Question Number 166950 by mr W last updated on 03/Mar/22 Commented by mr W last updated on 03/Mar/22 $${to}\:{Tinku}\:{Tara}\:{sir}: \\ $$$${can}\:{you}\:{please}\:{take}\:{a}\:{look}\:{at}\:{following}\: \\ $$$${issue}: \\ $$$${when}\:{i}\:{try}\:{to}\:{insert}\:{a}\:{line}\:{break}\:{with}…
Question Number 101409 by PRITHWISH SEN 2 last updated on 02/Jul/20 $$\mathrm{which}\:\mathrm{is}\:\mathrm{correct} \\ $$$$\int\frac{\mathrm{5x}^{\mathrm{4}} +\mathrm{4x}^{\mathrm{5}} }{\left(\mathrm{x}^{\mathrm{5}} +\mathrm{x}+\mathrm{1}\right)^{\mathrm{2}} }\:\mathrm{dx}\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to} \\ $$$$\left.\mathrm{a}\left.\right)\:\frac{\mathrm{x}^{\mathrm{5}} }{\mathrm{x}^{\mathrm{5}} +\mathrm{x}+\mathrm{1}}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{b}\right)−\frac{\mathrm{x}+\mathrm{1}}{\mathrm{x}^{\mathrm{5}} +\mathrm{x}+\mathrm{1}} \\ $$…
Question Number 101402 by 1549442205 last updated on 02/Jul/20 $$\mathrm{I}\:\mathrm{desire}\:\mathrm{the}\:\mathrm{developmenter}\:\mathrm{of}\:\mathrm{this}\:\mathrm{apps} \\ $$$$\mathrm{improve}\:\mathrm{adding}\:\mathrm{some}\:\mathrm{other}\:\mathrm{functions} \\ $$$$\mathrm{like}\:\mathrm{as}:\mathrm{choose}\:\mathrm{whole}\:\mathrm{text}\:\mathrm{by}\:\mathrm{tap}\:\mathrm{in} \\ $$$$\mathrm{text}\:\mathrm{or}\:\mathrm{choose}\:\mathrm{some}\:\mathrm{line}\:\mathrm{at}\:\mathrm{one}\:\mathrm{time} \\ $$$$\mathrm{has}\:\mathrm{many}\:\mathrm{colours}\:\mathrm{more} \\ $$ Commented by Tinku Tara last…
Question Number 166929 by MathsFan last updated on 02/Mar/22 $$\:{A}\:{particle}\:{of}\:{mass}\:\mathrm{0}.\mathrm{25}{kg}\:{vibrates} \\ $$$$\:{with}\:{a}\:{period}\:{of}\:\mathrm{2}{secs}.\:{If}\:{its}\: \\ $$$$\:{greatest}\:{displacement}\:{is}\:\mathrm{0}.\mathrm{4}{m}.\:{What} \\ $$$$\:{is}\:{its}\:{maximum}\:{kinetic}\:{energy}. \\ $$ Answered by mr W last updated on…
Question Number 101400 by Tinku Tara last updated on 02/Jul/20 $$\mathrm{App}\:\mathrm{Updates}: \\ $$$$\boldsymbol{\mathrm{Show}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{Hide}}\:\boldsymbol{\mathrm{Keyboard}} \\ $$$$\mathrm{Request}\:\mathrm{by}\:\mathrm{teachers}\:\mathrm{using}\:\mathrm{this} \\ $$$$\mathrm{app}\:\mathrm{along}\:\mathrm{with}\:\mathrm{screen}\:\mathrm{sharing}\:\mathrm{apps} \\ $$$$\mathrm{for}\:\mathrm{online}\:\mathrm{classes} \\ $$$$\boldsymbol{\mathrm{Set}}\:\boldsymbol{\mathrm{Home}}\:\boldsymbol{\mathrm{Screen}}\:\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{Forum}} \\ $$$$\mathrm{Requested}\:\mathrm{by}\:\mathrm{Mr}\:\mathrm{W} \\ $$…
Question Number 166904 by MathsFan last updated on 01/Mar/22 $${A}\:{pendulum}\:{has}\:{a}\:{period}\:\mathrm{2}{sec}.\:{The} \\ $$$${bob}\:{pulled}\:{aside}\:{a}\:{distance}\:\mathrm{8}{cm}\:{as} \\ $$$${the}\:{amplitude}\:{and}\:{release}.\:{Find}\:{the} \\ $$$${displacement}\:{of}\:{the}\:{bob}\:\mathrm{0}.\mathrm{7}{sec}\:{after} \\ $$$${it}\:{has}\:{been}\:{released}. \\ $$ Answered by mr W last…
Question Number 166891 by mathocean1 last updated on 01/Mar/22 $${Linearize}\:{sin}^{\mathrm{4}} \left({x}\right){cos}^{\mathrm{2}} \left({x}\right) \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$ Terms of Service…
Question Number 101319 by mhmd last updated on 01/Jul/20 $${find}\:{the}\:{area}\:{bounded}\:{the}\:{parabola}\: \\ $$$${y}=\mathrm{4}{x}^{\mathrm{2}} \:\:\:{and}\:\:{y}=\mathrm{8}−\mathrm{4}{x}^{\mathrm{2}} \:\:?\:\:{by}\:{using}\:{intigral}? \\ $$$${help}\:{me} \\ $$ Commented by smridha last updated on 01/Jul/20…
Question Number 101307 by Tinku Tara last updated on 01/Jul/20 $$\mathrm{Some}\:\mathrm{comments}\:\mathrm{with}\:\mathrm{inapproriate} \\ $$$$\mathrm{language}\:\mathrm{were}\:\mathrm{deleted}. \\ $$$$\mathrm{Kindly}\:\mathrm{refrain}\:\mathrm{from}\:\mathrm{posting}\:\mathrm{abusive} \\ $$$$\mathrm{comments}.\:\mathrm{Forum}\:\mathrm{has}\:\mathrm{been}\:\mathrm{around} \\ $$$$\mathrm{for}\:\mathrm{a}\:\mathrm{long}\:\mathrm{time}\:\mathrm{without}\:\mathrm{these} \\ $$$$\mathrm{occurrences}. \\ $$$$\mathrm{Every}\:\mathrm{new}\:\mathrm{user},\:\mathrm{please}\:\mathrm{scroll}\:\mathrm{through} \\ $$$$\mathrm{the}\:\mathrm{previous}\:\mathrm{posts}\:\mathrm{and}\:\mathrm{abide}\:\mathrm{by}\:\mathrm{the}\:…
Question Number 166839 by SANOGO last updated on 28/Feb/22 $$\int_{−{oo}} ^{+{oo}} \frac{{xe}^{{x}} }{\left(\mathrm{1}+{e}^{{x}} \right)^{\mathrm{2}} }{dx} \\ $$ Answered by amin96 last updated on 01/Mar/22 $$\boldsymbol{\mathrm{e}}^{\boldsymbol{\mathrm{x}}}…