Question Number 169756 by mokys last updated on 07/May/22 Answered by aleks041103 last updated on 07/May/22 $${A}.\:{y}=\frac{\mathrm{3}}{{x}} \\ $$$${V}=\int_{\mathrm{2}} ^{\:\mathrm{3}} \pi{y}^{\mathrm{2}} {dx}=\mathrm{9}\pi\int_{\mathrm{2}} ^{\:\mathrm{3}} \frac{{dx}}{{x}^{\mathrm{2}} }=\mathrm{9}\pi\left(\frac{\mathrm{1}}{{x}}\right)_{\mathrm{3}}…
Question Number 169736 by mathocean1 last updated on 07/May/22 $${Given}\:{a}\:\in\:\left[\frac{\mathrm{3}\pi}{\mathrm{2}};\mathrm{2}\pi\right]. \\ $$$${Determinate}\:{a}\:{values}\:{for}\:{which} \\ $$$${the}\:{sequence}\:{u}_{{n}} ={cos}\left({a}\right)\left({sin}\left({a}\right)\right)^{{n}} \:{is} \\ $$$${constant}\:{from}\:{a}\:{certain}\:{value}\:{of}\:{n}. \\ $$ Terms of Service Privacy Policy…
Question Number 169743 by naka3546 last updated on 07/May/22 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\:\frac{\underset{\mathrm{0}} {\int}\overset{\:{x}} {\:}\sqrt{\mathrm{1}\:+\:\mathrm{sin}\:{t}}\:{dt}}{{x}}\:=\:{a}\:\:,\:\: \\ $$$${then}\:\:\:{a}^{\mathrm{2}} \:−\:\mathrm{1}\:\:=\:\:…\:? \\ $$ Answered by Mathspace last updated on 07/May/22…
Question Number 104191 by mathocean1 last updated on 19/Jul/20 $${Given}\:\left({E}\right):{x}^{\mathrm{4}} −\mathrm{10}{x}^{\mathrm{2}} +{q}=\mathrm{0} \\ $$$${U}={x}^{\mathrm{2}} \:{so}\:\left({E}_{\left({U}\right)} \right)={U}^{\mathrm{2}} −\mathrm{40}{U}+{q}=\mathrm{0}\:. \\ $$$${We}\:{suppose}\:{that}\:{E}_{\left({U}\right)} {has}\:{two}\:{roots} \\ $$$${such}\:{as}\:{r}_{\mathrm{1}} <{r}_{\mathrm{2}\:} . \\…
Question Number 104187 by mathocean1 last updated on 19/Jul/20 $${Given}: \\ $$$$\left({E}\right):\:\left({m}+\mathrm{1}\right){x}^{\mathrm{2}} +\left({m}−\mathrm{2}\right){x}+\mathrm{1}=\mathrm{0} \\ $$$${We}\:{suppose}\:{that}\:{it}\:{has}\:{two}\:{roots}\:{x}_{\mathrm{1}} \\ $$$${and}\:{x}_{\mathrm{2}} . \\ $$$${Determinate}\:{m}\:{such}\:{that}: \\ $$$${x}_{\mathrm{1}} =\mathrm{1}+{x}_{\mathrm{2}} \\ $$…
Question Number 104181 by mathocean1 last updated on 19/Jul/20 $${Given} \\ $$$${P}\left({x}\right)={x}^{\mathrm{4}} +\mathrm{2}{x}^{\mathrm{3}} −\mathrm{41}{x}^{\mathrm{2}} +\mathrm{42}{x}+\mathrm{360} \\ $$$${Determinate}\:{Q}\left({x}\right)\:{a}\:{quadratic}\:{poly}− \\ $$$${nom}\:{such}\:{that}: \\ $$$${P}\left({x}\right)=\left({Q}\left({x}\right)\right)^{\mathrm{2}} −\mathrm{42}\left({Q}\left({x}\right)\right)+\mathrm{360} \\ $$ Answered…
Question Number 104178 by mathocean1 last updated on 19/Jul/20 $${Solve}\:{in}\:\mathbb{R} \\ $$$$\left.{a}\right)\:\mathrm{3}\mid{x}−\sqrt{\mathrm{3}}\mid−\mathrm{8}\sqrt{\left(\mid{x}−\sqrt{\mathrm{3}}\mid\right)+\mathrm{4}}=\mathrm{0} \\ $$$$\left.{b}\left.\right)\sqrt{\left(\mid{x}^{\mathrm{2}} −{x}−\mathrm{6}\right.}\mid\right)={x}+\mathrm{1} \\ $$$$\left.{c}\right)\sqrt{\left({x}^{\mathrm{3}} −\mathrm{27}\right.}+\mathrm{6}<{x}+\mathrm{3} \\ $$ Answered by OlafThorendsen last updated…
Question Number 169712 by mokys last updated on 06/May/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 104171 by Tinku Tara last updated on 19/Jul/20 $$\mathrm{App}\:\mathrm{Updates}: \\ $$$$\mathrm{v2}.\mathrm{110}\:\mathrm{is}\:\mathrm{available}\:\mathrm{now}\:\mathrm{on} \\ $$$$\mathrm{www}.\mathrm{tinkutara}.\mathrm{com}\:\mathrm{and}\:\mathrm{will}\:\mathrm{be} \\ $$$$\mathrm{available}\:\mathrm{in}\:\mathrm{playstore}\:\mathrm{in}\:\mathrm{a}\:\mathrm{day}. \\ $$$$\mathrm{This}\:\mathrm{version}\:\mathrm{improves}\:\mathrm{drawing}: \\ $$$$−\:\mathrm{sidebar}\:\mathrm{buttons}\:\mathrm{are}\:\mathrm{added} \\ $$$$−\:\mathrm{Multiple}\:\mathrm{shape}\:\mathrm{selection}\:\mathrm{for} \\ $$$$\:\:\:\:\:\mathrm{alignment}\:\mathrm{can}\:\mathrm{be}\:\mathrm{done}\:\mathrm{from}…
Question Number 169668 by mokys last updated on 05/May/22 Commented by mokys last updated on 06/May/22 $$????? \\ $$ Terms of Service Privacy Policy Contact:…