Question Number 97157 by mhmd last updated on 06/Jun/20 Commented by mhmd last updated on 06/Jun/20 $${sir}\:{please}\:{help}\:{me}\:{i}\:{want}\:{Ex}\left(\mathrm{3}\right)\:{and}\:{Ex}\left(\mathrm{4}\right) \\ $$ Answered by Sourav mridha last updated…
Question Number 31611 by mondodotto@gmail.com last updated on 11/Mar/18 Commented by mondodotto@gmail.com last updated on 11/Mar/18 $$\mathrm{please}\:\mathrm{help} \\ $$ Answered by Rasheed.Sindhi last updated on…
Question Number 162673 by mkam last updated on 31/Dec/21 Answered by mr W last updated on 31/Dec/21 $$\left({i}\right)×\mathrm{2}−\left({ii}\right): \\ $$$$−\mathrm{3}{x}=\mathrm{3}{t}+\mathrm{2}\:\Rightarrow{x}=−{t}−\frac{\mathrm{2}}{\mathrm{3}} \\ $$$$−\mathrm{1}+{t}+\frac{\mathrm{2}}{\mathrm{3}}+\frac{{dy}}{{dt}}=\mathrm{2}{t}+\mathrm{1} \\ $$$$\frac{{dy}}{{dt}}={t}+\frac{\mathrm{4}}{\mathrm{3}} \\…
Question Number 97142 by mhmd last updated on 06/Jun/20 $${prove}\:{that}\:{cos}\left({mx}\right){cos}\left({ny}\right)=\frac{{cos}\left({mx}+{ny}\right)+{cos}\left({mx}−{ny}\right)}{\mathrm{2}}\:\:? \\ $$$${help}\:{me}\:{sir}\:? \\ $$ Commented by mr W last updated on 06/Jun/20 $${just}\:{apply}\:{the}\:{formulae}\:{for} \\ $$$$\mathrm{cos}\:\left({a}+{b}\right)\:{and}\:\mathrm{cos}\:\left({a}−{b}\right).…
Question Number 97139 by mhmd last updated on 06/Jun/20 $${prove}\:{that}\:{sinh}\mathrm{3}{x}=\mathrm{3}{sinhx}+\mathrm{4}{sinh}^{\mathrm{3}} {x}\:? \\ $$$${help}\:{me}\:{sir}\:? \\ $$ Commented by mhmd last updated on 06/Jun/20 $${are}\:{you}\:{can}\:{help}\:{me}\:? \\ $$…
Question Number 97125 by PRITHWISH SEN 2 last updated on 06/Jun/20 $$\int\left\{\mathrm{xtanx}+\mathrm{ln}\mid\mathrm{cos}\:\mathrm{x}\mid\right\}\:\mathrm{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 31573 by mondodotto@gmail.com last updated on 10/Mar/18 Commented by MJS last updated on 10/Mar/18 $$\mathrm{messed}\:\mathrm{around}\:\mathrm{a}\:\mathrm{bit} \\ $$$$\mathrm{1}^{\mathrm{st}} \:\mathrm{thought}\:{y}={e}^{−{x}^{\mathrm{2}} } ,\:\mathrm{checking} \\ $$$$\mathrm{leads}\:\mathrm{to}\:−{x}×{e}^{−{x}^{\mathrm{2}} }…
Question Number 97108 by M±th+et+s last updated on 06/Jun/20 $$\left.\mathrm{1}\right){find}\:\frac{{dy}}{{dx}} \\ $$$${y}=\left({sin}\left({x}\right)\right)^{{cos}^{−\mathrm{1}} \left({x}\right)} \\ $$$$ \\ $$$$\left.\mathrm{2}\right)\underset{{x}\rightarrow\infty} {{lim}x}^{\frac{\mathrm{1}}{{x}}} \\ $$ Commented by M±th+et+s last updated…
Question Number 31572 by mondodotto@gmail.com last updated on 10/Mar/18 Answered by MJS last updated on 10/Mar/18 $${f}\left({x}\right)−{g}\left({x}\right)=\mathrm{3}{x}^{\mathrm{3}} −\mathrm{8}{x} \\ $$$$\mathrm{for}\:\mathrm{the}\:\mathrm{area}\:{A}\:\mathrm{we}\:\mathrm{need}\:\mathrm{the}\:\mathrm{zeros} \\ $$$$\mathrm{3}{x}^{\mathrm{3}} −\mathrm{8}{x}=\mathrm{0} \\ $$$${x}_{\mathrm{1}}…
Question Number 31571 by mondodotto@gmail.com last updated on 10/Mar/18 Answered by Joel578 last updated on 10/Mar/18 $$\frac{\mathrm{1}}{\left(\mathrm{1}\:+\:\mathrm{tan}^{\mathrm{2}} \:\theta\right)^{\mathrm{2}} }\:+\:\frac{\mathrm{1}}{\mathrm{cosec}^{\mathrm{4}} \:\theta} \\ $$$$=\:\frac{\mathrm{1}}{\mathrm{sec}^{\mathrm{4}} \:\theta}\:+\:\frac{\mathrm{1}}{\mathrm{cosec}^{\mathrm{4}} \:\theta} \\…