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hello-every-one-for-any-user-here-please-stop-saying-please-help-me-or-who-can-help-me-or-who-is-intellegent-or-just-post-your-question-and-if-we-can-help-you-we-will-do-

Question Number 101641 by  M±th+et+s last updated on 03/Jul/20 $${hello}\:{every}\:{one} \\ $$$${for}\:{any}\:{user}\:{here}\:{please}\:{stop}\:{saying} \\ $$$$\left({please}\:{help}\:{me}\:{or}\:{who}\:{can}\:{help}\:{me}\:{or}\right. \\ $$$$\left.{who}\:{is}\:{intellegent}\:{or}…….\right) \\ $$$${just}\:{post}\:{your}\:{question}\:{and}\:{if}\:{we}\:{can} \\ $$$${help}\:{you}\:{we}\:{will}\:{do}. \\ $$$$ \\ $$ Commented…

convert-0-26999999-into-fraction-a-b-where-a-0-

Question Number 36103 by mondodotto@gmail.com last updated on 28/May/18 $$\boldsymbol{\mathrm{convert}}\:\mathrm{0}.\mathrm{26999999}…\boldsymbol{\mathrm{into}}\:\boldsymbol{\mathrm{fraction}}\: \\ $$$$\frac{\boldsymbol{\mathrm{a}}}{\boldsymbol{\mathrm{b}}}\:\boldsymbol{\mathrm{where}}\:\boldsymbol{\mathrm{a}}\neq\mathrm{0} \\ $$ Answered by MJS last updated on 28/May/18 $$=\frac{\mathrm{26}}{\mathrm{100}}+\frac{\mathrm{9}}{\mathrm{900}}=\frac{\mathrm{27}}{\mathrm{100}} \\ $$ Commented…

dx-x-2-3-x-10-

Question Number 167145 by mkam last updated on 07/Mar/22 $$\int\:\frac{{dx}}{{x}^{\mathrm{2}} −\mathrm{3}\sqrt{{x}}+\mathrm{10}} \\ $$ Commented by MJS_new last updated on 07/Mar/22 $$\mathrm{1}^{\mathrm{st}} \:\mathrm{step}\:{t}=\sqrt{{x}}\:\rightarrow\:{dx}=\mathrm{2}{tdt}\:\Rightarrow \\ $$$$\mathrm{2}\int\frac{{t}}{{t}^{\mathrm{4}} −\mathrm{3}{t}+\mathrm{10}}{dt}…

Calculate-k-1-n-sin-1-cos-k-cos-k-1-

Question Number 167144 by mathocean1 last updated on 07/Mar/22 $${Calculate}\: \\ $$$$\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\:\frac{{sin}\left(\mathrm{1}\right)}{{cos}\left({k}\right){cos}\left({k}−\mathrm{1}\right)} \\ $$ Answered by mathsmine last updated on 07/Mar/22 $${sin}\left(\mathrm{1}\right)={sin}\left({k}−\left(\boldsymbol{{k}}−\mathrm{1}\right)\right)=\boldsymbol{{sin}}\left(\boldsymbol{{k}}\right)\boldsymbol{{cos}}\left(\boldsymbol{{k}}−\mathrm{1}\right)−{sin}\left({k}−\mathrm{1}\right){cos}\left({k}\right) \\…

Question-167120

Question Number 167120 by DAVONG last updated on 07/Mar/22 Answered by TheSupreme last updated on 07/Mar/22 $$\frac{{sin}\left(\frac{\pi}{\mathrm{2}}\left(\mathrm{1}−{cos}\left({x}\right)\right)\right)}{\mathrm{1}−{cos}\left({x}\right)}=\frac{\pi}{\mathrm{2}}\frac{\mathrm{1}−{cos}\left({x}\right)}{\mathrm{1}−{cos}\left({x}\right)}=\frac{\pi}{\mathrm{2}} \\ $$ Answered by Mathspace last updated on…

Question-36024

Question Number 36024 by bshahid010@gmail.com last updated on 27/May/18 Commented by abdo mathsup 649 cc last updated on 27/May/18 $${let}\:{use}\:{the}\:{changement}\:\:{x}\:=\mathrm{1}+{t}\:{so} \\ $$$$\frac{{m}}{{x}^{{m}} \:−\mathrm{1}}\:−\frac{{p}}{{x}^{{p}} \:−\mathrm{1}}\:=\frac{{m}}{\left(\mathrm{1}+{t}\right)^{{m}} \:−\mathrm{1}}\:−\:\frac{{p}}{\left(\mathrm{1}+{t}\right)^{{p}}…