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Question-32379

Question Number 32379 by mondodotto@gmail.com last updated on 24/Mar/18 Answered by MJS last updated on 24/Mar/18 $$\left({a}−{b}\right)^{\mathrm{5}} ={a}^{\mathrm{5}} −\mathrm{5}{a}^{\mathrm{4}} {b}+\mathrm{10}{a}^{\mathrm{3}} {b}^{\mathrm{2}} −\mathrm{10}{a}^{\mathrm{2}} {b}^{\mathrm{3}} +\mathrm{5}{ab}^{\mathrm{4}} −{b}^{\mathrm{5}}…

x-3-x-1-4-dx-x-1-3-x-1-4-dx-1-x-1-3-dx-3-1-x-1-4-dx-

Question Number 163441 by vishal1234 last updated on 07/Jan/22 $$\int\frac{{x}+\mathrm{3}}{\left({x}+\mathrm{1}\right)^{\mathrm{4}} }{dx}=\int\frac{{x}+\mathrm{1}+\mathrm{3}}{\left({x}+\mathrm{1}\right)^{\mathrm{4}} }{dx}=\int\frac{\mathrm{1}}{\left({x}+\mathrm{1}\right)^{\mathrm{3}} }{dx}+\mathrm{3}\int\frac{\mathrm{1}}{\left({x}+\mathrm{1}\right)^{\mathrm{4}} }{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

0-1-x-1-10-x-3-3-dx-

Question Number 163402 by Ahmed777hamouda last updated on 06/Jan/22 $$\:\:\:\:\:\:\int_{\mathrm{0}} ^{\mathrm{1}} \left(\boldsymbol{{x}}−\mathrm{1}\right)^{\mathrm{10}} \left(\boldsymbol{{x}}−\mathrm{3}\right)^{\mathrm{3}} \boldsymbol{{dx}} \\ $$ Answered by Ar Brandon last updated on 06/Jan/22 $${I}=\int_{\mathrm{0}}…

Question-163393

Question Number 163393 by nurtani last updated on 06/Jan/22 Answered by Ar Brandon last updated on 06/Jan/22 $$\left[\frac{\mathrm{1}}{\mathrm{2}}\centerdot\frac{\mathrm{3}}{\mathrm{4}}\left(\mathrm{2}{x}−\mathrm{1}\right)^{\frac{\mathrm{4}}{\mathrm{3}}} −\frac{\mathrm{1}}{\pi}\mathrm{cos}\pi{x}\right]_{\mathrm{1}/\mathrm{2}} ^{\mathrm{1}} \\ $$ Terms of Service…