Question Number 100899 by mhmd last updated on 29/Jun/20 $${find}\:{the}\:{fourier}\:{series}\:{of}\:{the}\:{function}\:{f}\left({x}\right)=\begin{cases}{{x}\:\:\:\:−\mathrm{2}\leqslant{x}\leqslant\mathrm{0}\:\:\:}\\{\mathrm{4}\:\:\:\:\:\:\:\:\:\:\mathrm{0}\leqslant{x}\leqslant\mathrm{2}}\end{cases}\:\:\:? \\ $$$${help}\:{me}\:{sir}\:? \\ $$ Answered by bramlex last updated on 29/Jun/20 $${f}\left({x}\right)\::\:{odd}\:{function}.\:{L}\:=\:\mathrm{4} \\ $$$${a}_{{n}} \:=\:\mathrm{0}\:…
Question Number 166424 by leicianocosta last updated on 20/Feb/22 Commented by cortano1 last updated on 20/Feb/22 $$\:\Rightarrow\mathrm{let}\:\mathrm{AB}=\mathrm{BC}=\mathrm{4} \\ $$$$\Rightarrow\mathrm{AC}=\mathrm{4}\sqrt{\mathrm{2}}\:\Rightarrow\mathrm{sin}\:\mathrm{30}°=\frac{\mathrm{CD}}{\:\mathrm{4}\sqrt{\mathrm{2}}} \\ $$$$\Rightarrow\mathrm{CD}=\mathrm{2}\sqrt{\mathrm{2}} \\ $$ Commented by…
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Question Number 166400 by naka3546 last updated on 20/Feb/22 $$\mathrm{Find}\:\:\mathrm{all}\:\:\mathrm{pairs}\:\:\mathrm{of}\:\:\mathrm{positive}\:\:\mathrm{integers}\:\left({a},{b}\right)\:\:\mathrm{such}\:\:\mathrm{that} \\ $$$$\:\:\:\:\:\:\frac{{a}^{\mathrm{2}} }{\mathrm{2}{ab}^{\mathrm{2}} \:−\:{b}^{\mathrm{3}} +\mathrm{1}}\:\:\in\:\:\mathbb{Z}^{+} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 166392 by leicianocosta last updated on 19/Feb/22 Answered by som(math1967) last updated on 19/Feb/22 $${n}=\mathrm{1} \\ $$$$\mathrm{3}^{\mathrm{4}} +\mathrm{2}^{\mathrm{7}} =\mathrm{81}+\mathrm{128}=\mathrm{209}=\mathrm{11}×\mathrm{19} \\ $$$${multiple}\:{of}\:\mathrm{11} \\ $$$$\:\mathrm{3}^{\mathrm{2}{m}+\mathrm{2}}…
Question Number 100843 by bachamohamed last updated on 28/Jun/20 $$\:\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\:\frac{\boldsymbol{{ln}}\left(\boldsymbol{{k}}\right)}{\boldsymbol{{k}}!}\:=\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 166378 by MathsFan last updated on 19/Feb/22 $$\:\mathrm{8}{x}^{\mathrm{3}} −\mathrm{6}{x}+\mathrm{1}=\mathrm{0} \\ $$$$\:{solve}\:{for}\:{x} \\ $$ Answered by mr W last updated on 19/Feb/22 $$\mathrm{3}{x}−\mathrm{4}{x}^{\mathrm{3}} =\frac{\mathrm{1}}{\mathrm{2}}…
Question Number 166379 by SANOGO last updated on 19/Feb/22 $${soit}\left\{_{{u}_{\mathrm{1}} =\mathrm{4}} ^{{u}_{{o}} =\mathrm{1}} \:\:\forall{n}\epsilon{N}\right. \\ $$$${montrer}\:{par}\:{reccurence}\:\:{que}: \\ $$$${U}_{{n}+\mathrm{2}} =\mathrm{2}{U}_{{n}+\mathrm{1}} −{U}_{{n}} \\ $$ Answered by qaz…
Question Number 166358 by leicianocosta last updated on 19/Feb/22 Answered by naka3546 last updated on 19/Feb/22 $$\frac{\mathrm{3a}^{\mathrm{2}} +\mathrm{5}}{\mathrm{a}^{\mathrm{2}} −\mathrm{1}}\:−\:\frac{\mathrm{3a}^{\mathrm{2}} +\mathrm{1}}{\mathrm{a}^{\mathrm{2}} −\mathrm{1}}\:<\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\frac{\mathrm{4}}{\mathrm{a}^{\mathrm{2}} −\mathrm{1}}\:<\:\mathrm{0} \\…
Question Number 166350 by mkam last updated on 18/Feb/22 Commented by mkam last updated on 18/Feb/22 $${how}\:{can}\:{it}\:{solve}\:{this}\:{proplem}\:{it}\:{is}\:{very}\:{hard}\:{helps}\:{me}\:? \\ $$ Answered by mahdipoor last updated on…