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Question Number 33103 by mondodotto@gmail.com last updated on 10/Apr/18 Commented by Rasheed.Sindhi last updated on 10/Apr/18 $$\mathrm{x}=\mathrm{y}=\mathrm{z}=\mathrm{0} \\ $$$$\mathrm{In}\:\mathrm{this}\:\mathrm{case}\:\mathrm{y}\neq\frac{\mathrm{2xz}}{\mathrm{x}+\mathrm{z}} \\ $$ Answered by MJS last…
Question Number 33100 by artibunja last updated on 10/Apr/18 Answered by MJS last updated on 10/Apr/18 $$\mathrm{48}{x}^{\mathrm{2}} −\mathrm{8}{x}−\mathrm{8}>\mathrm{0}\:\Rightarrow \\ $$$$\Rightarrow\:{x}<−\frac{\mathrm{1}}{\mathrm{3}}\vee{x}>\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\mathrm{42}{x}^{\mathrm{2}} +\mathrm{34}{x}−\mathrm{8}>\mathrm{0}\:\Rightarrow \\ $$$$\Rightarrow\:{x}<−\mathrm{1}\vee{x}>\frac{\mathrm{4}}{\mathrm{21}}…
Question Number 164171 by mkam last updated on 15/Jan/22 $$\int\:\frac{{dx}}{\mathrm{1}+{x}^{\mathrm{10}} } \\ $$ Answered by Ar Brandon last updated on 15/Jan/22 $$\int\frac{{dx}}{\mathrm{1}+{x}^{\mathrm{10}} }=\int\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\left(−{x}^{\mathrm{10}}…
Question Number 33090 by jasno91 last updated on 10/Apr/18 Answered by MJS last updated on 10/Apr/18 $${gcd}\left(\mathrm{663};\mathrm{975}\right)= \\ $$$$={gcd}\left(\mathrm{3}×\mathrm{13}×\mathrm{17};\mathrm{3}×\mathrm{5}^{\mathrm{2}} ×\mathrm{13}\right)= \\ $$$$=\mathrm{39} \\ $$$$ \\…
Question Number 33089 by mondodotto@gmail.com last updated on 10/Apr/18 $$\:\boldsymbol{\mathrm{T}}\mathrm{he}\:\boldsymbol{\mathrm{LCM}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{GCF}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{three}}\:\boldsymbol{\mathrm{numbers}}\:\boldsymbol{\mathrm{is}} \\ $$$$\:\mathrm{360}\:\boldsymbol{\mathrm{and}}\:\mathrm{6}\:\boldsymbol{\mathrm{respectively}}.\:\boldsymbol{\mathrm{if}}\:\boldsymbol{\mathrm{the}} \\ $$$$\:\boldsymbol{\mathrm{two}}\:\boldsymbol{\mathrm{numbers}}\:\boldsymbol{\mathrm{are}}\:\mathrm{18}\:\boldsymbol{\mathrm{and}}\:\mathrm{60}. \\ $$$$\:\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{third}}\:\boldsymbol{\mathrm{number}}. \\ $$ Commented by Rasheed.Sindhi last updated on 10/Apr/18…
Question Number 98618 by Ar Brandon last updated on 15/Jun/20 Answered by Ar Brandon last updated on 15/Jun/20 Commented by mr W last updated on…
Question Number 98621 by abony1303 last updated on 15/Jun/20 Commented by abony1303 last updated on 15/Jun/20 $$\mathrm{pls}\:\mathrm{help} \\ $$ Answered by mr W last updated…
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Question Number 164138 by LEKOUMA last updated on 14/Jan/22 Answered by floor(10²Eta[1]) last updated on 14/Jan/22 $$\mathrm{L}=\mathrm{lim}\left(…\right) \\ $$$$\mathrm{lnL}=\mathrm{lim}\left(\frac{\mathrm{x}+\mathrm{1}}{\mathrm{x}^{\mathrm{2}} +\mathrm{1}}\right).\mathrm{ln}\left(\mathrm{lim}\left(\frac{\mathrm{x}^{\mathrm{3}} +\mathrm{5}}{\mathrm{x}^{\mathrm{2}} +\mathrm{2}}\right)\right) \\ $$$$=\frac{\mathrm{lim}\left(\mathrm{ln}\left(\frac{\mathrm{x}^{\mathrm{3}} +\mathrm{5}}{\mathrm{x}^{\mathrm{2}}…