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Question-163110

Question Number 163110 by ampomahlosotho last updated on 03/Jan/22 Answered by mahdipoor last updated on 03/Jan/22 $$\mathrm{2}^{{x}−\mathrm{2}} =\mathrm{8}{x}\Rightarrow\frac{\mathrm{1}}{\mathrm{32}}\mathrm{2}^{{x}} ={x}\Rightarrow−\frac{\mathrm{1}}{\mathrm{32}×{ln}\mathrm{2}}=\left(−\frac{{x}}{{ln}\mathrm{2}}\right)\mathrm{2}^{\left(−{x}\right)} = \\ $$$$\left(−\frac{{x}}{{ln}\mathrm{2}}\right)\mathrm{2}^{{ln}\mathrm{2}×\frac{−{x}}{{ln}\mathrm{2}}} =\left(−\frac{{x}}{{ln}\mathrm{2}}\right){e}^{\left(\frac{−{x}}{{ln}\mathrm{2}}\right)} \Rightarrow \\…

Find-all-the-triples-of-positive-integers-x-y-z-so-that-x-y-2020-y-z-2020-is-a-rational-number-and-x-2-y-2-z-2-be-a-prime-number-

Question Number 97554 by 1549442205 last updated on 08/Jun/20 $$\mathrm{Find}\:\mathrm{all}\:\mathrm{the}\:\mathrm{triples}\:\mathrm{of}\:\mathrm{positive}\:\mathrm{integers}\:\left(\mathrm{x};\mathrm{y};\mathrm{z}\right) \\ $$$$\mathrm{so}\:\mathrm{that}\:\frac{\mathrm{x}−\mathrm{y}\sqrt{\mathrm{2020}}}{\mathrm{y}−\mathrm{z}\sqrt{\mathrm{2020}}}\:\mathrm{is}\:\mathrm{a}\:\mathrm{rational}\:\mathrm{number} \\ $$$$\mathrm{and}\:\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{z}^{\mathrm{2}} \mathrm{be}\:\mathrm{a}\:\mathrm{prime}\:\mathrm{number}. \\ $$ Commented by Rasheed.Sindhi last updated on…

Question-31954

Question Number 31954 by mondodotto@gmail.com last updated on 17/Mar/18 Answered by mrW2 last updated on 18/Mar/18 $${A}={A}_{\mathrm{0}} {e}^{−\lambda{t}} \\ $$$$\mathrm{0}.\mathrm{5}{A}_{\mathrm{0}} ={A}_{\mathrm{0}} {e}^{−\mathrm{15}\lambda} \\ $$$$\Rightarrow\lambda=\frac{\mathrm{ln}\:\mathrm{2}}{\mathrm{15}} \\…