Question Number 38262 by jasno91 last updated on 23/Jun/18 Answered by tanmay.chaudhury50@gmail.com last updated on 23/Jun/18 $$\frac{\mathrm{10}}{\mathrm{9}},\frac{\mathrm{11}}{\mathrm{9}}\:,\frac{\mathrm{12}}{\mathrm{9}} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 38261 by jasno91 last updated on 23/Jun/18 Answered by tanmay.chaudhury50@gmail.com last updated on 23/Jun/18 $$\frac{\mathrm{1}}{\mathrm{9}\:}\:\:\frac{\mathrm{2}}{\mathrm{9}}\:\:\frac{\mathrm{3}}{\mathrm{9}} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 169319 by otchereabdullai@gmail.com last updated on 28/Apr/22 $$\mathrm{if}\:\mathrm{f}\left(\mathrm{2x}−\mathrm{1}\right)=\mathrm{x}^{\mathrm{2}} −\mathrm{3x}+\mathrm{2},\:\:\mathrm{find}\:\mathrm{f}\left(\mathrm{2}\right) \\ $$ Commented by infinityaction last updated on 28/Apr/22 $${x}\rightarrow\frac{{x}+\mathrm{1}}{\mathrm{2}} \\ $$$${f}\left({x}\right)\:=\:\left(\frac{{x}+\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}\:} −\mathrm{3}\left(\frac{{x}+\mathrm{1}}{\mathrm{2}}\right)+\mathrm{2} \\…
Question Number 103781 by abony1303 last updated on 17/Jul/20 Commented by abony1303 last updated on 17/Jul/20 $$\mathrm{pls}\:\mathrm{help}\:\mathrm{ASAP} \\ $$ Commented by bemath last updated on…
Question Number 103738 by Faetma last updated on 17/Jul/20 $$\mathrm{Prime}-\mathrm{counting}\:\mathrm{function}: \\ $$$$\pi\left({x}\right) \\ $$$$ \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{name}\:\mathrm{of}\:\mathrm{her} \\ $$$$\mathrm{reciprocal}\:\mathrm{function}? \\ $$$$ \\ $$$$\left(\mathrm{Like}\:\mathrm{arcsin}\left({x}\right)\:\mathrm{is}\:\mathrm{the}\right. \\ $$$$\left.\mathrm{reciprocal}\:\mathrm{function}\:\mathrm{of}\:\mathrm{sin}\left({x}\right)\right) \\…
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Question Number 169249 by mathocean1 last updated on 26/Apr/22 $${calculate}\:{A}=\int\frac{{dt}}{{sin}\left({t}\right)}\:{by}\:{using} \\ $$$${u}={cos}\left({t}\right) \\ $$ Commented by infinityaction last updated on 26/Apr/22 $$\:\:\:\:\:\:\:{A}\:=\:\int\frac{\mathrm{sin}\:{t}}{\mathrm{sin}\:^{\mathrm{2}} {t}}{dt} \\ $$$$\:\:\:\:\:\:\:\:\:{A}\:=\:\int\frac{\mathrm{sin}\:{t}}{\mathrm{1}−\mathrm{cos}\:^{\mathrm{2}}…
Question Number 169251 by mathocean1 last updated on 26/Apr/22 $${calculate}\:{C}=\int\frac{{dt}}{\mathrm{1}+{tan}^{\mathrm{2}} \left({t}\right)}\:{using}\:{x}={tan}\left({t}\right) \\ $$ Answered by thfchristopher last updated on 27/Apr/22 $$\mathrm{Let}\:{x}=\mathrm{tan}\:{t} \\ $$$${dx}=\mathrm{sec}^{\mathrm{2}} {tdt} \\…
Question Number 103703 by mohammad17 last updated on 16/Jul/20 $${if}\:{an}\:{object}\:{moves}\:{along}\:{a}\:{straight}\:{line}\: \\ $$$${according}\:{to}\:{the}\:{relationship}\left(\:{x}\left({t}\right)=\left(\frac{\mathrm{1}}{\mathrm{2}}{t}^{\mathrm{2}} −{t}+\mathrm{2}\right)\right) \\ $$$${find}\: \\ $$$$\left(\mathrm{1}\right)\:{the}\:{average}\:{speed}\:{between}\:\left({x}=\frac{\mathrm{3}}{\mathrm{2}}\:,\:{x}=\frac{\mathrm{7}}{\mathrm{2}}\right) \\ $$$$\left(\mathrm{2}\right)\:{the}\:{pelvic}\:{velocity}\:{between}\:\left({x}=\frac{\mathrm{7}}{\mathrm{2}}\right) \\ $$ Answered by Dwaipayan Shikari…
Question Number 169250 by mathocean1 last updated on 26/Apr/22 $${Calculate}\:{B}=\int\frac{\mathrm{1}}{\mathrm{1}+{sin}\left({x}\right)}{dx}\:{using}\:{u}={tan}\left(\frac{{x}}{\mathrm{2}}\right) \\ $$ Commented by infinityaction last updated on 27/Apr/22 $$\:\:\:{I}\:=\:\int\frac{{dx}}{\left(\mathrm{sin}\:\frac{{x}}{\mathrm{2}}\:+\:\mathrm{cos}\:\frac{{x}}{\mathrm{2}}\right)^{\mathrm{2}} } \\ $$$$\:\:{I}\:=\:\int\frac{\mathrm{sec}\:^{\mathrm{2}} {x}/\mathrm{2}}{\left(\mathrm{1}+\mathrm{tan}\:{x}/\mathrm{2}\right)^{\mathrm{2}} }{dx}…