Question Number 104703 by abony1303 last updated on 23/Jul/20 Commented by abony1303 last updated on 23/Jul/20 $$\left.\mathrm{pls}\:\mathrm{help}\:\mathrm{too}\::\right) \\ $$ Answered by bemath last updated on…
Question Number 104701 by abony1303 last updated on 23/Jul/20 Commented by abony1303 last updated on 23/Jul/20 $$\mathrm{Pls}\:\mathrm{help} \\ $$ Answered by mathmax by abdo last…
Question Number 170226 by ali009 last updated on 18/May/22 $${solve}\: \\ $$$$\begin{cases}{{x}+{y}+{z}+{w}=\mathrm{0}}\\{{x}+{y}+{z}+\mathrm{2}{w}=\mathrm{0}}\\{\mathrm{2}{x}+\mathrm{2}{y}+\mathrm{3}{z}+\mathrm{4}{w}=\mathrm{1}}\\{\mathrm{2}{x}+\mathrm{3}{y}+\mathrm{4}{z}+\mathrm{5}{w}=\mathrm{2}}\end{cases} \\ $$$$ \\ $$ Answered by floor(10²Eta[1]) last updated on 18/May/22 $$\Rightarrow\mathrm{x}+\mathrm{y}+\mathrm{z}+\mathrm{w}=\mathrm{x}+\mathrm{y}+\mathrm{z}+\mathrm{2w}\Rightarrow\mathrm{w}=\mathrm{2w}\Rightarrow\mathrm{w}=\mathrm{0} \\…
Question Number 170212 by otchereabdullai@gmail.com last updated on 18/May/22 $$\:\mathrm{which}\:\mathrm{rectangle}\:\mathrm{with}\:\mathrm{integer}\:\mathrm{length}\: \\ $$$$\:\:\mathrm{side}\:\mathrm{have}\:\mathrm{numerically}\:\mathrm{the}\:\mathrm{same}\:\mathrm{area} \\ $$$$\:\:\mathrm{and}\:\mathrm{perimeter}?\:\mathrm{Find}\:\mathrm{them}\:\mathrm{all}.\:\mathrm{Find} \\ $$$$\:\mathrm{a}\:\mathrm{proof}\:\mathrm{that}\:\mathrm{convinces}\:\mathrm{that}\:\mathrm{you}\:\mathrm{have} \\ $$$$\:\mathrm{found}\:\mathrm{them}\:\mathrm{all}.\:\mathrm{what}\:\mathrm{about}\:\mathrm{right}− \\ $$$$\:\mathrm{angled}\:\mathrm{triangle}?\:\mathrm{how}\:\mathrm{many}\:\mathrm{solutions}? \\ $$ Answered by aleks041103…
Question Number 170205 by otchereabdullai@gmail.com last updated on 18/May/22 $$\:\mathrm{If}\:\mathrm{x}\:\mathrm{is}\:\mathrm{nearer}\:\:\:\mathrm{a}\:\:\mathrm{than}\:\:\mathrm{b}\:\:\mathrm{in}\:\left[\mathrm{a},\mathrm{b}\right],\: \\ $$$$\mathrm{is}\:\sqrt{\mathrm{x}}\:\mathrm{necessarily}\:\mathrm{nearer}\:\sqrt{\mathrm{a}}\:\:\mathrm{than}\:\sqrt{\mathrm{b}} \\ $$$$ \\ $$$$\mathrm{Give}\:\mathrm{a}\:\mathrm{proof}\:\mathrm{of}\:\mathrm{counterexample} \\ $$ Answered by floor(10²Eta[1]) last updated on 18/May/22…
Question Number 170206 by bounhome last updated on 18/May/22 $$\mathrm{1}.\:\:\:\:\begin{cases}{{y}^{{log}_{{x}} {y}} ={x}^{\mathrm{4}} }\\{{log}_{\mathrm{2}} \left({y}−{x}\right)=\mathrm{1}}\end{cases} \\ $$$$\mathrm{2}.\:\:\:\:\:\mathrm{25}^{−{x}} −\mathrm{5}^{−{x}+\mathrm{1}} \geqslant\mathrm{50} \\ $$ Answered by aleks041103 last updated…
Question Number 170203 by bounhome last updated on 18/May/22 $${solve}:\:\mathrm{5}^{{lgx}} =\mathrm{50}−{x}^{{lg}\mathrm{5}} \\ $$ Answered by aleks041103 last updated on 18/May/22 $$\mathrm{5}^{{lgx}} =\mathrm{10}^{\left({lgx}\right)\left({lg}\mathrm{5}\right)} ={y} \\ $$$${x}^{{lg}\mathrm{5}}…
Question Number 170202 by otchereabdullai@gmail.com last updated on 18/May/22 $$\:\mathrm{A}\:\mathrm{point}\:\mathrm{is}\:\mathrm{3cm},\:\mathrm{4cm}\:\mathrm{and}\:\mathrm{5cm}\:\mathrm{away}\: \\ $$$$\:\:\mathrm{from}\:\mathrm{three}\:\mathrm{vertices}\:\mathrm{of}\:\mathrm{a}\:\mathrm{rectangle}.\: \\ $$$$\:\mathrm{How}\:\mathrm{far}\:\mathrm{can}\:\mathrm{it}\:\mathrm{be}\:\mathrm{from}\:\mathrm{the}\:\mathrm{4th}\:\mathrm{vertex}. \\ $$$$ \\ $$$$\mathrm{Find}\:\mathrm{all}\:\mathrm{solutions} \\ $$ Commented by otchereabdullai@gmail.com last updated…
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