Question Number 42170 by lucha116 last updated on 19/Aug/18 $$\left(\mathrm{2}{tanx}−\mathrm{5}\right){tanx}+\left(\mathrm{2}{cotx}−\mathrm{5}\right){cotx}−\mathrm{8}=\mathrm{0} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 19/Aug/18 $$\left(\mathrm{2}{a}−\mathrm{5}\right){a}+\left(\frac{\mathrm{2}}{{a}}−\mathrm{5}\right)\frac{\mathrm{1}}{{a}}−\mathrm{8}=\mathrm{0} \\ $$$$\left(\mathrm{2}{a}^{\mathrm{2}} −\mathrm{5}{a}\right)+\left(\frac{\mathrm{2}−\mathrm{5}{a}}{{a}}\right)\frac{\mathrm{1}}{{a}}−\mathrm{8}=\mathrm{0} \\ $$$$\mathrm{2}{a}^{\mathrm{2}}…
Question Number 42169 by lucha116 last updated on 19/Aug/18 $${solve} \\ $$$$\mathrm{2}{sin}\mathrm{3}{x}\left({sinx}+\sqrt{\mathrm{3}}{cosx}\right)+\mathrm{1}+\mathrm{2}{cos}\mathrm{2}{x}=\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 42150 by Rio Michael last updated on 18/Aug/18 $${Expand}\:\:\:\left({x}^{{x}} +\:\mathrm{5}^{{x}} \right)^{\mathrm{3}{x}} \:{up}\:{to}\:{the}\:{term}\:{in}\:{x}^{\mathrm{5}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 107679 by seedhamaieng@gmail.com last updated on 12/Aug/20 $$\mathrm{dear}\:\mathrm{tinku}\:\mathrm{tara}\: \\ $$$$\mathrm{Please}\:\mathrm{add}\:\mathrm{a}\:\mathrm{option}\:\mathrm{which}\:\mathrm{gives}\: \\ $$$$\mathrm{us}\:\mathrm{to}\:\mathrm{save}\:\mathrm{a}\:\mathrm{file}\:\mathrm{as}\:\mathrm{pdf}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 173188 by dragan91 last updated on 08/Jul/22 Answered by mr W last updated on 08/Jul/22 $${t}=\sqrt{{x}^{\mathrm{2}} +{x}+\mathrm{1}}\:>\mathrm{0} \\ $$$$\frac{\mathrm{2}{t}}{\:\sqrt{{t}^{\mathrm{2}} +\mathrm{1}}}+\frac{\mathrm{2}\left({t}^{\mathrm{2}} +\mathrm{1}\right)}{{t}}=\mathrm{4}+\sqrt{\mathrm{2}} \\ $$$$\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}+\frac{\mathrm{1}}{{t}}}}+{t}+\frac{\mathrm{1}}{{t}}=\mathrm{2}+\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}…
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