Question Number 168585 by mkam last updated on 13/Apr/22 $${if}:\:{U}_{\mathrm{0}} =\mathrm{0}\:,\:{U}_{{n}+\mathrm{1}} \:=\:\left(\mathrm{2}{n}+\mathrm{2}\right){U}_{{n}} +\mathrm{2}{n}+\mathrm{1}\:{find}\:{U}_{{n}\:} \:? \\ $$ Commented by mr W last updated on 13/Apr/22 $${U}_{{n}}…
Question Number 37511 by MrW3 last updated on 14/Jun/18 $${To}\:{the}\:{developer}\:{of}\:{Tinku}\:{Tara}: \\ $$$${dear}\:{sir}:\:{for}\:{some}\:{unknown}\:{reasons} \\ $$$${I}\:{don}'{t}\:{get}\:{any}\:{notification}\:{from}\:{the} \\ $$$${app}\:{when}\:{a}\:{post},\:{in}\:{which}\:{I}\:{am}\:{involved}, \\ $$$${has}\:{been}\:{updated}.\:{Where}\:{is}\:{the} \\ $$$${problem}\:{and}\:{how}\:{can}\:{I}\:{solve}\:{it}? \\ $$$${Thank}\:{you}! \\ $$ Commented…
Question Number 168556 by mokys last updated on 13/Apr/22 $$\int\sqrt{{sinx}}\:{dx} \\ $$ Answered by MJS_new last updated on 13/Apr/22 $$\mathrm{this}\:\mathrm{question}\:\mathrm{keeps}\:\mathrm{reappearing};\:\mathrm{I}'\mathrm{ve}\:\mathrm{given} \\ $$$$\mathrm{the}\:\mathrm{answer}\:\mathrm{before}… \\ $$$$\int\sqrt{\mathrm{sin}\:{x}}\:{dx}=\int\sqrt{\mathrm{1}−\mathrm{sin}^{\mathrm{2}} \:\frac{\mathrm{2}{x}−\pi}{\mathrm{4}}}\:{dx}=…
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Question Number 102985 by DGmichael last updated on 12/Jul/20 Answered by mathmax by abdo last updated on 12/Jul/20 $$\mathrm{at}\:\mathrm{form}\:\mathrm{of}\:\mathrm{serie}\:\:\:\:\mathrm{let}\:\mathrm{f}\left(\mathrm{x}\right)\:=\int_{\mathrm{0}} ^{\mathrm{x}} \:\frac{\mathrm{e}^{\mathrm{t}} }{\left(\mathrm{1}+\mathrm{t}^{\mathrm{2}} \right)^{\mathrm{2}} }\mathrm{dt} \\…
Question Number 168519 by mokys last updated on 12/Apr/22 $$\int\:{x}^{{x}} \:{dx} \\ $$ Answered by Mathspace last updated on 12/Apr/22 $$\int\:{x}^{{x}} {dx}=\int\:{e}^{{xlnx}} {dx} \\ $$$$=\int\:\Sigma\:\frac{\left({xlnx}\right)^{{n}}…
Question Number 168510 by alephzero last updated on 12/Apr/22 $$\mathrm{Is}\:\mathrm{it}\:\mathrm{possible}\:\mathrm{to}\:\mathrm{express}\:{x}+{y}\:\mathrm{in} \\ $$$$\mathrm{terms}\:\mathrm{of}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} ? \\ $$ Commented by mr W last updated on 12/Apr/22 $${no}…
Question Number 168509 by stelor last updated on 12/Apr/22 $${hello}\:{everybody}\:\: \\ $$$${that}\:{is}\:{link}\:{for}\:{mathematics}\:{forum} \\ $$$$ \\ $$$$\mathrm{httpschat}.\mathrm{whatsapp}.\mathrm{comK8mwbIMlp4U5babIVrqVdw} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 168493 by mokys last updated on 11/Apr/22 Answered by FelipeLz last updated on 12/Apr/22 $$\begin{pmatrix}{{n}}\\{{r}}\end{pmatrix}−\begin{pmatrix}{{n}−\mathrm{1}}\\{{r}−\mathrm{1}}\end{pmatrix}\:=\:\frac{{n}!}{{r}!\left({n}−{r}\right)!}−\frac{\left({n}−\mathrm{1}\right)!}{\left({r}−\mathrm{1}\right)!\left({n}−{r}\right)!}\:=\:\frac{{n}!−{r}\left({n}−\mathrm{1}\right)!}{{r}!\left({n}−{r}\right)!}\:=\:\frac{\left({n}−{r}\right)\left({n}−\mathrm{1}\right)!}{{r}!\left({n}−{r}\right)!}\:=\:\frac{\left({n}−\mathrm{1}\right)!}{{r}!\left({n}−{r}−\mathrm{1}\right)!}\:=\:\frac{\left({n}−\mathrm{1}\right)!}{{r}!\left(\left({n}−\mathrm{1}\right)−{r}\right)!}\:=\:\begin{pmatrix}{{n}−\mathrm{1}}\\{\:\:\:\:\:{r}}\end{pmatrix} \\ $$ Terms of Service Privacy Policy Contact:…