Question Number 101551 by mhmd last updated on 03/Jul/20 Answered by bobhans last updated on 03/Jul/20 $$\left.\left(\mathrm{Q2}\right)\:\mathrm{The}\:\mathrm{area}\:=\:\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\underset{\mathrm{0}} {\overset{{x}} {\int}}\:{dy}\:{dx}\:=\:\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\left({y}\right)\right]_{\mathrm{0}} ^{{x}} \:\:{dx}…
Question Number 101546 by mhmd last updated on 03/Jul/20 Commented by mhmd last updated on 03/Jul/20 $${help}\:{me}\:{sir} \\ $$ Answered by bobhans last updated on…
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Question Number 101523 by MJS last updated on 03/Jul/20 $$\mathrm{Dear}\:\mathrm{Joint}\:\mathrm{Users}, \\ $$$$\mathrm{please}\:\mathrm{use}\:“\mathrm{answer}''\:\mathrm{instead}\:\mathrm{of}\:“\mathrm{comment}'' \\ $$$$\mathrm{when}\:\mathrm{answering}\:\mathrm{a}\:\mathrm{question}.\:\mathrm{it}'\mathrm{s}\:\mathrm{impossible} \\ $$$$\mathrm{to}\:\mathrm{find}\:\mathrm{unanswered}\:\mathrm{questions}\:\mathrm{at}\:\mathrm{the}\:\mathrm{moment}. \\ $$$$\mathrm{it}\:\mathrm{makes}\:\mathrm{no}\:\mathrm{sense}\:\mathrm{to}\:\mathrm{search}\:\mathrm{for}\:“\mathrm{unanswered} \\ $$$$\mathrm{questions}''\:\mathrm{anymore}.\:\mathrm{maybe}\:\mathrm{we}\:\mathrm{need}\:\mathrm{a}\:\mathrm{search} \\ $$$$\mathrm{function}\:\mathrm{for}\:“\mathrm{uncommented}\:\mathrm{questions}''\:\mathrm{soon}. \\ $$$$\mathrm{Thank}\:\mathrm{you} \\…
Question Number 167021 by mkam last updated on 04/Mar/22 $${how}\:{can}\:{it}\:{solve}\:{this}\:? \\ $$$$ \\ $$$$\left(\mathrm{1}\right){sin}\mathrm{360} \\ $$$$\left(\mathrm{2}\right){tan}\mathrm{345} \\ $$$$\left(\mathrm{3}\right){cos}\mathrm{170} \\ $$$$\left(\mathrm{4}\right){sec}\mathrm{150} \\ $$$$\left(\mathrm{5}\right){cot}\mathrm{150} \\ $$ Terms…
Question Number 35933 by mondodotto@gmail.com last updated on 26/May/18 $$\boldsymbol{\mathrm{differentiate}}\:\boldsymbol{\mathrm{from}} \\ $$$$\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{first}}\:\boldsymbol{\mathrm{principle}} \\ $$$$\boldsymbol{\mathrm{y}}=\frac{\mathrm{1}}{\:\sqrt{\boldsymbol{{x}}}} \\ $$ Answered by ajfour last updated on 26/May/18 $${dy}=\frac{\mathrm{1}}{\:\sqrt{{x}+{dx}}}−\frac{\mathrm{1}}{\:\sqrt{{x}}} \\…
Question Number 101458 by mhmd last updated on 02/Jul/20 Commented by mhmd last updated on 02/Jul/20 $$? \\ $$ Commented by mr W last updated…
Question Number 101439 by mhmd last updated on 02/Jul/20 Commented by mhmd last updated on 02/Jul/20 $${help}\:{me}\:{sir}\:? \\ $$ Commented by bramlex last updated on…
Question Number 101436 by bobhans last updated on 02/Jul/20 Answered by bramlex last updated on 02/Jul/20 $$\Leftrightarrow\:\mathrm{x}^{\mathrm{2}} +\mathrm{30}\:+\:\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{30}}\:=\:\mathrm{x}^{\mathrm{4}} +\mathrm{x}^{\mathrm{2}} \\ $$$$\mathrm{set}\:\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{30}}\:=\:\mathrm{z} \\ $$$$\Leftrightarrow\:\mathrm{z}^{\mathrm{2}}…