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Question-32965

Question Number 32965 by naka3546 last updated on 08/Apr/18 Commented by MJS last updated on 08/Apr/18 $${x}=\mathrm{30}° \\ $$$$\mathrm{found}\:\mathrm{this}\:\mathrm{by}\:\mathrm{setting}\:{BC}=\mathrm{1}\:\mathrm{and} \\ $$$$\mathrm{calculating}\:\mathrm{all}\:\mathrm{obvious}\:\mathrm{angles} \\ $$$$\mathrm{and}\:\mathrm{then}\:\mathrm{all}\:\mathrm{sides}\:\mathrm{one}\:\mathrm{by}\:\mathrm{one}\:\mathrm{using} \\ $$$$\frac{\mathrm{sin}\:\alpha}{{a}}=\frac{\mathrm{sin}\:\beta}{{b}}=\frac{\mathrm{sin}\:\gamma}{{c}}…

log-2-x-log-4-x-log-16-x-7-

Question Number 32960 by mondodotto@gmail.com last updated on 08/Apr/18 $$\:\boldsymbol{\mathrm{log}}_{\mathrm{2}} \boldsymbol{{x}}+\boldsymbol{\mathrm{log}}_{\mathrm{4}} \boldsymbol{{x}}+\boldsymbol{\mathrm{log}}_{\mathrm{16}} \boldsymbol{{x}}=\mathrm{7} \\ $$ Answered by Joel578 last updated on 08/Apr/18 $$\mathrm{log}_{{a}^{{n}} } \:{b}^{{m}}…

log-2-x-log-4-x-log-16-x-7-help-

Question Number 32954 by mondodotto@gmail.com last updated on 07/Apr/18 $$\:\boldsymbol{\mathrm{log}}_{\mathrm{2}} \boldsymbol{{x}}×\boldsymbol{\mathrm{log}}_{\mathrm{4}} \boldsymbol{{x}}×\boldsymbol{\mathrm{log}}_{\mathrm{16}} \boldsymbol{{x}}=\mathrm{7} \\ $$$$\:\boldsymbol{{help}} \\ $$ Answered by MJS last updated on 08/Apr/18 $$\mathrm{log}_{\mathrm{2}}…

Question-32946

Question Number 32946 by jasno91 last updated on 07/Apr/18 Answered by Rasheed.Sindhi last updated on 07/Apr/18 $$\frac{−\mathrm{36}}{\mathrm{24}}=\frac{−\mathrm{36}/\mathrm{4}}{\mathrm{24}/\mathrm{4}}=\frac{−\mathrm{9}}{\mathrm{6}} \\ $$ Terms of Service Privacy Policy Contact:…

Question-32947

Question Number 32947 by jasno91 last updated on 07/Apr/18 Answered by Rasheed.Sindhi last updated on 07/Apr/18 $$\frac{−\mathrm{1}}{\mathrm{8}}=\frac{\mathrm{8}}{\mathrm{x}} \\ $$$$−\mathrm{x}=\mathrm{8}×\mathrm{8} \\ $$$$\mathrm{x}=−\mathrm{64} \\ $$ Terms of…

Question-32945

Question Number 32945 by jasno91 last updated on 07/Apr/18 Answered by Rasheed.Sindhi last updated on 07/Apr/18 $$\left(\mathrm{i}\right)\:\:\:\frac{\mathrm{5}}{\mathrm{8}}=\frac{\mathrm{5}×\mathrm{3}}{\mathrm{8}×\mathrm{3}}=\frac{\mathrm{15}}{\mathrm{24}} \\ $$$$\left(\mathrm{ii}\right)\:\frac{\mathrm{5}}{\mathrm{8}}=\frac{\mathrm{5}×−\mathrm{2}}{\mathrm{8}×−\mathrm{2}}=\frac{−\mathrm{10}}{−\mathrm{16}} \\ $$ Terms of Service Privacy…