Question Number 203111 by lazyboy last updated on 10/Jan/24 $${please}\:{solve}\:{it} \\ $$$$\int\left[{x}^{\frac{{x}}{\mathrm{2}}} +{e}^{{xlnx}} +\frac{\left(\Pi+\sqrt{{x}}{ln}\left({x}\right)\right)^{\mathrm{2}} }{\mathrm{2}{ln}\mathrm{2}\sqrt{{x}−{e}^{{x}} \mathrm{sin}\:{x}}}\right]^{\mathrm{2}} {dx}=? \\ $$ Commented by lazyboy last updated on…
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Question Number 203045 by MathematicalUser2357 last updated on 08/Jan/24 $${very}\:{old}\:{q}\:{Q}.\mathrm{2} \\ $$ Commented by lazyboy last updated on 11/Jan/24 $${how}\:{can}\:{find}\:{Q}.\mathrm{2} \\ $$ Terms of Service…
Question Number 203000 by sonukgindia last updated on 07/Jan/24 Answered by SEKRET last updated on 07/Jan/24 $$\mathrm{3};\mathrm{6} \\ $$ Answered by Rasheed.Sindhi last updated on…
Question Number 203031 by sonukgindia last updated on 07/Jan/24 Answered by MathematicalUser2357 last updated on 08/Jan/24 $${find}\:\mathrm{8}\:{roots}\:{using}\:{newton}'{s}\:{method} \\ $$ Commented by Calculusboy last updated on…
Question Number 202970 by MathedUp last updated on 06/Jan/24 $$\mathrm{Help}\:\mathrm{me}\:\boldsymbol{\sigma}\: \:\boldsymbol{\sigma} \\ $$$$\mathrm{Find}\:\mathrm{all}\:\mathrm{the}\:\mathrm{Ideals}\:\mathrm{of}\:\mathrm{the}\:\mathrm{quotient}\:\mathrm{Ring}\: \\ $$$$\mathbb{Z}/\mathrm{18}\mathbb{Z}\:\mathrm{of}\:\mathrm{the}\:\mathrm{integer}\:\mathrm{ring}\:\mathbb{Z}\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 202962 by MathematicalUser2357 last updated on 06/Jan/24 $$\mathrm{Please}\:\mathrm{fix}\:\mathrm{the}\:\mathrm{bug}. \\ $$$$\underset{{k}=\mathrm{1}} {\overset{\mathrm{10}} {\coprod}}\mathrm{sin}\left(\mathrm{90}°+{k}\right) \\ $$$$\mathrm{Hint}:\:\mathrm{Make}\:\mathrm{the}\:\mathrm{bar}\:\mathrm{disappear}. \\ $$ Commented by Tinku Tara last updated on…
Question Number 202967 by sonukgindia last updated on 06/Jan/24 Answered by mr W last updated on 06/Jan/24 Commented by mr W last updated on 07/Jan/24…
Question Number 202988 by sonukgindia last updated on 06/Jan/24 Commented by Frix last updated on 06/Jan/24 $$\mathrm{By}\:\mathrm{parts}. \\ $$ Answered by MM42 last updated on…
Question Number 202893 by sonukgindia last updated on 05/Jan/24 Answered by BaliramKumar last updated on 05/Jan/24 $$\mathrm{0}.\mathrm{5}\:=\:{h}\left({cot}\mathrm{37}°−{cot}\mathrm{41}°\right) \\ $$$${h}\:=\:\mathrm{2}.\mathrm{830}\:{km} \\ $$ Answered by AST last…