Question Number 101003 by bachamohamed last updated on 29/Jun/20 $$\:\boldsymbol{{What}}\:\boldsymbol{{is}}\:\boldsymbol{{the}}\:\boldsymbol{{value}}\:\boldsymbol{{of}}\:\boldsymbol{{x}}\:\boldsymbol{{for}}\:\boldsymbol{{wich}}\:\boldsymbol{{the}}\:\boldsymbol{{serie}}\:\boldsymbol{{is}}\:\boldsymbol{{converge}}?\:\:\:\:\:\:\:\:\: \\ $$$$\:\:\:\left(\mathrm{1}\right)\:\underset{\boldsymbol{{n}}\geqslant\mathrm{0}} {\sum}\boldsymbol{{x}}^{\frac{\boldsymbol{{ln}}\left(\boldsymbol{{n}}\right)}{\boldsymbol{{n}}!}} \:?\:\:\:\:\:\:\left(\mathrm{2}\right)\:\underset{\boldsymbol{{n}}\geqslant\mathrm{0}\:} {\sum}\boldsymbol{{x}}^{\frac{\boldsymbol{{ln}}\left(\boldsymbol{{n}}!\right)}{\boldsymbol{{n}}}} \:? \\ $$$$ \\ $$ Terms of Service Privacy Policy…
Question Number 166542 by abdurehime last updated on 22/Feb/22 Answered by Rasheed.Sindhi last updated on 22/Feb/22 $${n}\left({A}\right)=\left(\mathrm{2}{x}+{y}\right)+\left({x}+{y}\right)=\mathrm{3}{x}+\mathrm{2}{y}=\mathrm{13} \\ $$$${n}\left({B}\right)=\left(\mathrm{3}{y}−{x}\right)+\left({x}+{y}\right)=\mathrm{4}{y}=\mathrm{8} \\ $$$${y}=\mathrm{8}/\mathrm{4}=\mathrm{2}\Rightarrow\mathrm{3}{x}+\mathrm{2}\left(\mathrm{2}\right)=\mathrm{13}\Rightarrow{x}=\mathrm{3} \\ $$$$\left({a}\right)\:{n}\left({A}\cup{B}\right)=\left(\mathrm{2}{x}+{y}\right)+\left({x}+{y}\right)+\left(\mathrm{3}{y}−{x}\right) \\ $$$$\:\:\:\:\:\:\:=\mathrm{2}{x}+\mathrm{5}{y}=\mathrm{2}\left(\mathrm{3}\right)+\mathrm{5}\left(\mathrm{2}\right)=\mathrm{16}…
Question Number 101001 by mhmd last updated on 29/Jun/20 Answered by mr W last updated on 29/Jun/20 Commented by mr W last updated on 29/Jun/20…
Question Number 166539 by daus last updated on 22/Feb/22 $${solve}\:{the}\:{equation} \\ $$$${x}^{\mathrm{2}} +{xy}+{y}^{\mathrm{2}} =\mathrm{6}{x}^{\mathrm{2}} +{y}\: \\ $$$$\mathrm{2}{x}^{\mathrm{2}} +\mathrm{2}{xy}={y}^{\mathrm{2}} \\ $$ Commented by cortano1 last updated…
Question Number 166516 by naka3546 last updated on 21/Feb/22 $$\mathrm{Determine}\:\:\mathrm{the}\:\:\mathrm{formula}\:\:\mathrm{of}\:\:\mathrm{this}\:\:\mathrm{expression} \\ $$$$\:\:\:\underset{{k}=\mathrm{0}} {\overset{{n}} {\sum}}\:\frac{\mathrm{1}}{\left({n}−{k}\right)!\left({n}+{k}\right)!}\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 100980 by bachamohamed last updated on 29/Jun/20 $$\:\:\:\:{prove}\:{that}\:\:\int_{−\infty} ^{+\infty} \left(\frac{\mathrm{1}}{\mathrm{1}+\left(\boldsymbol{{x}}+\boldsymbol{{tan}}\left(\boldsymbol{{x}}\right)\right)^{\mathrm{2}} }\boldsymbol{{dx}}\right)=\boldsymbol{\pi}\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 100968 by bachamohamed last updated on 29/Jun/20 $$\:\:\:\:\:\:\underset{\mathrm{k}=\mathrm{1}} {\overset{\infty} {\sum}}\:\left(\mathrm{x}+\mathrm{k}\right)^{\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{k}+\mathrm{1}} }} =?\:\:\:\:\:\:\mathrm{x}>\mathrm{0}\: \\ $$ Answered by mathmax by abdo last updated on 29/Jun/20…
Question Number 166511 by mkam last updated on 21/Feb/22 $${is}\:{the}\:{function}\:{f}\left({x}\right)\:=\:{tan}^{−\mathrm{1}} \left({x}\right)\:+\:{tan}^{−\mathrm{1}} \left(\mathrm{2}{x}\right)\:+\:{tan}^{−\mathrm{1}} \left(\mathrm{3}{x}\right)\:+\:…..\: \\ $$$${converge}\:{or}\:{diverge}\:? \\ $$$$ \\ $$ Answered by alephzero last updated on…
Question Number 100966 by mhmd last updated on 29/Jun/20 $${find}\:{the}\:{fourier}\:{series}\:{of}\:{the}\:{function} \\ $$$${f}\left({x}\right)=\begin{cases}{{x}\:\:\:\:\:\:\:\:\:−\mathrm{2}\leqslant{x}\leqslant\mathrm{0}}\\{{x}+\mathrm{2}\:\:\:\:\:\:\:\:\mathrm{0}\leqslant{x}\leqslant\mathrm{2}}\end{cases}\:\:\:\:\:\:{help}\:{me}\:{sir}\:? \\ $$ Commented by bobhans last updated on 29/Jun/20 $$\mathrm{f}\left(\mathrm{x}\right)\:=\:\frac{\mathrm{a}_{\mathrm{o}} }{\mathrm{2}}\:+\:\underset{\mathrm{n}=\mathrm{1}} {\overset{\infty} {\sum}}\:\mathrm{b}_{\mathrm{n}}…
Question Number 35412 by mondodotto@gmail.com last updated on 18/May/18 $$\boldsymbol{\mathrm{evaluate}}\:\int\sqrt{\left(\boldsymbol{\mathrm{t}}^{\mathrm{2}} +\mathrm{1}+\frac{\mathrm{3}}{\mathrm{4}}\boldsymbol{\mathrm{t}}\right)}\:\boldsymbol{\mathrm{dt}} \\ $$ Commented by prof Abdo imad last updated on 19/May/18 $${let}\:{put}\:{I}\:=\:\int\:\:\sqrt{{t}^{\mathrm{2}} +\frac{\mathrm{3}}{\mathrm{4}}{t}\:+\mathrm{1}}\:{dt} \\…