Question Number 105943 by bachamohamed last updated on 01/Aug/20 $$\:\:\:\:\:\int\boldsymbol{{ln}}\left(\mathrm{1}+\boldsymbol{\alpha}\sqrt{\mathrm{x}^{\mathrm{2}} −\mathrm{1}}\right)\mathrm{dx}=? \\ $$ Answered by Dwaipayan Shikari last updated on 01/Aug/20 $$\int{log}\left(\mathrm{1}+\alpha\sqrt{{x}^{\mathrm{2}} −\mathrm{1}}\right){dx}={I}\left(\alpha\right) \\ $$$${I}^{'}…
Question Number 171455 by mokys last updated on 15/Jun/22 $${find}\:{the}\:{sum}\:{of}\:{z}\:=\:{sinx}\:+\:{sin}\mathrm{2}{x}+{sin}\mathrm{3}{x}+……+{sinnx}\: \\ $$ Commented by mr W last updated on 15/Jun/22 $${z}=\frac{\mathrm{cos}\:\frac{{x}}{\mathrm{2}}−\mathrm{cos}\:\left({n}+\frac{\mathrm{1}}{\mathrm{2}}\right){x}}{\:\mathrm{2}\:\mathrm{sin}\:\frac{{x}}{\mathrm{2}}} \\ $$ Answered by…
Question Number 171448 by Gbenga last updated on 15/Jun/22 $$\int_{\mathrm{0}} ^{\frac{\boldsymbol{\pi}}{\mathrm{2}}} \boldsymbol{\mathrm{x}}\sqrt{\boldsymbol{\mathrm{cos}}\left(\boldsymbol{\mathrm{x}}\right)}\boldsymbol{\mathrm{dx}}\:\:\:\boldsymbol{\mathrm{evaluate}}!!!! \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 171440 by leicianocosta last updated on 15/Jun/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 40366 by mondodotto@gmail.com last updated on 20/Jul/18 $$\boldsymbol{\mathrm{use}}\:\boldsymbol{\mathrm{newton}}\:\boldsymbol{\mathrm{raphson}}\:\boldsymbol{\mathrm{method}} \\ $$$$\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{approximate}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{positive}}\:\boldsymbol{\mathrm{root}} \\ $$$$\boldsymbol{{x}}^{\mathrm{2}} −\mathrm{1}=\mathrm{0}\:\boldsymbol{\mathrm{correct}}\:\boldsymbol{\mathrm{to}}\:\mathrm{4}\:\boldsymbol{\mathrm{decimal}}\:\boldsymbol{\mathrm{places}} \\ $$$$\boldsymbol{\mathrm{perform}}\:\mathrm{3}\:\boldsymbol{\mathrm{iteration}}\:\boldsymbol{\mathrm{only}} \\ $$$$\boldsymbol{\mathrm{setting}}\:\boldsymbol{\mathrm{with}}\:\boldsymbol{{x}}=\mathrm{2} \\ $$ Commented by math khazana…
Question Number 105897 by Tinku Tara last updated on 01/Aug/20 $$\mathrm{App}\:\mathrm{Updates}: \\ $$$$\mathrm{cyrillic}\:\mathrm{alohabets}\:\mathrm{are}\:\mathrm{now}\:\mathrm{available} \\ $$$$\mathrm{in}\:\mathrm{app}.\:\mathrm{Email}\:\mathrm{us}\:\mathrm{for}\:\mathrm{any}\:\mathrm{missing} \\ $$$$\mathrm{conjunctions}. \\ $$ Commented by mr W last updated…
Question Number 105892 by mohammad17 last updated on 01/Aug/20 $${prove}\:{that}\:{sin}\left({x}\right)+{cos}\left({x}\right)=\sqrt{\mathrm{2}}{cos}\left({x}−\frac{\pi}{\mathrm{4}}\right)\:\:? \\ $$ Answered by john santu last updated on 01/Aug/20 $$\mathrm{sin}\:{x}+\mathrm{cos}\:{x}\:=\:{p} \\ $$$$\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\mathrm{sin}\:{x}+\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\mathrm{cos}\:{x}\:=\:\frac{{p}}{\:\sqrt{\mathrm{2}}} \\ $$$$\Rightarrow\:\mathrm{sin}\:\left(\frac{\pi}{\mathrm{4}}\right)\mathrm{sin}\:{x}+\:\mathrm{cos}\:\left(\frac{\pi}{\mathrm{4}}\right)\mathrm{cos}\:{x}…
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Question Number 171421 by mokys last updated on 14/Jun/22 $${Prove}\:{that}\:{arg}\left({e}^{{z}} \right)=\:{Im}\left({z}\right)\:+\:\mathrm{2}{k}\pi\:,{k}=\mathrm{0},\pm\mathrm{1},\pm\mathrm{2},…\sqrt{} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 105885 by mohammad17 last updated on 01/Aug/20 Answered by bemath last updated on 01/Aug/20 $$\mathrm{sin}\:\left({x}\right)+\mathrm{cos}\:\left({x}\right)\:=\:\sqrt{\mathrm{2}}\:\mathrm{cos}\:\left({x}−\frac{\pi}{\mathrm{4}}\right) \\ $$$$\int\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\mathrm{sec}\:\left({x}−\frac{\pi}{\mathrm{4}}\right)\:{dx}\:=\: \\ $$$$\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}\:}\:\mathrm{ln}\:\mid\mathrm{sec}\:\left({x}−\frac{\pi}{\mathrm{4}}\right)+\mathrm{tan}\:\left({x}−\frac{\pi}{\mathrm{4}}\right)\mid+{C} \\ $$$$\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}\:}\mathrm{ln}\:\mid\frac{\sqrt{\mathrm{2}}\:+\mathrm{sin}\:{x}−\mathrm{cos}\:{x}}{\mathrm{sin}\:{x}+\mathrm{cos}\:{x}}\mid\:+{C} \\ $$…