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Solve-in-R-3-x-2-2xy-y-2-4z-2-0-3x-2y-z-3-x-2-y-2-3z-2-4xy-yz-x-2y-3z-7-0-

Question Number 107065 by mathocean1 last updated on 08/Aug/20 $${Solve}\:{in}\:\mathbb{R}^{\mathrm{3}} \\ $$$$\begin{cases}{{x}^{\mathrm{2}} +\mathrm{2}{xy}+{y}^{\mathrm{2}} −\mathrm{4}{z}^{\mathrm{2}} =\mathrm{0}}\\{\mathrm{3}{x}−\mathrm{2}{y}+{z}=\mathrm{3}}\end{cases} \\ $$$$\:\:\:\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +\mathrm{3}{z}^{\mathrm{2}} −\mathrm{4}{xy}+{yz}+{x}+\mathrm{2}{y}−\mathrm{3}{z}+\mathrm{7}=\mathrm{0} \\ $$ Answered by Her_Majesty…

Question-107034

Question Number 107034 by mathdave last updated on 08/Aug/20 Commented by kaivan.ahmadi last updated on 08/Aug/20 $$=\frac{\sqrt{\mathrm{2}}\mid{sin}\mathrm{6}\pi\mid}{\:\sqrt{\mathrm{1}−{cos}\pi}}=\frac{\mathrm{0}}{\:\sqrt{\mathrm{1}−\left(−\mathrm{1}\right)}}=\frac{\mathrm{0}}{\:\sqrt{\mathrm{2}}}=\mathrm{0} \\ $$ Commented by kaivan.ahmadi last updated on…

Question-41488

Question Number 41488 by behi83417@gmail.com last updated on 08/Aug/18 Answered by tanmay.chaudhury50@gmail.com last updated on 08/Aug/18 $$\frac{{x}^{\mathrm{2}} }{{a}^{\mathrm{2}} }+\frac{{y}^{\mathrm{2}} }{\left(\frac{{a}^{\mathrm{2}} }{{b}^{\mathrm{2}} }\right)}=\mathrm{1}\:\:\:\:\:\:\:\frac{{x}^{\mathrm{2}} }{\left(\frac{{a}^{\mathrm{2}} }{{b}^{\mathrm{2}} }\right)}+\frac{{y}^{\mathrm{2}}…

ln-1-x-2-dx-

Question Number 172556 by SANOGO last updated on 28/Jun/22 $$\int_{} {ln}\left(\mathrm{1}+{x}^{\mathrm{2}} \right){dx} \\ $$ Answered by floor(10²Eta[1]) last updated on 28/Jun/22 $$\mathrm{u}=\mathrm{ln}\left(\mathrm{1}+\mathrm{x}^{\mathrm{2}} \right)\Rightarrow\mathrm{du}=\frac{\mathrm{2x}}{\mathrm{1}+\mathrm{x}^{\mathrm{2}} } \\…

Question-41479

Question Number 41479 by jasno91 last updated on 08/Aug/18 Answered by tanmay.chaudhury50@gmail.com last updated on 08/Aug/18 $$\mathrm{73}\:{days}=\frac{\mathrm{73}}{\mathrm{365}}=\frac{\mathrm{1}}{\mathrm{5}}{years} \\ $$$${p}=\mathrm{1175} \\ $$$${r}=\mathrm{10\%} \\ $$$${t}=\mathrm{1}+\frac{\mathrm{1}}{\mathrm{5}}=\frac{\mathrm{6}}{\mathrm{5}}{years} \\ $$$${i}=\frac{{ptr}}{\mathrm{100}}=\frac{\mathrm{1175}×\mathrm{6}×\mathrm{10}}{\mathrm{5}×\mathrm{100}}=\frac{\mathrm{235}×\mathrm{6}}{\mathrm{10}}=\frac{\mathrm{47}×\mathrm{3}}{}=\mathrm{141}…