Question Number 105599 by mohammad17 last updated on 30/Jul/20 Answered by bobhans last updated on 30/Jul/20 $${set}\:{z}\:=\:{y}^{\mathrm{1}−\mathrm{2}} ={y}^{−\mathrm{1}} \\ $$$$\frac{{dz}}{{dx}}\:=\:−{y}^{−\mathrm{2}} \:\frac{{dy}}{{dx}}\:\Rightarrow−{y}^{\mathrm{2}} \:\frac{{dz}}{{dx}}\:=\:\frac{{dy}}{{dx}}\: \\ $$$$\Leftrightarrow\:−{y}^{\mathrm{2}} \:\frac{{dz}}{{dx}}+\mathrm{3}{xy}\:=\:{y}^{\mathrm{2}}…
Question Number 105593 by Study last updated on 30/Jul/20 $${f}\left({x}\right)=\frac{\sqrt{\mathrm{2}{x}+\mathrm{1}}×\sqrt{\mathrm{2}{x}+\mathrm{1}}}{\mathrm{2}{x}+\mathrm{1}}\:\:\:\:\:\:{Dom}_{{f}} =? \\ $$ Answered by mathmax by abdo last updated on 30/Jul/20 $$\left.\mathrm{D}_{\mathrm{f}} =\right]−\frac{\mathrm{1}}{\mathrm{2}},+\infty\left[\right. \\…
Question Number 40022 by MrW3 last updated on 15/Jul/18 $${To}\:{the}\:{developer}\:{Tinku}\:{Tara}: \\ $$$${Dear}\:{sir}, \\ $$$${can}\:{you}\:{please}\:{make}\:{it}\:{possible}\:{again} \\ $$$${that}\:{a}\:{posted}\:{image}\:{can}\:{be}\:{updated} \\ $$$$\left({changed}\right)\:{through}\:{the}\:“{edit}\:{post}'' \\ $$$${function}. \\ $$$${This}\:{was}\:{possible}\:{in}\:{the}\:{past}.\:{But}\:{it}\:{is} \\ $$$${now}\:{not}\:{possible}\:{for}\:{unknown}\:{reasons}. \\…
Question Number 171091 by pablo1234523 last updated on 07/Jun/22 Commented by pablo1234523 last updated on 07/Jun/22 $$\mathrm{how}\:\mathrm{is}\:\mathrm{the}\:\mathrm{red}\:\mathrm{expression}\:\mathrm{obtained} \\ $$$${f}^{\mathrm{2}{n}+\mathrm{1}} \left(\theta{x}\right)=\mathrm{cos}\:\left(\frac{\left(\mathrm{2}{n}+\mathrm{1}\right)\pi}{\mathrm{2}}+\theta{x}\right)=\mathrm{cos}\:\left({n}\pi+\frac{\pi}{\mathrm{2}}+\theta{x}\right) \\ $$$$=−\mathrm{sin}\:\left({n}\pi+\theta{x}\right)=\left(−\mathrm{1}\right)^{{n}} \mathrm{sin}\:\left(\theta{x}\right) \\ $$$$…
Question Number 105544 by mohammad17 last updated on 29/Jul/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 171078 by MathsFan last updated on 07/Jun/22 $$\boldsymbol{\mathrm{sketch}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{graph}}\:\boldsymbol{\mathrm{of}} \\ $$$$\:\boldsymbol{\mathrm{y}}=\boldsymbol{\mathrm{ln}}\left(\boldsymbol{\mathrm{x}}+\mathrm{5}\right) \\ $$$$ \\ $$ Answered by thfchristopher last updated on 07/Jun/22 Commented by…
Question Number 171070 by MathsFan last updated on 07/Jun/22 $$\boldsymbol{\mathrm{x}}^{\mathrm{2}} −\mathrm{1}=\mathrm{2}^{\boldsymbol{\mathrm{x}}} \\ $$$$\:\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{x}} \\ $$ Answered by Rasheed.Sindhi last updated on 07/Jun/22 $$\mathrm{x}^{\mathrm{2}} −\mathrm{1}=\mathrm{2}^{\mathrm{x}} \:;\mathrm{find}\:\mathrm{x}…
Question Number 171071 by mathocean1 last updated on 07/Jun/22 $${justify}\:{that}\:\int_{\mathrm{0}} ^{+\infty} \frac{{dt}}{\mathrm{1}+{t}^{\mathrm{4}} }\:{is}\:{convergent}. \\ $$ Answered by aleks041103 last updated on 07/Jun/22 $$\int_{\mathrm{0}} ^{\infty} \frac{{dt}}{\mathrm{1}+{t}^{\mathrm{4}}…
Question Number 39983 by Necxx last updated on 14/Jul/18 $${To}\:{developer},{Is}\:{there}\:{any}\:{way}\:{of} \\ $$$${getting}\:{back}\:{your}\:{previous}\:{account} \\ $$$${if}\:{you}\:{lost}\:{your}\:{password}? \\ $$ Answered by Tinku Tara last updated on 14/Jul/18 $$\mathrm{Not}\:\mathrm{really}.\:\mathrm{Since}\:\mathrm{we}\:\mathrm{dont}\:\mathrm{have}…
Question Number 105506 by Anindita last updated on 29/Jul/20 $$\left(−\frac{\mathrm{1}}{\mathrm{2}}\right)+\left(+\frac{\mathrm{3}}{\mathrm{7}}\right)+\left(−\frac{\mathrm{1}}{\mathrm{10}}\right)=? \\ $$ Commented by Anindita last updated on 29/Jul/20 $$\boldsymbol{\mathrm{Can}}\:\boldsymbol{\mathrm{anyone}}\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{this}}? \\ $$ Commented by prakash…