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Question Number 164266 by naka3546 last updated on 15/Jan/22 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\:\left({x}−\mathrm{2}\right)\:−\:\sqrt{{x}^{\mathrm{2}} +\mathrm{2}{x}−\mathrm{5}}\:\:=\:\:? \\ $$ Answered by ajfour last updated on 15/Jan/22 $${x}=\frac{\mathrm{1}}{{h}}\rightarrow\infty \\ $$$${L}=\underset{{h}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{1}−\mathrm{2}{h}−\left(\mathrm{1}+\mathrm{2}{h}−\mathrm{5}{h}^{\mathrm{2}}…
Question Number 98723 by Tinku Tara last updated on 15/Jun/20 $$\mathrm{Version}\:\mathrm{2}.\mathrm{084}\:\mathrm{has}\:\mathrm{fixes}\:\mathrm{for}\:\mathrm{all} \\ $$$$\mathrm{crashes}\:\mathrm{which}\:\mathrm{were}\:\mathrm{reported}\:\mathrm{on} \\ $$$$\mathrm{playstore}\:\mathrm{in}\:\mathrm{last}\:\mathrm{week}. \\ $$$$\mathrm{If}\:\mathrm{anyone}\:\mathrm{is}\:\mathrm{facing}\:\mathrm{crashes}\:\mathrm{please} \\ $$$$\mathrm{update}\:\mathrm{to}\:\mathrm{v2}.\mathrm{084}\:\mathrm{and}\:\mathrm{see}\:\mathrm{if}\:\mathrm{the}\: \\ $$$$\mathrm{problem}\:\mathrm{is}\:\mathrm{solved}. \\ $$$$\mathrm{If}\:\mathrm{the}\:\mathrm{problem}\:\mathrm{is}\:\mathrm{still}\:\mathrm{present},\:\mathrm{please} \\ $$$$\mathrm{send}\:\mathrm{us}\:\mathrm{an}\:\mathrm{email}\:\mathrm{as}\:\mathrm{the}\:\mathrm{problem}…
Question Number 164237 by DAVONG last updated on 15/Jan/22 Answered by mathmax by abdo last updated on 15/Jan/22 $$=\mathrm{lim}_{\mathrm{x}\rightarrow−\mathrm{1}} \:\:\:\:\frac{\mathrm{nx}^{\mathrm{n}−\mathrm{1}} −\mathrm{n}}{\mathrm{2}\left(\mathrm{x}+\mathrm{1}\right)}\:=\mathrm{lim}_{\mathrm{x}\rightarrow−\mathrm{1}} \frac{\mathrm{n}\left(\mathrm{n}−\mathrm{1}\right)\mathrm{x}^{\mathrm{n}−\mathrm{2}} }{\mathrm{2}}=\frac{\mathrm{n}\left(\mathrm{n}−\mathrm{1}\right)}{\mathrm{2}} \\ $$$$\left(\mathrm{hospital}\:\mathrm{2times}\right)…
Question Number 164236 by DAVONG last updated on 15/Jan/22 Commented by DAVONG last updated on 15/Jan/22 $$\mathrm{Helpe}\:\mathrm{pleasd}\:\mathrm{sir} \\ $$ Answered by Kamel last updated on…
Question Number 98690 by abony1303 last updated on 15/Jun/20 Commented by abony1303 last updated on 15/Jun/20 $$\mathrm{pls}\:\mathrm{help} \\ $$ Commented by PRITHWISH SEN 2 last…
Question Number 164227 by SANOGO last updated on 15/Jan/22 Answered by TheSupreme last updated on 15/Jan/22 $$\begin{vmatrix}{\mathrm{4}}&{\mathrm{6}}&{\mathrm{0}}\\{−\mathrm{3}}&{−\mathrm{5}}&{\mathrm{0}}\\{−\mathrm{3}}&{−\mathrm{6}}&{−\mathrm{5}}\end{vmatrix}−\lambda\begin{bmatrix}{\mathrm{1}}&{\mathrm{0}}&{\mathrm{0}}\\{\mathrm{0}}&{\mathrm{1}}&{\mathrm{0}}\\{\mathrm{0}}&{\mathrm{0}}&{\mathrm{1}}\end{bmatrix}\left\{\begin{matrix}{{x}}\\{{y}}\\{{z}}\end{matrix}\right\}=\left\{\begin{matrix}{\mathrm{0}}\\{\mathrm{0}}\\{\mathrm{0}}\end{matrix}\right\} \\ $$$${det}\left({A}−\lambda{I}\right)=\mathrm{0} \\ $$$$\left[\left(\mathrm{4}−\lambda\right)\left(−\mathrm{5}−\lambda\right)+\mathrm{18}\right]\left(−\mathrm{5}−\lambda\right)=\mathrm{0} \\ $$$$\left[−\mathrm{20}−\mathrm{4}\lambda+\mathrm{5}\lambda+\lambda^{\mathrm{2}} +\mathrm{18}\right]\left(−\mathrm{5}−\lambda\right)=\mathrm{0} \\…
Question Number 33151 by naka3546 last updated on 11/Apr/18 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 98687 by abony1303 last updated on 15/Jun/20 Commented by abony1303 last updated on 15/Jun/20 $$\mathrm{pls}\:\mathrm{help} \\ $$ Commented by MWSuSon last updated on…
Question Number 98678 by PRITHWISH SEN 2 last updated on 15/Jun/20 $$\int_{\mathrm{0}} ^{\infty} \boldsymbol{\mathrm{e}}^{−\boldsymbol{\mathrm{ax}}} \frac{\mathrm{sin}\:\boldsymbol{\mathrm{mx}}}{\boldsymbol{\mathrm{x}}}\:\boldsymbol{\mathrm{dx}}\:=\:\mathrm{tan}^{−\mathrm{1}} \left(\frac{\boldsymbol{\mathrm{m}}}{\boldsymbol{\mathrm{a}}}\right),\:\boldsymbol{\mathrm{a}}>\mathrm{0} \\ $$ Commented by Tinku Tara last updated on…