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App-updates-Image-are-saved-as-a-background-task-so-that-you-dont-get-app-not-responding-when-saving-images-Bug-Fix-Background-color-was-ignored-while-sharing-Support-added-for-Ban

Question Number 105725 by Tinku Tara last updated on 31/Jul/20 $$\mathrm{App}\:\mathrm{updates}: \\ $$$$\bullet\:\mathrm{Image}\:\mathrm{are}\:\mathrm{saved}\:\mathrm{as}\:\mathrm{a}\:\mathrm{background} \\ $$$$\:\:\:\mathrm{task}\:\mathrm{so}\:\mathrm{that}\:\mathrm{you}\:\mathrm{dont}\:\mathrm{get}\:\mathrm{app}\:\mathrm{not} \\ $$$$\:\:\:\mathrm{responding}\:\mathrm{when}\:\mathrm{saving}\:\mathrm{images}. \\ $$$$\bullet\:\mathrm{Bug}\:\mathrm{Fix}:\:\mathrm{Background}\:\mathrm{color}\:\mathrm{was}\: \\ $$$$\:\:\:\:\mathrm{ignored}\:\mathrm{while}\:\mathrm{sharing} \\ $$$$\bullet\:\mathrm{Support}\:\mathrm{added}\:\mathrm{for}\:\mathrm{Bangla} \\ $$$$\bullet\:\mathrm{Fixes}\:\mathrm{for}\:\mathrm{crashes}\:\mathrm{reported}.…

Find-a-polynomial-f-x-which-satisfy-the-following-conditions-i-f-x-of-degree-4-ii-x-1-is-a-factor-of-f-x-and-f-x-iii-f-0-3-and-f-0-5-iv-when-f-x-is-divided-by-x-2-the-remain

Question Number 105707 by ZiYangLee last updated on 31/Jul/20 $$\mathrm{Find}\:\mathrm{a}\:\mathrm{polynomial}\:\mathrm{f}\left(\mathrm{x}\right)\:\mathrm{which}\:\mathrm{satisfy} \\ $$$$\mathrm{the}\:\mathrm{following}\:\mathrm{conditions}: \\ $$$$\left.\mathrm{i}\right)\:\mathrm{f}\left(\mathrm{x}\right)\:\mathrm{of}\:\mathrm{degree}\:\mathrm{4} \\ $$$$\left.\mathrm{ii}\right)\:\left(\mathrm{x}−\mathrm{1}\right)\:\mathrm{is}\:\mathrm{a}\:\mathrm{factor}\:\mathrm{of}\:\mathrm{f}\left(\mathrm{x}\right)\:\mathrm{and}\:\mathrm{f}'\left(\mathrm{x}\right) \\ $$$$\left.\mathrm{iii}\right)\:\mathrm{f}\left(\mathrm{0}\right)=\mathrm{3}\:\mathrm{and}\:\mathrm{f}'\left(\mathrm{0}\right)=−\mathrm{5} \\ $$$$\left.\mathrm{iv}\right)\:\mathrm{when}\:\mathrm{f}\left(\mathrm{x}\right)\:\mathrm{is}\:\mathrm{divided}\:\mathrm{by}\:\left(\mathrm{x}−\mathrm{2}\right),\:\mathrm{the} \\ $$$$\:\:\:\:\:\:\:\mathrm{remainder}\:\mathrm{is}\:\mathrm{13}. \\ $$ Commented…

Question-171229

Question Number 171229 by sciencestudent last updated on 10/Jun/22 Commented by mr W last updated on 10/Jun/22 $${you}\:{could}\:{mean}\:“{exactly}\:\mathrm{20}\:{apples}''\:{or} \\ $$$$“{about}\:\mathrm{20}\:{apples}''.\:{since}\:{this}\:{is}\:{not} \\ $$$${clear},\:{one}\:{can}\:{not}\:{say}\:{how}\:{many} \\ $$$${significant}\:{numbers}\:{you}\:{used}. \\…

A-triangle-QRS-is-to-be-constructed-from-a-line-segment-of-lenght-15cm-Construct-the-triangle-using-the-division-of-the-line-segment-into-the-ratio-5-4-3-such-that-QS-and-RS-are-laegest-and-smallest

Question Number 171165 by MathsFan last updated on 09/Jun/22 $${A}\:{triangle}\:{QRS}\:{is}\:{to}\:{be}\:{constructed}\:{from} \\ $$$${a}\:{line}\:{segment}\:{of}\:{lenght}\:\mathrm{15}{cm}.\: \\ $$$${Construct}\:{the}\:{triangle}\:{using}\:{the} \\ $$$${division}\:{of}\:{the}\:{line}\:{segment}\:{into}\:{the} \\ $$$${ratio}\:\mathrm{5}:\mathrm{4}:\mathrm{3}\:{such}\:{that}\:{QS}\:{and}\:{RS}\:{are} \\ $$$${laegest}\:{and}\:{smallest}\:{ratio}\:{respectively}. \\ $$$${circumscribe}\:{the}\:{triangle}\:{by}\:{locating} \\ $$$${the}\:{circumcenter}. \\…

show-that-the-common-chord-of-the-circle-x-2-y-2-4-and-x-2-y-2-4x-2y-4-0-passes-through-the-origin-

Question Number 171164 by MathsFan last updated on 08/Jun/22 $$\boldsymbol{\mathrm{show}}\:\boldsymbol{\mathrm{that}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{common}}\:\boldsymbol{\mathrm{chord}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{the}} \\ $$$$\boldsymbol{\mathrm{circle}}\:\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\boldsymbol{\mathrm{y}}^{\mathrm{2}} =\mathrm{4}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\boldsymbol{\mathrm{y}}^{\mathrm{2}} −\mathrm{4}\boldsymbol{\mathrm{x}}−\mathrm{2}\boldsymbol{\mathrm{y}}−\mathrm{4}=\mathrm{0} \\ $$$$\boldsymbol{\mathrm{passes}}\:\boldsymbol{\mathrm{through}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{origin}}. \\ $$ Answered by thfchristopher last updated…

Question-171160

Question Number 171160 by mokys last updated on 08/Jun/22 Answered by thfchristopher last updated on 09/Jun/22 $$\mathrm{A}.\:\frac{{dy}}{{dx}}=\mathrm{3}{x}^{\mathrm{2}} +\mathrm{9} \\ $$$${y}=\int\left(\mathrm{3}{x}^{\mathrm{2}} +\mathrm{9}\right){dx} \\ $$$$={x}^{\mathrm{3}} +\mathrm{9}{x}+{C} \\…