Question Number 34328 by mondodotto@gmail.com last updated on 04/May/18 $$\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{for}}\:\boldsymbol{{x}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{{y}} \\ $$$$\left(\boldsymbol{\mathrm{i}}\right)\:\mathrm{2}^{\boldsymbol{{x}}−\mathrm{1}} .\mathrm{3}^{\boldsymbol{{y}}+\mathrm{1}} =\mathrm{25} \\ $$$$\left(\boldsymbol{\mathrm{ii}}\right)\mathrm{2}^{\boldsymbol{{n}}−\mathrm{1}} .\mathrm{3}^{\boldsymbol{{m}}+\mathrm{1}} =\mathrm{113} \\ $$ Commented by Amstrongmazoka last updated…
Question Number 165383 by naka3546 last updated on 01/Feb/22 $${Find}\:\:{the}\:\:{value}\:\:{of}\:\:{this}\:\:{expression} \\ $$$$\left(−\mathrm{1}\right)\left(\mathrm{2}^{\mathrm{2}} −\mathrm{1}\right)+\frac{\left(\mathrm{3}^{\mathrm{2}} −\mathrm{2}\right)}{\mathrm{2}!}\:−\:\frac{\left(\mathrm{4}^{\mathrm{2}} −\mathrm{3}\right)}{\mathrm{3}!}\:+\:\ldots+\:\frac{\left(\mathrm{2019}^{\mathrm{2}} −\mathrm{2018}\right)}{\mathrm{2018}!} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 165349 by mkam last updated on 31/Jan/22 Answered by puissant last updated on 31/Jan/22 $$\frac{\mathrm{1}}{\mathrm{2}{n}^{\mathrm{2}} }\:=\:\frac{\left(\mathrm{2}{n}+\mathrm{1}\right)−\left(\mathrm{2}{n}−\mathrm{1}\right)}{\mathrm{1}+\left(\mathrm{2}{n}+\mathrm{1}\right)\left(\mathrm{2}{n}−\mathrm{1}\right)} \\ $$$$\Rightarrow\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}{arctan}\left(\frac{\mathrm{1}}{\mathrm{2}{n}^{\mathrm{2}} }\right)=\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\left\{{arctan}\left(\mathrm{2}{n}+\mathrm{1}\right)−{arctan}\left(\mathrm{2}{n}−\mathrm{1}\right)\right\}…
Question Number 99772 by Tinku Tara last updated on 23/Jun/20 $$\mathrm{Apk}\:\mathrm{file}\:\mathrm{for}\:\mathrm{upcoming}\:\mathrm{version} \\ $$$$\mathrm{with}\:\mathrm{shape}\:\mathrm{editing}\:\mathrm{is}\:\mathrm{available}. \\ $$ Commented by john santu last updated on 23/Jun/20 $$\mathrm{Tinku}\:\mathrm{Tara}\:\mathrm{math}\:\mathrm{Editor}\:\mathrm{Afdoll} \\…
Question Number 99766 by pranavdangi last updated on 23/Jun/20 $${my}\:{Quistion} \\ $$$${represnt}\:{these}\:{number}\:\:{on}\:\:{the}\:{number}\:\:{line}\:\left(\mathrm{1}\right)\mathrm{7}/\mathrm{4}\:\left(\mathrm{2}\right)−\mathrm{5}/\mathrm{6} \\ $$ Commented by pranavdangi last updated on 23/Jun/20 $${plese}\:{answer}\:{my}\:{question} \\ $$ Commented…
Question Number 165301 by mathdave last updated on 28/Jan/22 Answered by som(math1967) last updated on 29/Jan/22 $$\mathrm{1}.\boldsymbol{{No}}\:\boldsymbol{{of}}\:\boldsymbol{{ways}}\:'\boldsymbol{{median}}'\:\boldsymbol{{be}}\:\boldsymbol{{arranged}} \\ $$$$\:\mathrm{6}!=\mathrm{720} \\ $$$$\mathrm{2}.\:\boldsymbol{{M}}\:\boldsymbol{{begin}} \\ $$$$\:\boldsymbol{{M}}\:\Box\Box\Box\Box\Box\:^{\mathrm{5}} \boldsymbol{{P}}_{\mathrm{5}} =\mathrm{120}…
Question Number 165262 by mkam last updated on 28/Jan/22 $$\boldsymbol{{find}}\:\boldsymbol{{the}}\:\boldsymbol{{sum}}\:\underset{\boldsymbol{{n}}=\mathrm{1}} {\overset{\infty} {\sum}}\:\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\boldsymbol{{n}}} \:+\:\boldsymbol{{i}}\:\left(\:\frac{\mathrm{1}}{\mathrm{3}}\:\right)^{\boldsymbol{{n}}} \: \\ $$ Answered by Mathspace last updated on 28/Jan/22 $$\left.\sum_{{n}=\mathrm{1}} ^{\infty}…
Question Number 165253 by LEKOUMA last updated on 28/Jan/22 Answered by mindispower last updated on 28/Jan/22 $${sin}\left({x}\right)={x}−\frac{{x}^{\mathrm{3}} }{\mathrm{6}}+{o}\left({x}^{\mathrm{3}} \right) \\ $$ Answered by cortano1 last…
Question Number 99709 by Harasanemanabrandah last updated on 22/Jun/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 165240 by SANOGO last updated on 28/Jan/22 $$\:{soit}\:{la}\:{serie}\:{de}\:{fonction}\:\underset{{n}=\mathrm{2}\:\:\:} {\sum}\frac{{x}^{{n}} }{{nx}+{ln}\left({n}\right)} \\ $$$${etudie}\:{la}\:{convergence}\:{simple}\:{sur}\:\left[\mathrm{0},\mathrm{1}\left[\right.\right. \\ $$ Answered by mindispower last updated on 28/Jan/22 $$\forall{a}\in\left[\mathrm{0},\mathrm{1}\right] \\…