Menu Close

Category: None

5-5-x-x-5pi-find-all-answers-until-24-01-2024-

Tinku Tara 0 Comments

Question Number 203454 by Denis_volosenko352 last updated on 19/Jan/24 $$\sqrt{\mathrm{5}}+\sqrt{\mathrm{5}}={x} \\ $$$${x}×\mathrm{5}\pi=?\:{find}\:{all}\:{answers}\:{until}\:\mathrm{24}.\mathrm{01}.\mathrm{2024} \\ $$ Answered by MathematicalUser2357 last updated on 20/Jan/24 $${x}=\sqrt{\mathrm{5}}+\sqrt{\mathrm{5}}=\mathrm{2}\sqrt{\mathrm{5}} \\ $$$${x}×\mathrm{5}\pi=\mathrm{2}\sqrt{\mathrm{5}}×\mathrm{5}\pi=\mathrm{10}\pi\sqrt{\mathrm{5}} \\…

Read more →

let-A-B-and-C-be-sets-prove-using-venn-diagrams-and-by-first-principle-a-A-B-C-A-B-A-C-b-A-B-C-A-B-A-C-c-A-B-A-B-B-A-

Tinku Tara 0 Comments

Question Number 203468 by MrGHK last updated on 19/Jan/24 $$\:\boldsymbol{\mathrm{let}}\:\boldsymbol{\mathrm{A}}\:{B}\:{and}\:{C}\:\:\boldsymbol{\mathrm{be}}\:\boldsymbol{\mathrm{sets}}\:\boldsymbol{\mathrm{prove}}\:\boldsymbol{\mathrm{using}}\:\boldsymbol{\mathrm{venn}}\:\boldsymbol{\mathrm{diagrams}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{by}}\:\boldsymbol{\mathrm{first}}\:\boldsymbol{\mathrm{principle}} \\ $$$$\left.\:\boldsymbol{\mathrm{a}}\right)\boldsymbol{\mathrm{A}}×\left(\boldsymbol{\mathrm{B}}\cup\boldsymbol{\mathrm{C}}\right)=\left(\boldsymbol{\mathrm{A}}×\boldsymbol{\mathrm{B}}\right)\cup\left(\boldsymbol{\mathrm{A}}×\boldsymbol{\mathrm{C}}\right) \\ $$$$\left.\boldsymbol{\mathrm{b}}\right)\mathrm{A}×\left(\boldsymbol{\mathrm{B}}\cap\boldsymbol{\mathrm{C}}\right)=\left(\boldsymbol{\mathrm{A}}×\boldsymbol{\mathrm{B}}\right)\cap\left(\boldsymbol{\mathrm{A}}×\boldsymbol{\mathrm{C}}\right) \\ $$$$\left.\boldsymbol{\mathrm{c}}\right)\left(\boldsymbol{\mathrm{A}}−\boldsymbol{\mathrm{B}}\right)\cap\left(\boldsymbol{{A}}\cap\boldsymbol{\mathrm{B}}\right)\cap\left(\boldsymbol{\mathrm{B}}−\boldsymbol{\mathrm{A}}\right)=\left\{\right\} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Read more →

Question-203471

Tinku Tara 0 Comments

Question Number 203471 by DEGWE last updated on 19/Jan/24 Answered by MathematicalUser2357 last updated on 20/Jan/24 $$=\frac{\underset{{x}\rightarrow\mathrm{0}^{+} } {\mathrm{lim}}{x}^{\mathrm{cosec}\:{x}+\mathrm{cot}\:{x}} }{\underset{{x}\rightarrow\mathrm{0}^{+} } {\mathrm{lim}}\left(\mathrm{cosec}\:{x}+\mathrm{cot}\:{x}\right)} \\ $$$$=\frac{\underset{{x}\rightarrow\mathrm{0}^{+} }…

Read more →

Question-203434

Tinku Tara 0 Comments

Question Number 203434 by sonukgindia last updated on 19/Jan/24 Answered by witcher3 last updated on 20/Jan/24 $$=\int\frac{−\mathrm{2sin}\left(\mathrm{2x}\right)\mathrm{sin}\left(\mathrm{3x}\right)}{\mathrm{1}+\mathrm{2cos}\left(\mathrm{3x}\right)}\mathrm{dx} \\ $$$$=\frac{\mathrm{sin}\left(\mathrm{2x}\right)}{\mathrm{3}}\mathrm{ln}\left(\mathrm{1}+\mathrm{2cos}\left(\mathrm{3x}\right)\right)−\frac{\mathrm{1}}{\mathrm{6}}\int\mathrm{sin}\left(\mathrm{x}\right)\mathrm{cos}\left(\mathrm{x}\right)\mathrm{ln}\left(\mathrm{1}+\mathrm{2cos}\left(\mathrm{3x}\right)\right)\mathrm{dx} \\ $$$$\mathrm{ln}\left(\mathrm{1}+\mathrm{2cos}\left(\mathrm{3x}\right)\right)=\mathrm{ln}\left(\mathrm{1}+\mathrm{2cos}\left(\mathrm{x}\right)\left(\mathrm{2cos}^{\mathrm{2}} \left(\mathrm{x}\right)−\mathrm{1}\right)−\mathrm{4}\left(\mathrm{1}−\mathrm{cos}^{\mathrm{2}} \left(\mathrm{x}\right)\right)\mathrm{cos}\left(\mathrm{x}\right)\right) \\ $$$$=\mathrm{ln}\left(\mathrm{1}+\mathrm{8cos}^{\mathrm{3}}…

Read more →

Question-203457

Tinku Tara 0 Comments

Question Number 203457 by DEGWE last updated on 19/Jan/24 Answered by witcher3 last updated on 19/Jan/24 $$\mathrm{tanh}\left(\mathrm{x}\right)=\frac{\mathrm{e}^{\mathrm{2x}} −\mathrm{1}}{\mathrm{e}^{\mathrm{2x}} +\mathrm{1}} \\ $$$$\mathrm{f}\left(\mathrm{x}\right)=\frac{\frac{\mathrm{1}+\mathrm{3}^{\mathrm{x}} +\mathrm{x}^{\mathrm{3}} +\mathrm{sh}\left(\mathrm{x}\right)}{\mathrm{1}−\mathrm{3}^{\mathrm{x}} −\mathrm{x}^{\mathrm{3}} −\mathrm{sh}\left(\mathrm{x}\right)}−\mathrm{1}}{\frac{\mathrm{1}+\mathrm{3}^{\mathrm{x}}…

Read more →