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Version-2-091-is-available-Slightly-darker-characters-are-used-by-default-A-preference-setting-is-available-to-revert-to-previous-font-Change-setting-and-restart-app-A-new-menu

Question Number 101730 by Tinku Tara last updated on 04/Jul/20 $$\mathrm{Version}\:\mathrm{2}.\mathrm{091}\:\mathrm{is}\:\mathrm{available}: \\ $$$$-\:\mathrm{Slightly}\:\mathrm{darker}\:\mathrm{characters}\:\mathrm{are} \\ $$$$\:\:\:\:\mathrm{used}\:\mathrm{by}\:\mathrm{default}. \\ $$$$\:\:\:\:\mathrm{A}\:\mathrm{preference}\:\mathrm{setting}\:\mathrm{is}\:\mathrm{available} \\ $$$$\:\:\:\:\mathrm{to}\:\mathrm{revert}\:\mathrm{to}\:\mathrm{previous}\:\mathrm{font}. \\ $$$$\:\:\:\:\mathrm{Change}\:\mathrm{setting}\:\mathrm{and}\:\mathrm{restart}\:\mathrm{app}. \\ $$$$-\:\mathrm{A}\:\mathrm{new}\:\mathrm{menu}\:\mathrm{option}\:\mathrm{mark}\:\mathrm{as} \\ $$$$\:\:\:\mathrm{answered}\:\mathrm{is}\:\mathrm{added}.\:\mathrm{This}\:\mathrm{just}\:\mathrm{mark}…

Question-167252

Question Number 167252 by mkam last updated on 10/Mar/22 Answered by mr W last updated on 11/Mar/22 $$\frac{\partial{f}}{\partial{t}}=−\mathrm{2}{x}×{r}\:\mathrm{sin}\:{t}+\mathrm{2}{x}×{r}\:\mathrm{cos}\:{t}−\mathrm{2}{y}\:{r}\:\mathrm{sin}\:{t}+\mathrm{2}{y}×{r}\:\mathrm{cos}\:{t} \\ $$$$\frac{\partial{f}}{\partial{r}}=\mathrm{2}{x}×\mathrm{cos}\:{t}+\mathrm{2}{x}×\mathrm{sin}\:{t}+\mathrm{2}{y}\:\mathrm{cos}\:{t}+\mathrm{2}{y}×\mathrm{sin}\:{t} \\ $$ Terms of Service…

Deleted-a-few-comments-

Question Number 101715 by Tinku Tara last updated on 04/Jul/20 $$\mathrm{Deleted}\:\mathrm{a}\:\mathrm{few}\:\mathrm{comments}. \\ $$ Commented by mr W last updated on 04/Jul/20 $${sorry}\:{that}\:{this}\:{one}\:{single}\:{asshole}\:{has} \\ $$$${caused}\:{so}\:{much}\:{disturbance}\:{in}\:{the} \\…

lnx-x-1-dx-

Question Number 167233 by mkam last updated on 10/Mar/22 $$\int\:\frac{{lnx}}{{x}+\mathrm{1}}{dx} \\ $$ Answered by mindispower last updated on 10/Mar/22 $$={ln}\left({x}\right){ln}\left(\mathrm{1}+{x}\right)−\int\frac{{ln}\left(\mathrm{1}+{x}\right)}{{x}}{dx} \\ $$$$={ln}\left({x}\right){ln}\left(\mathrm{1}+{x}\right)−\int\frac{{ln}\left(\mathrm{1}−\left(−{x}\right)\right)}{−{x}}{d}\left(−{x}\right) \\ $$$$={ln}\left({x}\right){ln}\left(\mathrm{1}+{x}\right)+{Li}_{\mathrm{2}} \left(−{x}\right)+{c}…

Question-167220

Question Number 167220 by tabata last updated on 09/Mar/22 Answered by MikeH last updated on 10/Mar/22 $$\mid\mathrm{3}{x}−\mathrm{4}\mid\:\geqslant\:\mathrm{5} \\ $$$$\Rightarrow\:\mathrm{3}{x}−\mathrm{4}\:\leqslant\:−\mathrm{5}\:\mathrm{or}\:\mathrm{3}{x}−\mathrm{4}\:\geqslant\:\mathrm{5} \\ $$$$\Rightarrow\:{x}\:\leqslant−\frac{\mathrm{1}}{\mathrm{3}}\:\:\mathrm{or}\:{x}\:\geqslant\:\mathrm{3} \\ $$ Answered by…

What-is-the-set-of-point-M-in-each-case-1-6MG-2GC-2-6MG-2GC-0-

Question Number 101671 by mathocean1 last updated on 04/Jul/20 $${What}\:{is}\:{the}\:{set}\:{of}\:{point}\:{M}\:{in}\:{each} \\ $$$${case}: \\ $$$$\left.\mathrm{1}\right)\:\:\:\:\mid\mid\mathrm{6}\overset{\rightarrow} {{MG}}\mid\mid=\mid\mid−\mathrm{2}\overset{\rightarrow} {{GC}}\mid\mid \\ $$$$\left.\mathrm{2}\right)\:\:\:\:\left(\mathrm{6}\overset{\rightarrow} {{MG}}\right)×\left(−\mathrm{2}\overset{\rightarrow} {{GC}}\right)=\mathrm{0} \\ $$ Terms of Service…

Question-167202

Question Number 167202 by DAVONG last updated on 09/Mar/22 Answered by Rasheed.Sindhi last updated on 09/Mar/22 $$\mathrm{B}=\mathrm{3}+\mathrm{13}+\mathrm{31}+…+\left(\mathrm{4}{n}^{\mathrm{2}} −\mathrm{2}{n}+\mathrm{1}\right) \\ $$$$\mathrm{B}=\underset{{n}=\mathrm{1}} {\overset{{n}} {\sum}}\left(\mathrm{4}{n}^{\mathrm{2}} −\mathrm{2}{n}+\mathrm{1}\right) \\ $$$$=\mathrm{4}\underset{{n}=\mathrm{1}}…

solve-in-R-x-3-4x-1-0-

Question Number 101658 by mathocean1 last updated on 03/Jul/20 $${solve}\:{in}\:\mathbb{R} \\ $$$${x}^{\mathrm{3}} −\mathrm{4}{x}−\mathrm{1}=\mathrm{0} \\ $$ Answered by 1549442205 last updated on 04/Jul/20 $$\left(\mathrm{Please},\mathrm{get}\:\mathrm{his}\:\mathrm{permission}\:\mathrm{to}\:\mathrm{submit}\:\mathrm{the}\right. \\ $$$$\left.\mathrm{way}\:\mathrm{that}\:\mathrm{he}\:\mathrm{made}\:\mathrm{for}\:\mathrm{the}\:\mathrm{eqs}\:\mathrm{of}\:\mathrm{that}\:\mathrm{type}\:\right)…