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show-that-U-x-y-F-2x-5y-G-x-5y-is-the-general-solution-4U-25U-0-

Question Number 37422 by mondodotto@gmail.com last updated on 12/Jun/18 $$\boldsymbol{\mathrm{show}}\:\boldsymbol{\mathrm{that}}\:\boldsymbol{{U}}\left(\boldsymbol{{x}},\boldsymbol{{y}}\right)=\boldsymbol{{F}}\left(\mathrm{2}\boldsymbol{{x}}+\mathrm{5}\boldsymbol{{y}}\right)+\boldsymbol{{G}}\left(\boldsymbol{{x}}−\mathrm{5}\boldsymbol{{y}}\right) \\ $$$$\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{general}}\:\boldsymbol{\mathrm{solution}}\:\mathrm{4}\boldsymbol{{U}}_{\upsilon} −\mathrm{25}\boldsymbol{{U}}_{\upsilon} =\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

find-all-real-solutions-2-x-2-x-2-3-2x-4-1-i-what-if-x-is-permitted-to-be-complex-number-ii-what-if-1-1-2n-

Question Number 37382 by mondodotto@gmail.com last updated on 12/Jun/18 $$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{all}}\:\boldsymbol{\mathrm{real}}\:\boldsymbol{\mathrm{solutions}} \\ $$$$\left(\mathrm{2}−\boldsymbol{{x}}^{\mathrm{2}} \right)^{\boldsymbol{{x}}^{\mathrm{2}} −\mathrm{3}\sqrt{\mathrm{2}\boldsymbol{{x}}}+\mathrm{4}} =\mathrm{1} \\ $$$$\left.\mathrm{i}\right\}\boldsymbol{\mathrm{what}}\:\boldsymbol{\mathrm{if}}\:\boldsymbol{{x}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{permitted}} \\ $$$$\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{be}}\:\boldsymbol{\mathrm{complex}}\:\boldsymbol{\mathrm{number}} \\ $$$$\left.\boldsymbol{\mathrm{ii}}\right\}\boldsymbol{\mathrm{what}}\:\boldsymbol{\mathrm{if}}\:\mathrm{1}=\left(−\mathrm{1}\right)^{\mathrm{2}\boldsymbol{\mathrm{n}}} ? \\ $$ Commented…

Question-102918

Question Number 102918 by otchereabdullai@gmail.com last updated on 11/Jul/20 Commented by bramlex last updated on 12/Jul/20 Commented by otchereabdullai@gmail.com last updated on 14/Jul/20 $$\mathrm{thanks}\:\mathrm{for}\:\mathrm{ur}\:\mathrm{time}\:\mathrm{sir}\:! \\…

find-the-liength-of-x-y-3-2-from-1-1-to-2-2-2-

Question Number 168441 by mokys last updated on 10/Apr/22 $${find}\:{the}\:{liength}\:{of}\:{x}\:=\:{y}^{\frac{\mathrm{3}}{\mathrm{2}}} \:{from}\:\left(\mathrm{1},\mathrm{1}\right){to}\:\left(\mathrm{2},\mathrm{2}\sqrt{\mathrm{2}}\right) \\ $$ Answered by kowalsky78 last updated on 10/Apr/22 $${There}'{s}\:{something}\:{strange}\:{about}\:{this}\:{point}\:\left(\mathrm{2},\mathrm{2}\sqrt{\mathrm{2}}\right). \\ $$$${Did}\:{you}\:{mean}\:\left(\mathrm{2}\sqrt{\mathrm{2}},\mathrm{2}\right)? \\ $$…

Question-168400

Question Number 168400 by leicianocosta last updated on 10/Apr/22 Commented by cortano1 last updated on 10/Apr/22 $$\:\:\:\:\begin{cases}{\mathrm{5}\sqrt{\mathrm{7}}\:\pi{x}+\mathrm{2}\pi{y}\:=\:\frac{\mathrm{2}\pi\sqrt{\mathrm{7}}}{\mathrm{7}}}\\{{x}\:\:\:\:\:\:\:\:\:\:\:\:\:−\mathrm{2}\pi{y}\:=\:\mathrm{10}\pi^{\mathrm{2}} }\end{cases} \\ $$$$\:\:\:\:{x}\left(\mathrm{5}\sqrt{\mathrm{7}}\:\pi+\mathrm{1}\right)=\frac{\mathrm{2}\pi\sqrt{\mathrm{7}}}{\mathrm{7}}+\mathrm{10}\pi^{\mathrm{2}} \\ $$$$\:\:\:{x}=\frac{\mathrm{2}\pi\sqrt{\mathrm{7}}+\mathrm{70}\pi^{\mathrm{2}} }{\mathrm{35}\pi\sqrt{\mathrm{7}}+\mathrm{7}}\:;\:\left[\pi=\frac{\mathrm{22}}{\mathrm{7}}\right] \\ $$…

Question-102854

Question Number 102854 by Sontsaronald last updated on 11/Jul/20 Answered by Ar Brandon last updated on 11/Jul/20 $$\mathrm{arctan}\left(\mathrm{ch}\left(\mathrm{x}\right)\right)=\mathrm{arctan}\left(\frac{\mathrm{1}}{\mathrm{sh}\left(\mathrm{x}\right)}\right) \\ $$$$\Rightarrow\:\mathrm{ch}\left(\mathrm{x}\right)=\frac{\mathrm{1}}{\mathrm{sh}\left(\mathrm{x}\right)}\:\Rightarrow\:\mathrm{2sh}\left(\mathrm{x}\right)\mathrm{ch}\left(\mathrm{x}\right)=\mathrm{2}\:\Rightarrow\:\mathrm{sh}\left(\mathrm{2x}\right)=\mathrm{2} \\ $$$$\Rightarrow\:\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{e}^{\mathrm{2x}} −\mathrm{e}^{−\mathrm{2x}} \right)=\mathrm{2}\:\Rightarrow\:\mathrm{e}^{\mathrm{4x}} −\mathrm{4e}^{\mathrm{2x}}…

Question-102857

Question Number 102857 by mathocean1 last updated on 11/Jul/20 Commented by PRITHWISH SEN 2 last updated on 11/Jul/20 $$\frac{\mathrm{11}}{\mathrm{2}}\left\{\mathrm{2a}+\left(\mathrm{11}−\mathrm{1}\right)\mathrm{4}\right\}=\mathrm{374} \\ $$$$\mathrm{a}=\mathrm{14} \\ $$$$\therefore\:\:\mathrm{It}\:\mathrm{takes}\:\mathrm{14}\:\mathrm{mins}.\:\mathrm{to}\:\mathrm{sweep}\:\mathrm{the}\:\mathrm{first}\:\mathrm{class}\:\: \\ $$…