Question Number 106609 by DeepakMahato last updated on 06/Aug/20 $${Prove}\:{that} \\ $$$$\left(\mathrm{1}−{sin}^{\mathrm{2}} \theta\right){sec}^{\mathrm{2}} \theta=\mathrm{1} \\ $$ Commented by mohammad17 last updated on 06/Aug/20 $${when}:\mathrm{1}−{sin}^{\mathrm{2}} \theta={cos}^{\mathrm{2}}…
Question Number 106604 by mohammad17 last updated on 06/Aug/20 Commented by bemath last updated on 06/Aug/20 $$\mathrm{Q4}\left(\mathrm{5}\right)\:\underset{{x}\rightarrow\mathrm{1}/\mathrm{2}} {\mathrm{lim}}\:\frac{\mathrm{6}\sqrt{\mathrm{x}}−\mathrm{6}\sqrt{\mathrm{2x}−\mathrm{1}}}{\mathrm{x}−\mathrm{1}}\:=\:\frac{\frac{\mathrm{6}}{\:\sqrt{\mathrm{2}}}−\mathrm{0}}{−\frac{\mathrm{1}}{\mathrm{2}}} \\ $$$$=\:−\frac{\mathrm{12}}{\:\sqrt{\mathrm{2}}}\:=\:−\mathrm{6}\sqrt{\mathrm{2}}\:\:\:\:\:@\mathrm{bemath}@ \\ $$ Answered by Dwaipayan…
Question Number 106596 by mathdave last updated on 06/Aug/20 Answered by john santu last updated on 06/Aug/20 $$\:\:\:\:\:@\mathrm{JS}@ \\ $$$$\left(\mathrm{2}^{\mathrm{x}} −\mathrm{1}\right)\left(\mathrm{x}+\mathrm{3}\right)\left(\mathrm{x}−\mathrm{1}\right)=\mathrm{0} \\ $$$$\rightarrow\begin{cases}{\left.\mathrm{x}=−\mathrm{3};\:\mathrm{x}=\mathrm{1}\:;\:\mathrm{x}\:=\:\mathrm{0}\:\right\}\:}\end{cases} \\ $$$$…
Question Number 106594 by mathdave last updated on 06/Aug/20 Commented by ShreeRaghav last updated on 06/Aug/20 $${How}\:{to}\:{insert}\:{a}\:{matrix}\:{and}\:{add}\:{rows}\:{and} \\ $$$${columns}\:{in}\:{it}? \\ $$ Commented by prakash jain…
Question Number 106591 by mathdave last updated on 06/Aug/20 Commented by Her_Majesty last updated on 06/Aug/20 $$\infty\:{is}\:{not}\:{a}\:{number} \\ $$$$\underset{{x}\rightarrow\infty} {{lim}x}!\:\neq\sqrt{\mathrm{2}\pi} \\ $$ Commented by mathdave…
Question Number 106572 by DeepakMahato last updated on 06/Aug/20 Commented by Rasheed.Sindhi last updated on 06/Aug/20 $$\:\:\:\:\underset{−} {\:\:\:\:\:\:\:{Still}\:{another}\:{way}\:\:\:\:\:\:\:\:} \\ $$$${Roots}\left({zeros}\right)\:{of}\:{ax}^{\mathrm{2}} +{bx}+{c}=\mathrm{0} \\ $$$${are}: \\ $$$$\:{x}=\frac{−{b}\pm\sqrt{{b}^{\mathrm{2}}…
Question Number 106559 by MessiasAntonii last updated on 05/Aug/20 $${sen}\left(\mathrm{7}\right)= \\ $$ Commented by bobhans last updated on 06/Aug/20 $$\mathrm{cos}\:\left(\mathrm{14}°\right)=\mathrm{1}−\mathrm{2sin}\:^{\mathrm{2}} \left(\mathrm{7}°\right) \\ $$$$\mathrm{sin}\:\left(\mathrm{7}°\right)=\sqrt{\frac{\mathrm{1}−\mathrm{cos}\:\left(\mathrm{14}°\right)}{\mathrm{2}}}\:\smile\overset{\bullet} {\bullet}\smile \\…
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Question Number 106548 by mohammad17 last updated on 05/Aug/20 $${lim}_{{x}\rightarrow{C}} \:\frac{\mathrm{2}{x}+{c}}{{x}−{c}} \\ $$ Answered by Rio Michael last updated on 05/Aug/20 $$\:=\:\mathrm{2} \\ $$ Answered…
Question Number 41003 by mondodotto@gmail.com last updated on 30/Jul/18 $$\boldsymbol{\mathrm{The}}\:\boldsymbol{\mathrm{LCM}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{GCF}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{{x}},\mathrm{18}\:\boldsymbol{\mathrm{and}}\:\mathrm{60} \\ $$$$\boldsymbol{\mathrm{are}}\:\mathrm{360}\:\boldsymbol{\mathrm{and}}\:\mathrm{6}\:\boldsymbol{\mathrm{respectively}}. \\ $$$$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{value}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{{x}} \\ $$ Answered by $@ty@m last updated on 31/Jul/18 $${Let}\:{x}=\mathrm{6}{k} \\…