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To-the-developer-of-Tinku-Tara-dear-sir-for-some-unknown-reasons-I-don-t-get-any-notification-from-the-app-when-a-post-in-which-I-am-involved-has-been-updated-Where-is-the-problem-and-how-can-I-s

Question Number 37511 by MrW3 last updated on 14/Jun/18 $${To}\:{the}\:{developer}\:{of}\:{Tinku}\:{Tara}: \\ $$$${dear}\:{sir}:\:{for}\:{some}\:{unknown}\:{reasons} \\ $$$${I}\:{don}'{t}\:{get}\:{any}\:{notification}\:{from}\:{the} \\ $$$${app}\:{when}\:{a}\:{post},\:{in}\:{which}\:{I}\:{am}\:{involved}, \\ $$$${has}\:{been}\:{updated}.\:{Where}\:{is}\:{the} \\ $$$${problem}\:{and}\:{how}\:{can}\:{I}\:{solve}\:{it}? \\ $$$${Thank}\:{you}! \\ $$ Commented…

sinx-dx-

Question Number 168556 by mokys last updated on 13/Apr/22 $$\int\sqrt{{sinx}}\:{dx} \\ $$ Answered by MJS_new last updated on 13/Apr/22 $$\mathrm{this}\:\mathrm{question}\:\mathrm{keeps}\:\mathrm{reappearing};\:\mathrm{I}'\mathrm{ve}\:\mathrm{given} \\ $$$$\mathrm{the}\:\mathrm{answer}\:\mathrm{before}… \\ $$$$\int\sqrt{\mathrm{sin}\:{x}}\:{dx}=\int\sqrt{\mathrm{1}−\mathrm{sin}^{\mathrm{2}} \:\frac{\mathrm{2}{x}−\pi}{\mathrm{4}}}\:{dx}=…

Question-102985

Question Number 102985 by DGmichael last updated on 12/Jul/20 Answered by mathmax by abdo last updated on 12/Jul/20 $$\mathrm{at}\:\mathrm{form}\:\mathrm{of}\:\mathrm{serie}\:\:\:\:\mathrm{let}\:\mathrm{f}\left(\mathrm{x}\right)\:=\int_{\mathrm{0}} ^{\mathrm{x}} \:\frac{\mathrm{e}^{\mathrm{t}} }{\left(\mathrm{1}+\mathrm{t}^{\mathrm{2}} \right)^{\mathrm{2}} }\mathrm{dt} \\…

x-x-dx-

Question Number 168519 by mokys last updated on 12/Apr/22 $$\int\:{x}^{{x}} \:{dx} \\ $$ Answered by Mathspace last updated on 12/Apr/22 $$\int\:{x}^{{x}} {dx}=\int\:{e}^{{xlnx}} {dx} \\ $$$$=\int\:\Sigma\:\frac{\left({xlnx}\right)^{{n}}…

Question-168493

Question Number 168493 by mokys last updated on 11/Apr/22 Answered by FelipeLz last updated on 12/Apr/22 $$\begin{pmatrix}{{n}}\\{{r}}\end{pmatrix}−\begin{pmatrix}{{n}−\mathrm{1}}\\{{r}−\mathrm{1}}\end{pmatrix}\:=\:\frac{{n}!}{{r}!\left({n}−{r}\right)!}−\frac{\left({n}−\mathrm{1}\right)!}{\left({r}−\mathrm{1}\right)!\left({n}−{r}\right)!}\:=\:\frac{{n}!−{r}\left({n}−\mathrm{1}\right)!}{{r}!\left({n}−{r}\right)!}\:=\:\frac{\left({n}−{r}\right)\left({n}−\mathrm{1}\right)!}{{r}!\left({n}−{r}\right)!}\:=\:\frac{\left({n}−\mathrm{1}\right)!}{{r}!\left({n}−{r}−\mathrm{1}\right)!}\:=\:\frac{\left({n}−\mathrm{1}\right)!}{{r}!\left(\left({n}−\mathrm{1}\right)−{r}\right)!}\:=\:\begin{pmatrix}{{n}−\mathrm{1}}\\{\:\:\:\:\:{r}}\end{pmatrix} \\ $$ Terms of Service Privacy Policy Contact:…

solve-for-Z-x-t-if-Z-n-x-2-t-subjected-Z-x-0-x-2-and-Z-1-t-cost-

Question Number 37424 by mondodotto@gmail.com last updated on 12/Jun/18 $$\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{for}}\:\boldsymbol{{Z}}\left(\boldsymbol{{x}},\boldsymbol{{t}}\right)\boldsymbol{\mathrm{if}}\:\boldsymbol{\mathrm{Z}}_{\boldsymbol{\mathrm{n}}} =\boldsymbol{{x}}^{\mathrm{2}} \boldsymbol{{t}}\:\:\boldsymbol{\mathrm{subjected}}\:\boldsymbol{{Z}}\left(\boldsymbol{{x}},\mathrm{0}\right)=\boldsymbol{{x}}^{\mathrm{2}} \\ $$$$\boldsymbol{\mathrm{and}}\:\boldsymbol{{Z}}\left(\mathrm{1},\boldsymbol{{t}}\right)=\boldsymbol{\mathrm{cos}{t}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com