Question Number 199854 by sonukgindia last updated on 10/Nov/23 Answered by aleks041103 last updated on 10/Nov/23 $${every}\:{fold}\:{is}\:{done}\:{at}\:{the}\:{angle}\:{bisector} \\ $$$$\Rightarrow{final}\:{accute}\:{angle}=\mathrm{90}°/\mathrm{4}=\mathrm{22}.\mathrm{5}° \\ $$$${S}=\mathrm{8}×\mathrm{6}−\mathrm{2}×\frac{\mathrm{3}×\left(\frac{\mathrm{3}}{{tan}\left(\mathrm{22}.\mathrm{5}°\right)}\right)}{\mathrm{2}}= \\ $$$$=\mathrm{48}−\mathrm{9}{cot}\left(\frac{\mathrm{45}°}{\mathrm{2}}\right)=\mathrm{48}−\mathrm{9}{cot}\left({x}\right)=\mathrm{48}−\mathrm{9}{z} \\ $$$$…
Question Number 199783 by majidghafari66 last updated on 09/Nov/23 $$\int{xdx}=? \\ $$ Answered by mathfreak01 last updated on 09/Nov/23 $$\frac{{x}^{\mathrm{2}} }{\mathrm{2}}\:+{C} \\ $$ Terms of…
Question Number 199708 by tri26112004 last updated on 08/Nov/23 $${n}^{\mathrm{20}} +\mathrm{11}^{{n}} =\mathrm{2023}\:\left({n}\in{N}\right) \\ $$$${n}=¿ \\ $$ Commented by Rasheed.Sindhi last updated on 08/Nov/23 $${f}\left({n}\right)={n}^{\mathrm{20}} +\mathrm{11}^{{n}}…
Question Number 199736 by MathedUp last updated on 08/Nov/23 $$\int\int_{\:\boldsymbol{\mathcal{S}}} \:\hat {\boldsymbol{\mathrm{F}}}\centerdot\mathrm{d}\hat {\boldsymbol{\mathrm{S}}} \\ $$$$\hat {\boldsymbol{\mathrm{F}}}=−{yz}\hat {\boldsymbol{\mathrm{e}}}_{\mathrm{1}} −{xz}\hat {\boldsymbol{\mathrm{e}}}_{\mathrm{2}} −{xy}\boldsymbol{\mathrm{e}}_{\mathrm{3}} \: \\ $$$$\hat {\boldsymbol{\mathrm{S}}};\:\begin{pmatrix}{\hat {{x}}}\\{\hat…
Question Number 199738 by sonukgindia last updated on 08/Nov/23 Answered by AST last updated on 08/Nov/23 $$\frac{{sin}\left({x}\right)}{{DB}}=\frac{{sin}\left(\alpha\right)}{{BC}};\frac{{sin}\left(\mathrm{2}{x}\right)}{{BE}={DB}}=\frac{{sinCEB}={sin}\left(\mathrm{90}+{x}\right)}{{BC}} \\ $$$$\Rightarrow\frac{{DB}}{{BC}}=\frac{{sin}\left({x}\right)}{{sin}\left(\alpha\right)}=\frac{{sin}\left(\mathrm{2}{x}\right)}{{sin}\left(\mathrm{90}+{x}\right)} \\ $$$$\Rightarrow{sin}\left(\alpha\right)=\frac{{sin}\left({x}\right)\left[{sin}\mathrm{90}{cosx}\right]}{\mathrm{2}{sinxcosx}}=\frac{\mathrm{1}}{\mathrm{2}}\Rightarrow\alpha=\mathrm{30}° \\ $$ Commented by…
Question Number 199707 by SANOGO last updated on 08/Nov/23 $${study}\:{the}\:{convergence} \\ $$$$\underset{{n}\geqslant{o}} {\overset{} {\sum}}{sin}\left(\pi\sqrt{\mathrm{4}{n}^{\mathrm{2}} +\mathrm{2}\:\:\:\:}\right. \\ $$ Answered by witcher3 last updated on 09/Nov/23 $$\sqrt{\mathrm{4n}^{\mathrm{2}}…
Question Number 199753 by sonukgindia last updated on 08/Nov/23 Answered by MM42 last updated on 09/Nov/23 $${let}\:\::\:\:{f}={xsinx}+{cosx}\:\:\&\:\:{g}={xcosx}+{sinx} \\ $$$${f}={g}\:\:\overset{\mathrm{0}\leqslant{x}\leqslant\mathrm{1}} {\Rightarrow}\:{x}=\mathrm{1}\:,\frac{\pi}{\mathrm{4}} \\ $$$$\Rightarrow{s}=\mid\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \left({f}−{g}\right){dx}\mid+\mid\int_{\frac{\pi}{\mathrm{4}}} ^{\mathrm{1}}…
Question Number 199719 by sonukgindia last updated on 08/Nov/23 Answered by witcher3 last updated on 08/Nov/23 $$\mathrm{I}_{\mathrm{a}} =\mathrm{I}_{\mathrm{b}} \\ $$$$\mathrm{I}_{\mathrm{a}} =\int_{\mathrm{0}} ^{\pi} \mathrm{e}^{\mathrm{sin}\left(\mathrm{x}\right)} \mathrm{cos}\left(\mathrm{cos}\left(\mathrm{x}\right)\right)\mathrm{dx}+\int_{\pi} ^{\mathrm{2}\pi}…
Question Number 199666 by sonukgindia last updated on 07/Nov/23 Answered by witcher3 last updated on 07/Nov/23 $$\mathrm{I}=\int_{\mathrm{0}} ^{\infty} \frac{\mathrm{x}^{\mathrm{a}} }{\mathrm{1}+\mathrm{x}^{\mathrm{b}} }\mathrm{dx}\:\mathrm{x}\rightarrow\mathrm{0}\:\frac{\mathrm{x}^{\mathrm{a}} }{\mathrm{1}+\mathrm{x}^{\mathrm{b}} }\sim\mathrm{x}^{\mathrm{a}} \:\mathrm{cv}\:\mathrm{if}\:\mathrm{only}\:\mathrm{if}?\mathrm{a}>−\mathrm{1}..\mathrm{true} \\…
Question Number 199686 by MathedUp last updated on 07/Nov/23 $${Can}\:{you}\:{help}\:{me}..???\:{pls}…. \\ $$$$\: \\ $$$$\: \\ $$$$\mathrm{Evaluate}\:\int\int_{\:\boldsymbol{\mathcal{S}}} \:\hat {\boldsymbol{\mathrm{F}}}\centerdot\mathrm{d}\hat {\boldsymbol{\mathrm{S}}} \\ $$$$\mathrm{Parametric}\:\mathrm{Surface} \\ $$$$\hat {\boldsymbol{\mathrm{S}}}\left({u},{v}\right)=\left(\mathrm{2}+\mathrm{sin}\left({u}\right)\right)\mathrm{cos}\left({v}\right)\hat {\boldsymbol{\mathrm{e}}}_{\mathrm{1}}…