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show-that-A-B-A-B-

Question Number 167386 by MathsFan last updated on 15/Mar/22 $$\:\boldsymbol{{show}}\:\boldsymbol{{that}}\: \\ $$$$\:\left(\boldsymbol{{A}}\oplus\boldsymbol{{B}}\right)'\:=\:\boldsymbol{{A}}\:\cap\:\boldsymbol{{B}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

show-that-A-B-C-A-B-C-

Question Number 167380 by MathsFan last updated on 14/Mar/22 $$\:\boldsymbol{{show}}\:\boldsymbol{{that}} \\ $$$$\:\boldsymbol{{A}}'\:\cup\:\boldsymbol{{B}}'\:\cup\:\boldsymbol{{C}}'\:=\left(\boldsymbol{{A}}\cup\boldsymbol{{B}}\cup\boldsymbol{{C}}\right)' \\ $$ Commented by cortano1 last updated on 15/Mar/22 $$\mathrm{wrong} \\ $$ Commented…

0-e-pix-e-x-x-e-pix-1-e-x-1-dx-

Question Number 101828 by floor(10²Eta[1]) last updated on 05/Jul/20 $$\underset{\mathrm{0}} {\overset{\infty} {\int}}\frac{\mathrm{e}^{\pi\mathrm{x}} −\mathrm{e}^{\mathrm{x}} }{\mathrm{x}\left(\mathrm{e}^{\pi\mathrm{x}} +\mathrm{1}\right)\left(\mathrm{e}^{\mathrm{x}} +\mathrm{1}\right)}\mathrm{dx} \\ $$ Answered by maths mind last updated on…

dx-1-x-1-x-

Question Number 167360 by LEKOUMA last updated on 14/Mar/22 $$\int\frac{{dx}}{\mathrm{1}+\sqrt{{x}}+\sqrt{\mathrm{1}+{x}}} \\ $$ Answered by MJS_new last updated on 14/Mar/22 $$\int\frac{{dx}}{\mathrm{1}+\sqrt{{x}}+\sqrt{{x}+\mathrm{1}}}= \\ $$$$\:\:\:\:\:\left[{t}=\sqrt{{x}}+\sqrt{{x}+\mathrm{1}}\:\rightarrow\:{dx}=\frac{\left({t}−\mathrm{1}\right)\left({t}+\mathrm{1}\right)\left({t}^{\mathrm{2}} +\mathrm{1}\right)}{\mathrm{2}{t}^{\mathrm{3}} }{dt}\right] \\…

Question-101778

Question Number 101778 by mathocean1 last updated on 04/Jul/20 Answered by mr W last updated on 04/Jul/20 $${f}\left({x}\right)={P}\left({x}\right) \\ $$$$\frac{{x}^{\mathrm{2}} +\mathrm{4}{x}+\mathrm{1}}{{x}+\mathrm{1}}={x}^{\mathrm{2}} \\ $$$${x}^{\mathrm{3}} −\mathrm{4}{x}−\mathrm{1}=\mathrm{0} \\…

solve-3-x-2-4-x-6-6-

Question Number 167282 by abdurehime last updated on 11/Mar/22 $$\mathrm{solve}\:\left(\mathrm{3}^{\mathrm{x}} \right)^{\mathrm{2}} ×\mathrm{4}^{\mathrm{x}} =\mathrm{6}\sqrt{\mathrm{6}} \\ $$ Answered by nurtani last updated on 11/Mar/22 $$\left(\mathrm{3}^{{x}} \right)^{\mathrm{2}} ×\mathrm{4}^{{x}}…