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We-have-2-red-and-1-black-tokens-We-want-to-dispose-them-on-9-places-of-this-checker-board-1-What-the-number-of-possibilities-to-dispose-these-3-tokens-on-these-9-places-2-What-it-is-the-number-of

Question Number 102101 by mathocean1 last updated on 06/Jul/20 $${We}\:{have}\:\mathrm{2}\:{red}\:{and}\:\mathrm{1}\:{black}\:{tokens}. \\ $$$${We}\:{want}\:{to}\:{dispose}\:{them}\:{on}\:\mathrm{9}\:{places} \\ $$$${of}\:{this}\:{checker}−{board}. \\ $$$$\left.\mathrm{1}\right){What}\:{the}\:{number}\:{of}\:{possibilities}\: \\ $$$${to}\:{dispose}\:{these}\:\mathrm{3}\:{tokens}\:{on}\:{these} \\ $$$$\mathrm{9}\:{places}. \\ $$$$\left.\mathrm{2}\right){What}\:{it}\:{is}\:{the}\:{number}\:{of}\:{possibilities} \\ $$$${to}\:{dispose}\:{these}\:\mathrm{3}\:{tokens}\:\:{like}\:{that}: \\…

Question-102086

Question Number 102086 by mathocean1 last updated on 06/Jul/20 Commented by mr W last updated on 06/Jul/20 $${what}\:{is}\:{a}\:{pair}\:{number}?\:\:={even}\:{number}? \\ $$$${what}\:{is}\:{a}\:{pair}\:{digit}?\:={even}\:{digit}? \\ $$$${what}\:{is}\:{an}\:{unpair}\:{digit}?\:={odd}\:{digit}? \\ $$ Commented…

How-do-i-show-that-A-B-C-A-B-A-C-

Question Number 167616 by MathsFan last updated on 20/Mar/22 $$\boldsymbol{{How}}\:\boldsymbol{{do}}\:\boldsymbol{{i}}\:\boldsymbol{{show}}\:\boldsymbol{{that}} \\ $$$$\:\boldsymbol{{A}}\backslash\boldsymbol{{B}}\oplus\boldsymbol{{C}}=\left(\boldsymbol{{A}}\backslash\boldsymbol{{B}}\right)\oplus\left(\boldsymbol{{A}}\backslash\boldsymbol{{C}}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

1-cos-ax-dx-sin-ax-b-2-D-3-2D-2-D-y-e-2x-x-2-x-3-the-area-between-the-curves-y-2-x-and-y-x-3-

Question Number 102066 by bramlex last updated on 06/Jul/20 $$\left(\mathrm{1}\right)\int\:\frac{\mathrm{cos}\:\left(\mathrm{ax}\right)\:\mathrm{dx}}{\:\sqrt{\mathrm{sin}\:\mathrm{ax}−\mathrm{b}}} \\ $$$$\left(\mathrm{2}\right)\:\left(\mathrm{D}^{\mathrm{3}} +\mathrm{2D}^{\mathrm{2}} +\mathrm{D}\right)\mathrm{y}\:=\:\mathrm{e}^{\mathrm{2x}} +\mathrm{x}^{\mathrm{2}} −\mathrm{x} \\ $$$$\left(\mathrm{3}\right)\mathrm{the}\:\mathrm{area}\:\mathrm{between}\:\mathrm{the}\:\mathrm{curves} \\ $$$$\mathrm{y}\:=\:\frac{\mathrm{2}}{\mathrm{x}}\:\mathrm{and}\:\mathrm{y}\:=\:−\mathrm{x}+\mathrm{3}\: \\ $$ Answered by bemath…

1-1-

Question Number 167588 by AlbertEinstein last updated on 20/Mar/22 $$\mathrm{1}+\mathrm{1}=¿ \\ $$ Answered by chhaythean last updated on 20/Mar/22 $$=\frac{\mathrm{1}}{\mathrm{3}}\int_{\mathrm{0}} ^{\mathrm{2}\pi} \int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \mathrm{sin}\varphi\mathrm{cos}^{\mathrm{3}} \theta\mathrm{d}\varphi\mathrm{d}\theta…

prove-by-useing-the-polar-cordinaite-0-a-2-y-a-2-y-2-x-dx-dy-5-a-3-24-

Question Number 167576 by mkam last updated on 19/Mar/22 $$\boldsymbol{{prove}}\:\boldsymbol{{by}}\:\boldsymbol{{useing}}\:\boldsymbol{{the}}\:\boldsymbol{{polar}}\:\boldsymbol{{cordinaite}}\: \\ $$$$ \\ $$$$\int_{\mathrm{0}} ^{\:\frac{\boldsymbol{{a}}}{\mathrm{2}}} \:\:\:\int_{\boldsymbol{{y}}} ^{\:\sqrt{\boldsymbol{{a}}^{\mathrm{2}} −\boldsymbol{{y}}^{\mathrm{2}} }} \:\boldsymbol{{x}}\:\boldsymbol{{dx}}\:\boldsymbol{{dy}}\:\:=\:\frac{\mathrm{5}\:\boldsymbol{{a}}^{\mathrm{3}} }{\mathrm{24}\:} \\ $$ Commented by…

Question-167547

Question Number 167547 by LEKOUMA last updated on 19/Mar/22 Commented by MJS_new last updated on 19/Mar/22 $$\mathrm{I}\:\mathrm{don}'\mathrm{t}\:\mathrm{think}\:\mathrm{this}\:\mathrm{can}\:\mathrm{be}\:\mathrm{solved}. \\ $$ Terms of Service Privacy Policy Contact:…