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x-1-x-6-dx-

Question Number 168231 by naka3546 last updated on 06/Apr/22 $$\int\:\:{x}\:\sqrt{\mathrm{1}−{x}^{\mathrm{6}} }\:\:{dx}\:\:=\:\:? \\ $$ Commented by MJS_new last updated on 06/Apr/22 $$\mathrm{first}\:\mathrm{step} \\ $$$$\int{x}\sqrt{\mathrm{1}−{x}^{\mathrm{6}} }{dx}= \\…

Question-102644

Question Number 102644 by otchereabdullai@gmail.com last updated on 10/Jul/20 Answered by Rasheed.Sindhi last updated on 10/Jul/20 $${x}:\:{tricycles},{y}:{taxicabs} \\ $$$${x}+{y}=\mathrm{20} \\ $$$$\mathrm{2}{x}+\mathrm{4}{y}=\mathrm{66} \\ $$$$\mathrm{2}{x}+\mathrm{2}{y}=\mathrm{40} \\ $$$$\mathrm{2}{x}+\mathrm{4}{y}=\mathrm{66}…

prove-that-cos-sin-2-cosec-sin-2-2-

Question Number 37110 by mondodotto@gmail.com last updated on 09/Jun/18 $$\boldsymbol{\mathrm{prove}}\:\boldsymbol{\mathrm{that}} \\ $$$$\left(\boldsymbol{\mathrm{cos}\vartheta}−\boldsymbol{\mathrm{sin}\vartheta}\right)^{\mathrm{2}} +\left(\boldsymbol{\mathrm{cosec}\vartheta}+\boldsymbol{\mathrm{sin}\vartheta}\right)^{\mathrm{2}} =\mathrm{2} \\ $$ Commented by tanmay.chaudhury50@gmail.com last updated on 09/Jun/18 $${to}\:{make}\:{it}\:{true}\:{replace}\:{cosec}\theta\:{by}\:{cos}\theta \\…

Question-102642

Question Number 102642 by otchereabdullai@gmail.com last updated on 10/Jul/20 Answered by som(math1967) last updated on 10/Jul/20 $$\angle\mathrm{SRQ}=\angle\mathrm{RTS}=\mathrm{28} \\ $$$$\mathrm{x}=\mathrm{180}−\angle\mathrm{VRS}=\angle\mathrm{VRM}+\angle\mathrm{SRQ} \\ $$$$=\mathrm{46}+\mathrm{28}=\mathrm{74}°\mathrm{ans} \\ $$ Commented by…

v2-095-has-been-uploaded-Changes-Go-To-opens-in-a-pop-window-Drawing-Fix-for-drawing-tool-not-usable-in-some-countries-Uploaded-to-playstore-

Question Number 102624 by Tinku Tara last updated on 10/Jul/20 $$\mathrm{v2}.\mathrm{095}\:\mathrm{has}\:\mathrm{been}\:\mathrm{uploaded}. \\ $$$$\boldsymbol{\mathrm{Changes}}: \\ $$$$\mathrm{Go}\:\mathrm{To}:\:\mathrm{opens}\:\mathrm{in}\:\mathrm{a}\:\mathrm{pop}\:\mathrm{window} \\ $$$$\mathrm{Drawing}:\:\mathrm{Fix}\:\mathrm{for}\:\mathrm{drawing}\:\mathrm{tool}\:\mathrm{not}\:\mathrm{usable} \\ $$$$\mathrm{in}\:\mathrm{some}\:\mathrm{countries}.\: \\ $$$$\mathrm{Uploaded}\:\mathrm{to}\:\mathrm{playstore}. \\ $$ Commented by…

Question-168138

Question Number 168138 by Shemson_buo last updated on 04/Apr/22 Answered by MJS_new last updated on 04/Apr/22 $$\int\frac{{dx}}{\:\sqrt{\mathrm{1}−\mathrm{2}{x}−{x}^{\mathrm{2}} }}= \\ $$$$\:\:\:\:\:\left[{t}=\mathrm{arcsin}\:\frac{{x}+\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\rightarrow\:{dx}=\sqrt{\mathrm{1}−\mathrm{2}{x}−{x}^{\mathrm{2}} }{dt}\right] \\ $$$$=\int{dt}={t}=\mathrm{arcsin}\:\frac{{x}+\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:+{C} \\ $$…