Answered by 1549442205PVT last updated on 13/Aug/20 $$\mathrm{Set}\:\sqrt{\mathrm{x}}\:=\mathrm{t}\:\mathrm{and}\:\sqrt{\mathrm{y}}=\mathrm{z}\Rightarrow\mathrm{y}=\frac{\mathrm{t}^{\mathrm{2}} }{\mathrm{t}^{\mathrm{4}} +\mathrm{1}} \\ $$$$\mathrm{z}^{\mathrm{2}}…
Question Number 107925 by mohammad17 last updated on 13/Aug/20 Answered by Aziztisffola last updated on 13/Aug/20 $$\mathrm{True}\:\mathrm{by}\:\mathrm{lagrange}\:\mathrm{theorem}\: \\ $$$$\:\mathrm{The}\:\mathrm{order}\:\mathrm{than}\:\mathrm{subgroup}\:\mathrm{H}\:\mathrm{of}\:\mathrm{G}\:\mathrm{divides} \\ $$$$\:\mathrm{the}\:\mathrm{order}\:\mathrm{of}\:\mathrm{G}\:\mathrm{then}\:\mathrm{if}\:\mathrm{the}\:\mathrm{order}\:\mathrm{than} \\ $$$$\mathrm{element}\:\mathrm{h}\:\mathrm{in}\:\mathrm{H}\:\mathrm{divides}\:\mathrm{the}\:\mathrm{order}\:\mathrm{of}\:\mathrm{H} \\ $$$$\:\mathrm{hence}\:\mid\mathrm{h}\mid\:\mathrm{divides}\:\mid\mathrm{G}\mid.…
Question Number 173401 by DAVONG last updated on 11/Jul/22 $$\mathrm{1}.\mathrm{show}\:\mathrm{that}\:\underset{\mathrm{n}\rightarrow+\propto} {\mathrm{lim}}\frac{\mathrm{2}^{\mathrm{2022}} \mathrm{n}^{\mathrm{2}} }{\mathrm{3}^{\mathrm{n}} }=\mathrm{0}\:? \\ $$ Commented by alephzero last updated on 11/Jul/22 $$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\frac{\mathrm{2}^{\mathrm{2022}}…
Question Number 107852 by mathdave last updated on 12/Aug/20 Answered by hgrocks last updated on 13/Aug/20 $$\:\mathrm{I}\:=\:\int\:\underset{\mathrm{k}=\mathrm{1}} {\overset{\infty} {\sum}}\left(\frac{\mathrm{x}−\mathrm{1}}{\mathrm{x}}\right)^{\mathrm{k}} \frac{\mathrm{1}}{\mathrm{k}}\:\mathrm{dx} \\ $$$$\:\:\:\:=\:\int−\mathrm{ln}\left(\mathrm{1}−\frac{\mathrm{x}−\mathrm{1}}{\mathrm{x}}\right)\:\mathrm{dx} \\ $$$$\:\:\:\:=\:\int\mathrm{lnx}\:\mathrm{dx} \\…
Question Number 42315 by mondodotto@gmail.com last updated on 23/Aug/18 $$\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{point}}\:\left(\mathrm{2},−\mathrm{1}\right)\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{reflected}}\: \\ $$$$\boldsymbol{\mathrm{in}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{line}}\:\:\boldsymbol{{x}}=\mathrm{4}\:\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{the}} \\ $$$$\boldsymbol{\mathrm{image}}\:\boldsymbol{\mathrm{point}}. \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 23/Aug/18 Answered by…