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Question-107279

Question Number 107279 by mathdave last updated on 09/Aug/20 Commented by Dwaipayan Shikari last updated on 10/Aug/20 $$\mathrm{As}\:\mathrm{x}\rightarrow\mathrm{0} \\ $$$$\mathrm{tanx}\rightarrow\mathrm{x} \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\frac{\mathrm{x}^{\mathrm{x}^{\mathrm{x}^{\mathrm{x}^{\mathrm{x}^{\mathrm{x}^{} } }…

Question-107272

Question Number 107272 by mathocean1 last updated on 09/Aug/20 Answered by Dwaipayan Shikari last updated on 09/Aug/20 $$\left(\mathrm{3}+\mathrm{8}\right).\mathrm{4} \\ $$$$\left(\mathrm{9}+\mathrm{7}\right).\mathrm{2} \\ $$$$\left(\mathrm{8}+\mathrm{7}\right).\mathrm{5} \\ $$$$\mathrm{Answer}\:\mathrm{is}\:\mathrm{5} \\…

Tank-T-1-and-T-2-initially-contains-100gal-of-water-each-In-T-1-the-water-is-pure-whereas-150lb-of-fertilizer-are-dissolved-in-T-2-By-circulating-liquid-at-a-rate-of-1gal-min-and-stirring-the-amou

Question Number 41726 by Necxx last updated on 11/Aug/18 $${Tank}\:{T}_{\mathrm{1}} \:{and}\:{T}_{\mathrm{2}} \:{initially}\:{contains} \\ $$$$\mathrm{100}{gal}\:{of}\:{water}\:{each}.{In}\:{T}_{\mathrm{1}} \:{the} \\ $$$${water}\:{is}\:{pure},{whereas}\:\mathrm{150}{lb}\:{of} \\ $$$${fertilizer}\:{are}\:{dissolved}\:{in}\:{T}_{\mathrm{2}} .{By} \\ $$$${circulating}\:{liquid}\:{at}\:{a}\:{rate}\:{of} \\ $$$$\mathrm{1}{gal}/{min}\:{and}\:{stirring}\:{the}\:{amount} \\…

Question-107247

Question Number 107247 by ZiYangLee last updated on 09/Aug/20 Answered by abdomathmax last updated on 09/Aug/20 $$\mathrm{let}\:\mathrm{f}\left(\mathrm{t}\right)\:=\int_{\mathrm{0}} ^{\infty} \:\frac{\mathrm{e}^{−\mathrm{x}} −\mathrm{e}^{−\mathrm{2x}} }{\mathrm{x}}\:\mathrm{e}^{−\mathrm{tx}} \:\mathrm{dx}\:\mathrm{with}\:\mathrm{t}\geqslant\mathrm{0} \\ $$$$\mathrm{we}\:\mathrm{hsve}\:\mathrm{f}^{'} \left(\mathrm{t}\right)\:=−\int_{\mathrm{0}}…

find-the-perpendicular-distance-btn-two-lines-y-2x-3-and-y-3x-1-

Question Number 41699 by mondodotto@gmail.com last updated on 11/Aug/18 $$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{perpendicular}}\:\boldsymbol{\mathrm{distance}}\:\boldsymbol{\mathrm{btn}} \\ $$$$\boldsymbol{\mathrm{two}}\:\boldsymbol{\mathrm{lines}}\:\boldsymbol{{y}}=\mathrm{2}\boldsymbol{{x}}−\mathrm{3} \\ $$$$\boldsymbol{\mathrm{and}}\:\boldsymbol{{y}}=\mathrm{3}\boldsymbol{{x}}−\mathrm{1} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com